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Bunuel
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Bunuel
If a triangle of base 6 has the same area as a circle of radius 6, what is the altitude of the triangle?

A. \(6\pi\)

B. \(8\pi\)

C. \(10\pi\)

D. \(12\pi\)

E. \(14\pi\)

As the required calculation is straightforward, we'll just do it.
This is a Precise approach.

Writing what we're told as an equation, b*h/2 = pi*r^2.
That is, 6h/2 = 36pi so h = 12pi.

(D) is our answer.
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Area of triangle=1/2*base*Altitude= 1/2*6*Altitude =3*Altitude
Area of circle= π*r*r = π*6*6=36π

Given area of triangle= area of circle,
=>3*Altitude=36π
Altitude= 12π
Hence D is the answer
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Bunuel
If a triangle of base 6 has the same area as a circle of radius 6, what is the altitude of the triangle?

A. \(6\pi\)

B. \(8\pi\)

C. \(10\pi\)

D. \(12\pi\)

E. \(14\pi\)

We can create the equation, in which h = height = altitude of the triangle. We equate the area of the triangle with base 6 to the area of the circle with radius 6:

6 x h x 1/2 = π x 6^2

3h = 36π

h = 12π

Answer: D
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If a triangle of base 6 has the same area as a circle of radius 6, what is the altitude of the triangle?

A. \(6\pi\)

B. \(8\pi\)

C. \(10\pi\)

D. \(12\pi\)

E. \(14\pi\)

It can be done like: 0.5*6*h = pi*6^2, that gives: h = 12pi
Answer: D
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