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Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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15 Jun 2011, 11:58

should the question not be -

If R is an integer ,is R exactly divisible by 3? a. 2R is exactly divisible by 3. b. 3R is exactly divisible by 3.

st -1 mentions that 2R is exactly divisible by 3 meaning R has to be multiple of 3. sufficient.

st-2 - 3R is exactly divisible by 3. meaning R could be 2 in which case 3R=6 is exactly divisible by 3. and R could be 3 in which case 3R = 9 is exactly divisible by 3. But in case 1, then R is not divisible by 3, and in 2nd case R is divisible by 3. so not sufficient.

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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04 Aug 2011, 04:41

The answer is (A).

Statement (1): If 2R is divisible by 3, then R has to be divisible by 3, because multiplying R by 2 does not multiply it by a multiple of 3. Sufficient. Statement (2): If 3R is divisible by 3, then R may or may not be divisible by 3. Example: 21 (3x7) is divisible by 3, but 7 is not. Similarly, 18 (3x6) is divisible by 3, and so is 6. Not sufficient.

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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25 Oct 2011, 02:34

Statement 1: Since 2 is not divisible by 3, R should be a divisible by 3 for 2R to be divisible. Hence sufficient. Statement 2: This statement is not sufficient as 3 is divisible by 3 and we cannot make out from this whether R can be divided or not. SO the answer is A.

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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19 Apr 2016, 00:20

kashishh wrote:

Q. if R is an integer, is R evenly divisible by 3 1. 2R is evenly divisible by 3 2. 3R is evenly divisible by 3

Statement 1: 2R is evenly divisible by 3 Since 2 is not a multiple of 3, hence # should be a multiple of 3 Sufficient

Statement 2: 3R is evenly divisible by 3 Since 3 is a multiple of 3, R may or may not be a multiple of 3 Case 1: R = 2, 3R = 6. Here R is not a multiple of 3. Case 2: R = 3, 3R = 9. Here R is a multiple of 3. Insufficient