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If r and t are three-digit positive integers, is r greater than t ?
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24 Jun 2017, 07:07
5
7
If r and t are three-digit positive integers, is r greater than t ?
(1) The tens digit of r is greater than each of the three digits of t. We know nothing about the hundreds digit of r. Not sufficient.
(2) The tens digit of r is less than either of the other two digits of r. We know nothing about t.
(1)+(2) From (2) we know that the tens digit of r, is smallest of the three and from (1) we know that the tens digit of r is greater than each of the digits of t. Thus, the hundreds digit of r must be greater than the hundreds digit of t, which means that r > t. Sufficient.
If r and t are three-digit positive integers, is r greater than t ?
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02 Jul 2017, 07:59
If R = 100a + 10b + c, and T = 100d + 10e + f, then From the 1st statement it follows that b>d, b>e, and b>f, however a and c are not given - NS From the 2nd statement: a > b, and c > b, hence a > d, e, f and c > d, e, f but b is not given - NS From both statements: 100a+10b+c > 100d + 10e + f
Re: If r and t are three-digit positive integers, is r greater than t ?
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24 Jul 2017, 10:51
Use nos
Statement 1 -let Digit r=x9y and digit t=888 so X could be 9 or 7 or some other no hence not sufficient Statement 2- 10's digit is less than either of the 2 digits of R eg 656 or 746 hence not sufficient
combined
eg r=898 and t=888 hence r>t and both statements together are sufficient.
Re: If r and t are three-digit positive integers, is r greater than t ?
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06 Nov 2017, 02:35
I have a question:
If both r and t are 3-digits numbers, it means that they are >= 100 (at least 100). So, if the tens digit of r is greater than each of t's digits, that means that the tens digit of r is at least 2 (since the smallest 3-digit number is 100). If this case, r is at least 12X and t is at least 100. So why isn't statement 1 sufficient?
Re: If r and t are three-digit positive integers, is r greater than t ?
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06 Nov 2017, 02:57
Mike2805 wrote:
I have a question:
If both r and t are 3-digits numbers, it means that they are >= 100 (at least 100). So, if the tens digit of r is greater than each of t's digits, that means that the tens digit of r is at least 2 (since the smallest 3-digit number is 100). If this case, r is at least 12X and t is at least 100. So why isn't statement 1 sufficient?
hi..
the statement should give yes clear answer to is r>t?
lets see.. t = 345, r can be 786 so r>t t=345, r can be 286 now r<t so different answers possible insyff
_________________
Re: If r and t are three-digit positive integers, is r greater than t ?
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17 Nov 2017, 12:34
AbdurRakib wrote:
If r and t are three-digit positive integers, is r greater than t ?
(1) The tens digit of r is greater than each of the three digits of t .
(2) The tens digit of r is less than either of the other two digits of r .
We are given that r and t are three-digit positive integers and need to determine whether r is greater than t.
Statement One Alone:
The tens digit of r is greater than each of the three digits of t.
Statement one alone is not sufficient to answer the question. For example, if r = 190 and t = 180, then r is greater than t; however, if r = 190 and t = 210, then r is less than t.
Statement Two Alone:
The tens digit of r is less than either of the other two digits of r.
Since we know nothing about t, statement two alone is not sufficient to answer the question.
Statements One and Two Together:
Using statements one and two, we see that the tens digit of r is greater than each of the three digits of t and that the tens digit of r is less than either of the other two digits of r.
Thus, we can say that all digits of r must be greater than all digits of t, so we can say that r is greater than t.
Re: If r and t are three-digit positive integers, is r greater than t ?
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19 Nov 2017, 13:50
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Hi All,
We're told that R and T are both three-digit positive integers. We're asked if R is greater than T. This is a YES/NO question. We can solve it by TESTing VALUES.
1) The TENS digit of R is greater than each of the three digits of T.
IF.... R = 191 and T = 111, then the answer to the question is YES. R = 191 and T = 888, then the answer to the question is NO. Fact 1 is INSUFFICIENT
2) The TENS digit of R is less than either of the other two digits of R.
Fact 2 tells us NOTHING about the value of T, so there's no way to determine whether R is greater than T or not. Fact 2 is INSUFFICIENT
Combined, we know: -The TENS digit of R is greater than each of the three digits of T. -The TENS digit of R is less than either of the other two digits of R.
With Fact 1, we know that the TENS digit of R is greater than all 3 digits in T, but we had no way to compare the HUNDREDS digits of R and T (so we didn't know which number was bigger). With the information in Fact 2 though, we know that the TENS digit of R is LESS than the HUNDREDS digit of R. Thus, we can create the following inequality:
(Hundreds digit of R) > (Tens digit of R) > (ANY digit in T)
eg. R = 870 and T = 512
Since the HUNDREDS digit of R is greater than EACH digit in T (including the HUNDREDS digit of T), R will ALWAYS be greater than T. Combined, SUFFICIENT
If r and t are three-digit positive integers, is r greater than t ?
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14 Aug 2018, 04:41
AbdurRakib wrote:
If r and t are three-digit positive integers, is r greater than t ?
(1) The tens digit of r is greater than each of the three digits of t .
(2) The tens digit of r is less than either of the other two digits of r .
Statement One: R can be 245 and T can be 222 ( r is greater than t)
R can be 257 and T can be 333 ( r is less than t)
Hence St.(1) alone is insufficient
Statement Two: R can be 768 for example. But no information about T is given.
Hence St.(2) alone is insufficient
Combined (1)+(2)
(1) The tens digit of r is greater than each of the three digits of t .
(2) The tens digit of r is less than either of the other two digits of r
If R is 768 and tens digit of R is Greater than Each of the Three Digits of T , it means T can be 555, 545, 455, etc (in other words each digit of T will be less than 6)
close
69% (01:38) correct 
YAY!
