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If 33 – x = 7, what is the product of all the possible va [#permalink]
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28 Mar 2013, 21:09
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If 33 – x = 7, what is the product of all the possible values of x? A. 1/9 B. 1/3 C. 2/3 D. 16/9 E. 32/9
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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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28 Mar 2013, 21:40
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nave81 wrote: If 33 – x = 7, what is the product of all the possible values of x?
A. 1/9 B. 1/3 C. 2/3 D. 16/9 E. 32/9 33x = 7 can be rewritten as: \(3x = \frac{7}{3}\) So \(\frac{9}{3}  x = \frac{7}{3}\) x has two possible solutions \(\frac{2}{3}\) and \(\frac{16}{3}\) that satisfy the equation \(\frac{2}{3}*\frac{16}{3} = \frac{32}{9}\) Answer is E



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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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\(33  x = 7\) case \(3x>0\) \(3(3x)=7\) \(93x=7, x=\frac{2}{3}\) case \(3x<0\) \(3(3+x)=7\) \(9+3x=7, x= 16/3\) \(\frac{2}{3}*\frac{16}{3}=\frac{32}{9}\) E
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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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01 Apr 2013, 08:00
nave81 wrote: If 33 – x = 7, what is the product of all the possible values of x?
A. 1/9 B. 1/3 C. 2/3 D. 16/9 E. 32/9 33 – x = 7 So, 3 – x = 7/3 or (3x) = +7/3 or 7/3 Solving we get x = 2/3 or 16/3 product = \(2/3 * 16/3 = 32/9\)



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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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10 Jul 2013, 10:38
If 33 – x = 7, what is the product of all the possible values of x?
x≥3, x<3
x≥3: 33 – x = 7 3 (3x) = 7 3 (3+x) = 7 9 + 3x = 7 3x = 16 x=16/3 Valid
x<3 3(3x) = 7 93x = 7 3x=2 x=2/3
(16/3)*(2/3) = 32/9
(E)



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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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23 Jan 2015, 01:33
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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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09 Mar 2016, 05:40
I don't agree with E. 16/3, when substituted in the original equation doesn't satisfy it. you would get 9/3 = 7/3 which is not legit. So we should discard 16/3 as a solution of the equation. That leaves us with 2/3 which is option C
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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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If 33 – x = 7, what is the product of all the possible va [#permalink]
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Re: If 33 – x = 7, what is the product of all the possible va [#permalink]
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13 Mar 2017, 01:19
33x = 7 can be rewritten as: 3−x=7/3 so we have 1. 3x =7/3 x=2/3
2. 3x=7/3 x=16/3
so product will be 32/9




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