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12 Mar 2016, 06:37
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Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (02:36) correct
30%
(02:22)
wrong
based on 135
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
ABCD.jpg [ 5.87 KiB | Viewed 7002 times ]
A. 45o
B. 50o
C. 60o
D. 75o
E. 80o
* A solution will be posted in two days.
12 Mar 2016, 09:53
Kudos
Bookmarks
MathRevolution
Hi,
since it seems to be a complicated pics, let me label and draw again. pl see att figure
let each side of square be x, so each side of equilateral side will also be x..
1) lets see the triangle ADF
angle D= 90+60=150
AD=DF=x so isosceles triangle..
angle DAF and Angle DFA= (180-150)/2=15
2) similarily in triangle CDE
angle DEC= angle DCE=15..
3) lets see the polygon in center which has D and G as opposite vertices...
angle D=90..
angle on the other two vertices= 180-90-15=75..
so all angles in this polygon=90+75+75+G=240+G=360..
so G= 120.
we are looking for angle ?...
G + ?=180..
120+?=180
?=60
ans C
Attachments
IMG_5574.JPG [ 1.77 MiB | Viewed 8223 times ]
14 Mar 2016, 18:04
Kudos
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If ABCD is square and both AED and CDF are equilateral triangles, what is the angle FGC?
A. 45o
B. 50o
C. 60o
D. 75o
E. 80o
-> Angle ADC=90 degrees, angle DEC=angle DCE=angle DFA=angle DAF=15 degrees. Then, angle DCF=60 degrees and angle GFC=45 degrees, which makes angle G=60 degrees. Therefore, the answer is C.
A. 45o
B. 50o
C. 60o
D. 75o
E. 80o
-> Angle ADC=90 degrees, angle DEC=angle DCE=angle DFA=angle DAF=15 degrees. Then, angle DCF=60 degrees and angle GFC=45 degrees, which makes angle G=60 degrees. Therefore, the answer is C.
