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#1
Q ≠ 1
we P =2 , q=4 ; or p=2 ,q=4 or p=-4 q=2
|P - Q| = 2, 6 insufficient
#2
P > 0
P = 2,4,16 and q = 4,2,1 again insufficient
from 1 &2
|P - Q| = 2
IMO C; sufficient

If P and Q are integers and P^Q = 16, what is the value of |P - Q| ?

(1) Q ≠ 1
(2) P > 0
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Given: P^Q = 16, Need to find |P - Q|

Statement 1:Q ≠ 1
P,Q value can be (-4,2), (2,4) & (4,2).
So it will give 2 values for |P - Q| = 6, 2
Not Sufficient.
Statement 2: P>1
P,Q value can be (16,1), (2,4) & (4,2).
So it will give 2 values for |P - Q| = 15, 2
Not Sufficient.

Combining 1&2,
P,Q value can be (2,4) & (4,2).
So it will give 1 values for |P - Q| = 2
Sufficient.

IMO-C
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Solution


Step 1: Analyse Question Stem


    • \(P\) and \(Q\) are integers.
      o \(P^Q = 16\)
    • If \(P = 16\), and \(Q = 1\), then \(P^Q=16\)
      o \(|P-Q|=15\)
    • If \(P = 4\), and \(Q = 2\), then \(P^Q=16\)
      o \(|P-Q|=2\)
    • If \(P = -4\), and \(Q = 2\), then \(P^Q=16\)
      o \(|P-Q|=6\)
    • If \(P = 2\), and \(Q = 4\), then \(P^Q=16\)
      o \(|P-Q|=2\)
    • If \(P = -2\), and \(Q = 4\), then \(P^Q=16\)
      o \(|P-Q|=6\)

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE


Statement 1:
    • It means \(Q\) can either be \(2\) or \(4\),
      o Here, multiple cases are possible and the value \(|P-Q|\) for each case is different.
Hence, statement 1 is not sufficient, we can eliminate answer options B, C, and E.
Statement 2:
    • It means \(p\) can either be \(2, 4\) or \(16\).
      o Here, multiple cases are possible and the value \(|P-Q|\) for each case is different.
Hence, statement 2 is also not sufficient, we can eliminate option B.

Step 3: Analyse Statements by combining.


From equation 1: Q can be either \(2\) or \(4\)
From equation 2: P can be either \(2, 4\), or \(16\)
By combining the both there are two possible cases.
    • Case 1: If \(p = 4\) and \(Q = 2\), then \(|P-Q|=2\).
    • Case 2: If \(P = 2\) and \(Q = 4\), then \(|P-Q|=2\).
Hence, the correct answer is Option C.
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Quote:
If P and Q are integers and P^Q = 16, what is the value of |P - Q| ?

(1) Q ≠ 1
(2) P > 0

PˆQ=16 (both integers)
P,Q: 2ˆ4, -2ˆ4, 4ˆ2, -4ˆ2, 16ˆ1

(1) Q ≠ 1 insufic

q=4,2
p=2,-2,4,-4
|p-q|: 2-4=-2=2, -2-4=-6=6, -4-2=-6=6, 4-2=2

(2) P > 0 insufic

p=2,4,16
q=4,2,1
|p-q|: 2-4=-2=2, 4-2=2, 16-1=15

(1&2) sufic

p=2,4
q=4,2
|p-q|: 2-4=-2=2, 4-2=2,

Ans (C)
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If P and Q are integers and P^Q = 16, what is the value of |P - Q| ?

(1) Q ≠ 1

If P=2, Q=4, |P-Q|=2
If P=-4, Q=2, |P-Q|=6

Not Sufficient

(2) P > 0

If P=16, Q=1, |P-Q|=15
If P=2, Q=4, |P-Q|=2

Not Sufficient

(1)+(2)

Either P=2, Q=4 or P=4, Q=2

In both cases |P-Q|=2

Sufficient

Answer is (C)
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IMO A.

If q!=1 then we have 2^4 =16
4^2 =16 Resulting answer to be 2 in both cases. Hence sufficient.

Stmt 2 says p greater than 0 can be 16,4,2 can have resulting answer to be 2 or 15
Insufficient
.

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If P and Q are integers and P^Q = 16, what is the value of |P - Q|?

(1) Q ≠ 1
(2) P > 0

(1) Q ≠ 1 => P = -4; Q = 2 or P = 4; Q = 2
=> Not Suff

(2) P > 0 => P = 16; Q = 1 or P = 4; Q = 2
=> Not Suff

Combine (1) & (2) => P = 4; Q = 2
=> Suff

=> Choice C
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If P and Q are integers and P^Q = 16, what is the value of |P - Q| ?

(1) Q ≠ 1
(2) P > 0
Conditions:
• P and Q are integers
• P^Q = 16

First cases:
(I) Let p = -4 and Q = 2, then P^Q = (-4) ^2 = 16
Therefore, |P- Q | = |-4- 2 |= |-6 |= 6
(II) P = 4 and Q = 2, then P^Q = (4) ^2 = 16
Therefore, |P- Q | = |4- 2 |= |2 |= 2
(III) P = 2 and Q = 4, then P^Q = (2) ^4 = 16
Therefore, |P- Q | = |2- 4 |= |-2 |= 2
Therefore, statement (1) is not sufficient.

Second cases:
(I) Let p = 2 and Q = 4, then P^Q = (2) ^4 = 16
Therefore, |P - Q| = |2- 4 |= |-2 |= 2
(II) P = 4 and Q = 2, then P^Q = (4) ^2 = 16
Therefore, |P- Q | = |4- 2 |= |2 |= 2
(III P = 16 and Q = 1, then P^Q = (16) ^1 = 16
Therefore, |P- Q | = |16- 1 |= |15 |= 15
Therefore, statement (2) is not sufficient.

Combining both statements, considering (II) and (III) from First Cases and (I) and (II) from Second Cases, we can decide (C)
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We are given that p and q are integers such that p^q = 16. We are to determine |p-q|

Since p and q are integers, we only need to find the possible integral values of p^q=16
There are three possibilities:
2^4, where p=2 and q=4, and |p-q|=|q-p|=2
4^2, where p=4 and q=2, and |p-q|=|q-p|=2
16^1, where p=16 and q=1, and |p-q|=|q-p|=15

Statement 1: q!=1
Sufficient. Since either p=2 and q=4 or p=4 and q=2. In each of this cases, |p-q|=|q-p|=2

Statement 2: p>0
Insufficient since we know p can be 2, 4, or 16 and when p=2 or p=4, |p-q|=2. But when p=16, |p-q|=15.

A is the answer.
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1)
P=4, Q=2, |P - Q| = 2
P=-4, Q=2, |P - Q| = 6
P=2, Q=4, |P - Q| = 2
P=-2, Q=4, |P - Q| = 6
NOT SUFFICIENT

2)
P=4, Q=2, |P - Q| = 2
P=16, Q=1, |P - Q| = 15
P=2, Q=4, |P - Q| = 2
NOT SUFFICIENT

1)+2)
P=4, Q=2, |P - Q| = 2
P=2, Q=4, |P - Q| = 2
SUFFICIENT

FINAL ANSWER IS (C)

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If P and Q are integers and P^Q = 16, what is the value of |P - Q| ?

(Statement1): Q ≠ 1
It could be \(2^{4}\), \(4^{2}\), \((-2)^{4}\) or \((-4)^{2}\)
\(|2-4|=2, |4-2|=2, |-2-4|=6 or |-4-2|=6 \)
Insufficient

(Statement2): P > 0
\(16^{1}=16\) --> \(|16-1|=15\)
\(2^{4}= 16 \)--> \(|2-4|= 2\)
Insufficient

Taken together 1 &2,
\(2^{4}=16 --> |2-4|=2\)
\(4^{2}= 16 --> |4-2|= 2\)
Sufficient

The answer is C.
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Soln:
P & Q are integers. +ve or -ve.
Possible values for (P,Q) are (-4,2),(-2,4),(2,4),(4,2),(16,1).
Possible values of |P-Q|
|P-Q|=|-4-2|=|-2-4|=6
|P-Q|=|2-4|=|4-2|=2
|P-Q|= |16-1| =15.

Statements:
1) Q not equal to 1.
So, P cannot be 16. But, We don't know whether P is +ve or -ve.
Not sufficient

2) P>0
Shows P is +ve. But P maybe 2,4 or 16.
Not sufficient

Combining, P is +ve and not 16. So |P-Q|=2
Answer C
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