GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Feb 2019, 13:18

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
• ### Free GMAT Prep Hour

February 20, 2019

February 20, 2019

08:00 PM EST

09:00 PM EST

Strategies and techniques for approaching featured GMAT topics. Wednesday, February 20th at 8 PM EST

February 21, 2019

February 21, 2019

10:00 PM PST

11:00 PM PST

Kick off your 2019 GMAT prep with a free 7-day boot camp that includes free online lessons, webinars, and a full GMAT course access. Limited for the first 99 registrants! Feb. 21st until the 27th.

# How many 3 digits even numbers are possible using the digits 0, 3, 1

Author Message
TAGS:

### Hide Tags

e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

Updated on: 13 Aug 2018, 06:45
2
2
00:00

Difficulty:

35% (medium)

Question Stats:

61% (01:10) correct 39% (01:41) wrong based on 157 sessions

### HideShow timer Statistics

Learn when to “Add” and “Multiply” in Permutation & Combination questions- Exercise Question #4

How many 3 digits even numbers are possible using the digits $$0,3,1,6,7,9$$ if repetition of digits is allowed?

Options:
A) 20
B) 30
C) 40
D) 60
E) 120

Learn to use the Keyword Approach in Solving PnC question from the following article:

Learn when to “Add” and “Multiply” in Permutation & Combination questions

_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Originally posted by EgmatQuantExpert on 04 Apr 2018, 05:42.
Last edited by EgmatQuantExpert on 13 Aug 2018, 06:45, edited 8 times in total.
Manager
Joined: 05 Feb 2016
Posts: 157
Location: India
Concentration: General Management, Marketing
WE: Information Technology (Computer Software)
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

04 Apr 2018, 06:27
1
EgmatQuantExpert wrote:

Question:

How many 3 digits even numbers are possible using the digits $$0,3,1,6,7,9$$?

Options:
A) 20
B) 30
C) 40
D) 60
E) 120

let abc is three digit number:

a can have 3,1,6,7,9 values so 5 ways.
b can have 0,3,1,6,7,9 values so 6 ways.
c can have 0,6values so 2 ways.
total ways =5*6*2=60 ways

D
e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

Updated on: 20 Apr 2018, 21:01
1

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Originally posted by EgmatQuantExpert on 08 Apr 2018, 20:42.
Last edited by EgmatQuantExpert on 20 Apr 2018, 21:01, edited 1 time in total.
Intern
Joined: 30 Sep 2017
Posts: 2
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

13 Apr 2018, 06:20
Hi,
Is it implicit that if were not told the phrase "pick numbers without repetition", We would assume that we can repeat the numbers for units, tents and hundreds digits?
e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

17 Apr 2018, 06:44
rodrigo.mendozay wrote:
Hi,
Is it implicit that if were not told the phrase "pick numbers without repetition", We would assume that we can repeat the numbers for units, tents and hundreds digits?

Hey rodrigo.mendozay,

Thanks for pointing this in question.

We have updated the question
_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Intern
Joined: 12 Apr 2018
Posts: 3
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

17 Apr 2018, 10:31
1
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hi,

As per my understanding

Case 1
0 at unit digit 5*4 ways
6 at unit digit 4*4 ways

Total 36

Can you tell me where I went wrong??

Sent from my ONEPLUS A5010 using GMAT Club Forum mobile app
Intern
Joined: 06 Dec 2017
Posts: 7
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 06:39
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hi. I am a bit confused. Let's say if 0 or 6 is picked for the unit digit, there should be left with only 5 options on the tens digit and 4 options for the hundreds digit right? since all digits have to be different.
Senior Manager
Joined: 29 Dec 2017
Posts: 385
Location: United States
Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33
GMAT 2: 690 Q47 V37
GMAT 3: 710 Q50 V37
GPA: 3.25
WE: Marketing (Telecommunications)
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 07:39
1
EgmatQuantExpert wrote:
rodrigo.mendozay wrote:
Hi,
Is it implicit that if were not told the phrase "pick numbers without repetition", We would assume that we can repeat the numbers for units, tents and hundreds digits?

Hey rodrigo.mendozay,

Thanks for pointing this in question.

We have updated the question

Hi,
If you set "without repetition" so the answer will change to 36 ways. The guy above is right.
Manager
Joined: 22 Jun 2017
Posts: 71
Location: Brazil
GMAT 1: 600 Q48 V25
GPA: 3.5
WE: Engineering (Energy and Utilities)
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 08:01
1
Slomo5000 wrote:
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hi,

As per my understanding

Case 1
0 at unit digit 5*4 ways
6 at unit digit 4*4 ways

Total 36

Can you tell me where I went wrong??

Sent from my ONEPLUS A5010 using GMAT Club Forum mobile app

I agree with Slomo5000 .

I think the answer is 36.
Manager
Joined: 02 Aug 2015
Posts: 150
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 09:28
1
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hello Payal,

If the unit's place includes '0', the tenth place cannot include '0' as the question states the numbers cannot repeat. You've considered '0' for both tenth place and ones place in your solution.

I used the below approach and I'm getting a different answer, please let me know where I'm going wrong.

Last digit is 0
Tens place and hundredth place - 5x4 =20 ways.

Last digit is 6.
Tens placeand hundredth place - 4x4 = 16 ways.

So a total of 36 ways.

Cheers!
Intern
Joined: 03 Aug 2016
Posts: 40
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 09:45
For a 3 digit number to be even, it has to be either 0 or 6.

Constraint: all digits have to be different

Case 1: With 0 as the last digit.

Units digit = 0 --> 1 way
Tens digit can be 3,1,6,7,9, and NOT 0 --> 5 ways
Hundreds digit cannot be 0 and tens digit --> 4 ways
Total = 1 x 5 x 4 = 20 ways

Case 2: With 6 as the last digit

Units digit = 6 --> 1 way
Tens digit cannot be 6 --> 5 ways
Hundreds digit cannot be units digit, tens digit, and zero --> 3 ways
Total = 1 x 5 x 3 = 15 ways

Total = case 1 + case 2 = 20 + 15 = 35 ways.

Could someone please tell me where I went wrong? Thank you!
_________________

e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 21:06
Slomo5000 wrote:
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hi,

As per my understanding

Case 1
0 at unit digit 5*4 ways
6 at unit digit 4*4 ways

Total 36

Can you tell me where I went wrong??

Sent from my ONEPLUS A5010 using GMAT Club Forum mobile app

Hey Slomo,

There is nothing wrong with your method. There was just some confusion while updating the question stem. Apologies for that.

If repetition is not allowed then in that case the total cases will definitely be 36.

When 0 is at the units place then the tens and hundreds digits can be filled in 5 x 4 ways.

However, when 6 is at the units place, then the hundreds place can be filled in only 4 ways and even the tens place can be filled in 4 ways.

Thus, total cases possible will be 20 + 16 = 36 ways.

Regards,
Saquib
Quant Expert
e-GMAT
_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 21:16
1
Wildflower wrote:
For a 3 digit number to be even, it has to be either 0 or 6.

Constraint: all digits have to be different

Case 1: With 0 as the last digit.

Units digit = 0 --> 1 way
Tens digit can be 3,1,6,7,9, and NOT 0 --> 5 ways
Hundreds digit cannot be 0 and tens digit --> 4 ways
Total = 1 x 5 x 4 = 20 ways

Case 2: With 6 as the last digit

Units digit = 6 --> 1 way
Tens digit cannot be 6 --> 5 ways
Hundreds digit cannot be units digit, tens digit, and zero --> 3 ways
Total = 1 x 5 x 3 = 15 ways

Total = case 1 + case 2 = 20 + 15 = 35 ways.

Could someone please tell me where I went wrong? Thank you!

Hey Wildflower,

I have highlighted the areas where you made a mistake.

Whenever you have a situation in which 0 is involved, try to fill that space first, where the confusion will happen (hundreds place in this case)!

When 6 has been placed in the units digit, we are left with the following options for tens and hundreds place: 0, 1, 3, 7 and 9

Now, if you fill the tens place first and say that there are five ways to fill it, then you are basically saying that I can put 0 in the hundreds place, I can put 1 also, I can put 3 or 7 or 9 also in the hundreds place.

Now think a bit. If you put 6 in the units place and say 0 in the tens place, how many digits are available for the hundreds place? We have 3,7,9 and 1 available right?

However, you have written that the hundreds place can be filled in only 3 ways, which is incorrect!

So, I hope you understand what cases you are missing out?

You are missing those cases, when 0 is put on the tens place.

Thus, to avoid such confusion, what we do is that we fill the hundreds place first and say that the hundreds place can be filled in 4 ways (1,3,7 or 9), this ensure that all eligible digits will get a chance to be placed at the hundreds place.

Now with are left with 0 and the remaining 3 digits (since one of the digits is already placed at the hundreds place), thus total available cases for the tens place will also be 4 and thus the correct answer will be 4 x 4 = 16.

Let me know if you still have any doubts.

Regards,
Saquib
Quant Expert
e-GMAT
_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

e-GMAT Representative
Joined: 04 Jan 2015
Posts: 2577
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 21:18
antarcticsugar wrote:
EgmatQuantExpert wrote:

Solution

Given:
• We are given 6 digits: 0,1,3,6,7, and 9.
To find:
• The number of all the 3 digits even numbers from: 0,1,3,6,7, and 9.
Approach and Working:

Total ways to make the 3-digit number= Ways to fill the hundreds digit AND Ways to fill the tens digit AND ways to fill the units digit

Ways to fill the units place: 2 ways
• When O is the units digit, OR
• When 6 is the units digit

Ways to fill the tens place: 6 ways
• Tens place can have every digit from0,1,3,6,7, and 9.

Ways to fill the hundreds place: 5 ways

The important point to note here is that 0 cannot be the hundreds digit.
• Hence, hundreds place can have only any digit from 1,3,6,7, and 9.
Hence, total ways= 5*6*2=60

Hence, the correct answer is option D.

Hi. I am a bit confused. Let's say if 0 or 6 is picked for the unit digit, there should be left with only 5 options on the tens digit and 4 options for the hundreds digit right? since all digits have to be different.

Hey,

I have updated the question. Please check.

If repetition is allowed then 60 cases are possible. If it is not allowed then 36 cases are possible.

Regards,
Saquib
Quant Expert
e-GMAT
_________________

| '4 out of Top 5' Instructors on gmatclub | 70 point improvement guarantee | www.e-gmat.com

Intern
Joined: 03 Aug 2016
Posts: 40
Re: How many 3 digits even numbers are possible using the digits 0, 3, 1  [#permalink]

### Show Tags

20 Apr 2018, 22:34
1
EgmatQuantExpert wrote:
Wildflower wrote:
For a 3 digit number to be even, it has to be either 0 or 6.

Constraint: all digits have to be different

Case 1: With 0 as the last digit.

Units digit = 0 --> 1 way
Tens digit can be 3,1,6,7,9, and NOT 0 --> 5 ways
Hundreds digit cannot be 0 and tens digit --> 4 ways
Total = 1 x 5 x 4 = 20 ways

Case 2: With 6 as the last digit

Units digit = 6 --> 1 way
Tens digit cannot be 6 --> 5 ways
Hundreds digit cannot be units digit, tens digit, and zero --> 3 ways
Total = 1 x 5 x 3 = 15 ways

Total = case 1 + case 2 = 20 + 15 = 35 ways.

Could someone please tell me where I went wrong? Thank you!

Hey Wildflower,

I have highlighted the areas where you made a mistake.

Whenever you have a situation in which 0 is involved, try to fill that space first, where the confusion will happen (hundreds place in this case)!

When 6 has been placed in the units digit, we are left with the following options for tens and hundreds place: 0, 1, 3, 7 and 9

Now, if you fill the tens place first and say that there are five ways to fill it, then you are basically saying that I can put 0 in the hundreds place, I can put 1 also, I can put 3 or 7 or 9 also in the hundreds place.

Now think a bit. If you put 6 in the units place and say 0 in the tens place, how many digits are available for the hundreds place? We have 3,7,9 and 1 available right?

However, you have written that the hundreds place can be filled in only 3 ways, which is incorrect!

So, I hope you understand what cases you are missing out?

You are missing those cases, when 0 is put on the tens place.

Thus, to avoid such confusion, what we do is that we fill the hundreds place first and say that the hundreds place can be filled in 4 ways (1,3,7 or 9), this ensure that all eligible digits will get a chance to be placed at the hundreds place.

Now with are left with 0 and the remaining 3 digits (since one of the digits is already placed at the hundreds place), thus total available cases for the tens place will also be 4 and thus the correct answer will be 4 x 4 = 16.

Let me know if you still have any doubts.

Regards,
Saquib
Quant Expert
e-GMAT

I see where I went wrong. Thank you, EgmatQuantExpert for pointing it out
_________________

Re: How many 3 digits even numbers are possible using the digits 0, 3, 1   [#permalink] 20 Apr 2018, 22:34
Display posts from previous: Sort by