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Joined: 12 Jan 2019
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How many nails did Rudy buy if he purchased them at a price of $0.25
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Updated on: 12 Jan 2019, 03:25
Question Stats:
88% (02:25) correct 12% (02:43) wrong based on 33 sessions
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How many nails did Rudy buy if he purchased them at a price of $0.25 per four nails, sold them at $0.22 per three nails, and made a profit of $2.60? A. 300 B. 240 C. 180 D. 160 E. 120
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Originally posted by Nums99 on 12 Jan 2019, 01:42.
Last edited by Bunuel on 12 Jan 2019, 03:25, edited 1 time in total.
Renamed the topic, edited the question, moved to PS and added the OA.



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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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12 Jan 2019, 02:12
Hi there,
Here's the solution.
Let the number of nails Rudy purchased be x.
Rudy purchased nails at a price of $0.25 per four nails. So, Cost Price of 4 nails = $0.25 Cost Price of 1 nail = = $0.25/4 Cost price of x nails = ($0.25/4)x
Also given that Rudy sold nails at $0.22 per three nails. So, Selling Price of 3 nails = $0.22 Selling Price of 1 nail = = $0.22/3 Selling price of x nails = ($0.22/3)x
Also, Rudy made a profit of $2.60. Profit = Selling Price  Cost Price $2.60 = ($0.22/3)x  ($0.25/4)x = x(0.88  0.75)/12 $2.60 = x(0.13)/12 x = 240 Hence, the the number of nails Rudy purchased is 240.
Therefore, the Correct Answer is Option B. 240
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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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16 Jan 2019, 02:57
Nums99 wrote: How many nails did Rudy buy if he purchased them at a price of $0.25 per four nails, sold them at $0.22 per three nails, and made a profit of $2.60?
A. 300 B. 240 C. 180 D. 160 E. 120 Profit = Sales  Cost \(2.6 = \frac{0.22}{3}n  \frac{0.25}{4}n = \frac{0.88n}{12}  \frac{0.75n}{12}\) \(\frac{13}{5} = \frac{0.13n}{12} = \frac{13n}{1200}\) \(n = \frac{13*1200}{13*5} = 240\) B
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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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16 Jan 2019, 08:15
As we are dealing with two numbers 3 & 4 .... lets take the LCM of them i.e.,12 . Cost price for 12 nails = $0.25*12/4=$0.75 & Selling price for 12 nails = $0.22*12/3=$0.88 Profit made per 12 nails = $0.88  $0.75 = $0.13 So total '12 units' sold = $2.60/$0.13 =20 Total nails sold = 20*12 = 240 .... Thus Ans would be option B.
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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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25 Feb 2019, 09:26
Nums99 wrote: How many nails did Rudy buy if he purchased them at a price of $0.25 per four nails, sold them at $0.22 per three nails, and made a profit of $2.60?
A. 300 B. 240 C. 180 D. 160 E. 120 LCM approach is good in such questions: Rudy purchased nails at a price of $0.25 per four nails, or $0.75 per 12 nails sold them at $0.22 per three nails, or $0.88 per 12 nails and made a profit of $2.60 (total) or $(0.880.75) = $ 0.13 per 12 nails (2.60 * 12)/0.13 = 240 nails (Ans)
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How many nails did Rudy buy if he purchased them at a price of $0.25
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28 Feb 2019, 11:09
Nums99 wrote: How many nails did Rudy buy if he purchased them at a price of $0.25 per four nails, sold them at $0.22 per three nails, and made a profit of $2.60?
A. 300 B. 240 C. 180 D. 160 E. 120 Cost Price of \(4\) nails \(= $ 0.25\) Cost Price of \(3\) nails \(= \frac{0.25*3}{4} = $ 0.1875\) Selling Price of \(3\) nails \(= $0.22\) Profit on \(3\) nails \(= 0.22  0.1875 = $ 0.0325\) Let \("x"\) be total number of nails to make profit of \($ 2.60\). \(\frac{0.0325}{3} = \frac{2.60}{x}\) \(0.0325*x =3*2.60\) \(x = \frac{3*2.60}{0.0325} = 240\) Answer B



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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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02 Mar 2019, 10:08
Nums99 wrote: How many nails did Rudy buy if he purchased them at a price of $0.25 per four nails, sold them at $0.22 per three nails, and made a profit of $2.60?
A. 300 B. 240 C. 180 D. 160 E. 120 We can let n = the number of nails and create the equation: (0.22/3)n  (0.25/4)n = 2.6 Multiplying by 12, we have: 0.22 x 4n  0.25 x 3n = 31.2 0.88n  0.75n = 31.2 0.13n = 31.2 n = 240 Answer: B
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Re: How many nails did Rudy buy if he purchased them at a price of $0.25
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