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If a, b, c, d, e are positive integers such that a<b<c<d<e, then what

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If a, b, c, d, e are positive integers such that a<b<c<d<e, then what  [#permalink]

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New post 29 Sep 2018, 23:21
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If a, b, c, d, e are integers such that a<b<c<d<e, then what is the positive difference between averages of Sets (b, c, d, e) and (a, b, c, d)

1) a, b, c, d, e are consecutive integers
2) a = 5

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If a, b, c, d, e are positive integers such that a<b<c<d<e, then what  [#permalink]

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New post 30 Sep 2018, 02:03
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GMATinsight wrote:
If a, b, c, d, e are integers such that a<b<c<d<e, then what is the positive difference between averages of Sets (b, c, d, e) and (a, b, c, d)

1) a, b, c, d, e are consecutive integers
2) a = 5

Source: http://www.GMATinsight.com


Average of,c, d,e,b= (b+c+d+e)/4
And average of a,b,c,d = (a+b+c+d)/4

Difference = \(\frac{e+d+c+b}{4}+\frac{a+b+c+d}{4}\)=\frac{e-a}{4}
So we require value of e and a
1) a,b,c,d,e are consecutive integers
So e=a+4......e-a=4
Sufficient
2) a=5
Insufficient

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Re: If a, b, c, d, e are positive integers such that a<b<c<d<e, then what  [#permalink]

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New post 31 Jan 2019, 04:38
chetan2u: I think e=a+4 and not a+5.
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Re: If a, b, c, d, e are positive integers such that a<b<c<d<e, then what   [#permalink] 31 Jan 2019, 04:38
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