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Manager
Joined: 25 Dec 2018
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Location: India
GPA: 2.86

If a and b are integers with each being greater than 1, is a × b > 20?
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29 Dec 2018, 20:41
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49% (01:13) correct 51% (01:12) wrong based on 51 sessions
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If a and b are integers with each being greater than 1, is a × b > 20? (1) a + b = 9 (2) (a − 4)^2 + (b − 5)^2 = 0
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Director
Joined: 18 Jul 2018
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Concentration: Finance, Marketing
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Re: If a and b are integers with each being greater than 1, is a × b > 20?
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29 Dec 2018, 20:56
From statement 1: a+b = 9 As a and b are greater than 1. then a and b can take values (6,3) or (4,5) or (7,2) 6*3 = 18 < 20. 7*2 = 14 < 20 4*5 = 20 and 20 is not greater than 20. Hence, Insufficient. From statement 2: \((a − 4)^2 + (b − 5)^2 = 0\) Here a and b can only take values 4 and 5. and 20 is not greater than 20. Hence, a*b can never be greater than 20. Sufficient. B is the answer. akurathi12, is the OA correct?
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Joined: 17 Aug 2018
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Re: If a and b are integers with each being greater than 1, is a × b > 20?
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29 Dec 2018, 21:10
I think OA is wrong. The correct answer is B.
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Manager
Joined: 01 May 2017
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Location: India

Re: If a and b are integers with each being greater than 1, is a × b > 20?
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30 Dec 2018, 03:08
(1) a + b = 9
Combinations possible are (2,7), (3,6) and (4,5) 2*7 < 20 3*6 < 20 4*5 = 20
Is a*b > 20, No it is less than or equal to 20 So, clearly I can say a*b not greater than 20 i.e.,\(a*b <= 20\) Sufficient
(2) (a − 4)^2 + (b − 5)^2 = 0 for some of squares i.e., positive values to be zero, they should be zero a = 4 and b = 5 is the only possibility a*b = 20 which is not greater than Sufficient
So, option D is correct



Manager
Joined: 25 Dec 2018
Posts: 87
Location: India
GPA: 2.86

Re: If a and b are integers with each being greater than 1, is a × b > 20?
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30 Dec 2018, 05:16
Afc0892 wrote: From statement 1: a+b = 9 As a and b are greater than 1. then a and b can take values (6,3) or (4,5) or (7,2) 6*3 = 18 < 20. 7*2 = 14 < 20 4*5 = 20 and 20 is not greater than 20. Hence, Insufficient. From statement 2: \((a − 4)^2 + (b − 5)^2 = 0\) Here a and b can only take values 4 and 5. and 20 is not greater than 20. Hence, a*b can never be greater than 20. Sufficient. B is the answer. akurathi12, is the OA correct? I am in a confusion with OA, that is the reason I have posted.



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Re: If a and b are integers with each being greater than 1, is a × b > 20?
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30 Dec 2018, 05:18
Dare Devil wrote: (1) a + b = 9
Combinations possible are (2,7), (3,6) and (4,5) 2*7 < 20 3*6 < 20 4*5 = 20
Is a*b > 20, No it is less than or equal to 20 So, clearly I can say a*b not greater than 20 i.e.,\(a*b <= 20\) Sufficient
(2) (a − 4)^2 + (b − 5)^2 = 0 for some of squares i.e., positive values to be zero, they should be zero a = 4 and b = 5 is the only possibility a*b = 20 which is not greater than Sufficient
So, option D is correct Thank you for the statement 1 explanation.



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Re: If a and b are integers with each being greater than 1, is a × b > 20?
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30 Dec 2018, 08:42
akurathi12 wrote: Dare Devil wrote: (1) a + b = 9
Combinations possible are (2,7), (3,6) and (4,5) 2*7 < 20 3*6 < 20 4*5 = 20
Is a*b > 20, No it is less than or equal to 20 So, clearly I can say a*b not greater than 20 i.e.,\(a*b <= 20\) Sufficient
(2) (a − 4)^2 + (b − 5)^2 = 0 for some of squares i.e., positive values to be zero, they should be zero a = 4 and b = 5 is the only possibility a*b = 20 which is not greater than Sufficient
So, option D is correct Thank you for the statement 1 explanation. My Pleasure... We are here to help out each other...



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Re: If a and b are integers with each being greater than 1, is a × b > 20?
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08 Jan 2019, 11:10
akurathi12 wrote: If a and b are integers with each being greater than 1, is a × b > 20?
(1) a + b = 9
(2) (a − 4)^2 + (b − 5)^2 = 0 Given a and b are integers with each being greater than 1 Statement 1 a + b = 9 2+7, is 14>20, No 3+6, is 18>20, No 4+5, is 20>20, No Consistent, No. Sufficient. Statement 2 \((a − 4)^2 + (b − 5)^2\) = 0 Can only be true when a = 4 and b = 5 is 20>20, No Sufficient. Answer D
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Re: If a and b are integers with each being greater than 1, is a × b > 20? &nbs
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