adkikani
chetan2u niks18 pushpitkc pikolo2510How about below analysis of option A?
Quote:
If k is a positive integer and m is the product of the first 40 positive integers, what is the value of k ?
\(k\geq{0}\)
m = 40!
Quote:
(1) 10^k is a factor of m.
So m also contains 2*5 ie 10 divisible by 10^1
and m also contains 25*4 which is divisible by 10^2
So k can be 1 or 2.
I could not understand above approach used for examinating statement 1
Hi
adkikaniThe analysis of statement 1 as already explained by chetan2u is as follows
There is a formula for finding the highest power of a prime number in a factorial
If p is a prime number, then the highest power of p in a factorial n is {\(\frac{n}{p}\)} + {\(\frac{n}{p^2}\)} + {\(\frac{n}{p^3}\)}.....
where {\(\frac{a}{b}\)} is the quotient when integer b divides another integer a
Now coming to the problem at hand. Since p is 10, which can be prime-factorized as 2*5, it is
enough if we are able to find the highest power of 5(since it is the biggest prime number). n = 40
Therefore, the highest power of p(10) is nothing but the highest power of 5.
Substituting values in the formula \({\frac{40}{5^1}} + {\frac{40}{5^2}} = {\frac{40}{5}} + {\frac{40}{25}} = 8 + 1 = 9\)
This means that the 10^9 will divide 40!. So even the smaller powers of 10 will divide 40!
Hope this clears your confusion!