Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
11 Nov 2019, 04:05
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
37% (02:05) correct
63%
(01:59)
wrong
based on 276
sessions
History
Date
Time
Result
Not Attempted Yet
If \(1,485= a^x b^y c^z\), then \(abc=\) ?
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Are You Up For the Challenge: 700 Level Questions
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Are You Up For the Challenge: 700 Level Questions
11 Nov 2019, 08:41
Kudos
Bookmarks
If \(1,485= a^x b^y c^z\), then \(abc=\) ?
\(1485=3^3*5*11\)
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Combined..
We know that c=11, but a and b could be anything as it is NOT given that they are integers..
\(1485=a^3*b*11...a^3b=135=3*3*3*5.\).
\(a=3\), and \(b=5...abc=3*5*11\).
\(a=135^{\frac{1}{3}}\) and \(b=1.....abc = 135^{\frac{1}{3}}*1*11\)
Insuff
E
\(1485=3^3*5*11\)
(1) \(1485 = a^3bc\)
(2) \(c = 11\)
Combined..
We know that c=11, but a and b could be anything as it is NOT given that they are integers..
\(1485=a^3*b*11...a^3b=135=3*3*3*5.\).
\(a=3\), and \(b=5...abc=3*5*11\).
\(a=135^{\frac{1}{3}}\) and \(b=1.....abc = 135^{\frac{1}{3}}*1*11\)
Insuff
E
ShankSouljaBoi
Joined: 21 Jun 2017
Last visit: 28 Mar 2026
Posts: 600
Own Kudos:
Given Kudos: 4,090
Location: India
Concentration: Finance, Economics
Schools: Rotman '23 (D) IIMA PGPX'22 (D) Desautels '23 (D) Schulich Sept '23 (D) WBS (D) IIML IPMX'25 (A)
GMAT 1: 660 Q49 V31
GMAT 2: 620 Q47 V30
GMAT 3: 650 Q48 V31
GPA: 3.1
WE:Corporate Finance (Non-Profit and Government)
Products:
Schools: Rotman '23 (D) IIMA PGPX'22 (D) Desautels '23 (D) Schulich Sept '23 (D) WBS (D) IIML IPMX'25 (A)
GMAT 3: 650 Q48 V31
Posts: 600
Kudos:
611
15 Nov 2019, 06:53
Kudos
Bookmarks
Very tricky. It's not given a b and c are prime , neither it's given that they are integers . Got it wrong :D
Posted from my mobile device
Posted from my mobile device
