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If n is an integer, the greatest possible value of the

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If n is an integer, the greatest possible value of the  [#permalink]

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New post 05 Jan 2011, 07:44
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If n is an integer, the greatest possible value of the expression: 12 - |32 - 7n| is

A. -20
B. 1
C. 8
D. 9
E. 12

I know to answer this correctly I can just plug in numbers. I was wondering is there any tricks to solving it faster.
Thanks.
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Re: Are there any tricks to solving this question  [#permalink]

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New post 05 Jan 2011, 09:00
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PASSINGGMAT wrote:
if n is an integer, the greatest possible value of the expression: 12 - |32 - 7n| is

A) -20
B) 1
C) 8
D) 9
E) 12

I know to answer this correctly I can just plug in numbers. I was wondering is there any tricks to solving it faster.
Thanks.


Algebraic approach:

The greatest possible value of the expression \(12-|32-7n|\) will be for the least value of \(|32-7n|\). Now, the least possible value of an absolute value is 0 --> \(|32-7n|=0\) --> \(n=\frac{32}{7}=4\frac{4}{7}\), but we are told that \(n\) is an integer so the least value of \(|32-7n|\) will be for \(n=5\) (the closest integer value to \(4\frac{4}{7}\)) --> \(n=5\) --> \(12-|32-7n|=12-3=9\).

Answer: D.

Similar question from OG: if-y-is-an-integer-then-the-least-possible-value-of-139867.html
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New post 04 Jul 2013, 00:44
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 04 Jul 2013, 01:35
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Let the greatest possible value be x.

1. For n>4, i.e., when the value within the modulus is negative, the modulus becomes, -(32-7n)
12- (- (32-7n))=x
12+32-7n=x
x=44-7n
so when n>4, x is greatest for n=5 and the value of x is 9.

2. For n<=4 , the modulus is 32-7n
12-(32-7n)=x
So when n<=4, the greatest value of x is 8

So , of the two, x=9 is the greater value.
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 03 Feb 2016, 17:54
PASSINGGMAT wrote:
If n is an integer, the greatest possible value of the expression: 12 - |32 - 7n| is

A. -20
B. 1
C. 8
D. 9
E. 12

I know to answer this correctly I can just plug in numbers. I was wondering is there any tricks to solving it faster.
Thanks.



good one...so...we need to get the greatest possible value..we have an absolute value..thus, it will always be positive.
since n must be an integer, 7n can't be 32. it can be either 28, or 35. in case it's 35, then we have |-3|. in case it is 28, then |4|. since we have a minus sign, we would rather have |-3|, since 12-3=9, but 12-4=8. thus, the max value is 9.
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 06 Jan 2017, 09:56
SravnaTestPrep wrote:
Let the greatest possible value be x.

1. For n>4, i.e., when the value within the modulus is negative, the modulus becomes, -(32-7n)
12- (- (32-7n))=x
12+32-7n=x
x=44-7n
so when n>4, x is greatest for n=5 and the value of x is 9.

2. For n<=4 , the modulus is 32-7n
12-(32-7n)=x
So when n<=4, the greatest value of x is 8

So , of the two, x=9 is the greater value.


x is greatest for n = 5; x is 9 , when n = 6; x is 2
so greatest x =9
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 14 Jun 2017, 00:20
My approach, no difficult algebra needed, but please correct me if i'm wrong. I'm still learning!:

First look at |32 - 7n|.

On the number line you would be at number 32 with 7n to the left en 7n to the right. The question asks for the greatest possible value of 12 - X.
X stands for |32 - 7n|. So you know X must be small in order for the formula to turn out big.

You know n is an integer, and you know X needs to be small, so:
32-7*4=4 (Let's try one more)
32-7*5=-3 (Bingo)

-3 it is. (Absolute value, so 3)

12-3=9. There you go.
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 14 Jun 2017, 01:07
maximum value for the expression
12-mod(x)
to maximise the value of the expression x must be minimum
mod(x)=35-7x
x=4 mod x =4
x=5 mod x =3
x=6 mod x =7

Hence max value of the expression =9
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Re: If n is an integer, the greatest possible value of the  [#permalink]

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New post 30 Aug 2018, 03:28
Let's think of it like this -

n is an integer so 7n must also be an integer. Correct?

Now the question asks for the greatest value, for this the part in the modulus needs to be be the smallest value. (The smaller the number is from 12 the better)

Inside the modulus we have 2 numbers |32-7n|

So, the value of 7n should be as close to the number 32 as possible to get a small value.

What multiples of 7 is the closest to 32? --->>> You guessed it right it is 35. That means n=5, (since 7x5=35)

So now let's get to the simple math -

32-35=-3, Since there is modulus, it will only be 3

Next -> 12-3=9. Which is the greatest value of the expression

Answer D
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Re: If n is an integer, the greatest possible value of the &nbs [#permalink] 30 Aug 2018, 03:28
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