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11 Nov 2019, 04:05
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If \(1,485= a^x b^y c^z\), then \(abc=\) ?
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Are You Up For the Challenge: 700 Level Questions
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Are You Up For the Challenge: 700 Level Questions
11 Nov 2019, 08:41
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If \(1,485= a^x b^y c^z\), then \(abc=\) ?
\(1485=3^3*5*11\)
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Combined..
We know that c=11, but a and b could be anything as it is NOT given that they are integers..
\(1485=a^3*b*11...a^3b=135=3*3*3*5.\).
\(a=3\), and \(b=5...abc=3*5*11\).
\(a=135^{\frac{1}{3}}\) and \(b=1.....abc = 135^{\frac{1}{3}}*1*11\)
Insuff
E
\(1485=3^3*5*11\)
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Combined..
We know that c=11, but a and b could be anything as it is NOT given that they are integers..
\(1485=a^3*b*11...a^3b=135=3*3*3*5.\).
\(a=3\), and \(b=5...abc=3*5*11\).
\(a=135^{\frac{1}{3}}\) and \(b=1.....abc = 135^{\frac{1}{3}}*1*11\)
Insuff
E
ShankSouljaBoi
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Schools: Rotman '23 (D) IIMA PGPX'22 (D) Desautels '23 (D) Schulich Sept '23 (D) WBS (D) IIML IPMX'25 (A)
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15 Nov 2019, 06:53
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Very tricky. It's not given a b and c are prime , neither it's given that they are integers . Got it wrong :D
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