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niteshwaghray
GMAT 1: 700 Q45 V40
Posts: 59
23 May 2017, 13:25
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
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Question Stats:
68% (02:55) correct
32%
(02:46)
wrong
based on 109
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If a cube of side length 24 units is cut into 512 smaller cubes of equal dimensions, then what is the ratio of the combined surface area of the smaller cubes and the surface area of the original cube?
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
23 May 2017, 14:04
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niteshwaghray
If a cube of side length 24 units is cut into 512 smaller cubes of equal dimensions, then what is the ratio of the combined surface area of the smaller cubes and the surface area of the original cube?
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
512 = 8^3, which means that a side of a large cube will be divided into 8 parts giving the side lengths of smaller cubes as 24/8 = 3.
The combined surface area of the smaller cubes = 512*(6*3^2);
The surface area of the original cube = 6*24^2 (number of faces * area of a face).
\(Ratio = \frac{512*6*3^2}{6*24^2}=\frac{8^3*3^2}{6*8^2*3^2}=8\).
Answer: C.
Shruti0805
24 May 2017, 00:00
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Bunuel
niteshwaghray
If a cube of side length 24 units is cut into 512 smaller cubes of equal dimensions, then what is the ratio of the combined surface area of the smaller cubes and the surface area of the original cube?
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
A. 1:48
B. 3:32
C. 8:1
D. 32:3
E. 48:1
512 = 8^3, which means that a side of a large cube will be divided into 8 parts giving the side lengths of smaller cubes as 24/8 = 3.
The combined surface area of the smaller cubes = 512*(6*3^2);
The surface area of the original cube = 6*24^2 (number of faces * area of a face).
\(Ratio = \frac{512*6*3^2}{6*24^2}=\frac{8^3*3^2}{6*8^2*3^2}=8\).
Answer: C.
Hi Bunuel,
I'm having a little trouble understanding the highlighted part. could you please explain that a bit ?
Thanks in advance.
