Bunuel
If n is an integer, is (0.1)^n greater than (10)^n?
(1) n > −10
(2) n < 10
Kudos for a correct solution.Here's another approach:
Target question: Is (0.1)^n > (10)^n?This is a good candidate for
rephrasing the target question. Since (0.1)^n is always POSITIVE, we can safely divide both sides of the inequality by (0.1)^n to get:
1 > [(10)^n]/[(0.1)^n]There's a nice rule that says (a^n)/(b^n) = (a/b)^n
When we apply this rule to the right side of the inequality, we get:
1 > (10/0.1)^nSimplify to get:
Is 1 > 100^n?Notice that, when n = 0, then 100^n = 100^0 = 1
So, when n > 0, then 100^n > 1, and when
n < 0, then 100^n < 1So, we can REPHRASE the target question as....
REPHRASED target question: Is n < 0? Statement 1: n > -10 There are several values of n that satisfy statement 1. Here are two:
Case a: n = -9, in which case
n < 0Case b: n = 2, in which case
n > 0Since we cannot answer the
REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: n < 10 There are several values of n that satisfy statement 1. Here are two:
Case a: n = -9, in which case
n < 0Case b: n = 2, in which case
n > 0Since we cannot answer the
REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined IMPORTANT: Notice that I was able to use the
same counter-examples to show that each statement ALONE is not sufficient. So, the same counter-examples will satisfy the two statements COMBINED.
Since we cannot answer the
REPHRASED target question with certainty, the combined statements are NOT SUFFICIENT
Answer:
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