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Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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03 Apr 2015, 06:53

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Bunuel wrote:

If R is an integer, is R evenly divisible by 3?

(1) 2R is evenly divisible by 3 (2) 3R is evenly divisible by 3

Kudos for a correct solution.

Let's revisit the rules of divisibility. For an integer x*y to be divisible by 3, either x OR y must be divisible by 3 (or both).

I) 2 is not divisible by 3, so for 2R to be divisible by 3, R must be divisible by 3. SUFFICIENT II) 3 is divisible by 3, so R may or not be divisible by 3. Think about it, R can be any integer and 3R is still divisible by 3. INSUFFICIENT.

When dealing with DS questions, you have to make sure that you are answering the question that is ASKED.

Here, we're asked if R is evenly divisible by 3. This is a YES/NO question.

When dealing with Fact 1, you correctly determined that R could be 3 or 6 (among other values), but you considered that to be insufficient.

IF R = 3, then the answer to the question is YES IF R = 6, then the answer to the question is still YES This evidence proves that Fact 1 is SUFFICIENT. Any additional values that you would come up with would ALSO be multiples of 3, so those answers would ALSO be YES.

Losing sight of the details on DS questions can cost you dearly on Test Day. Here, your examples were perfect, but your note-taking was 'off' and it cost you the question. To maximize your score, a bit more note-taking and attention-to-detail is required.

Concentration: Technology, Social Entrepreneurship

WE: Information Technology (Computer Software)

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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04 Apr 2015, 23:40

Is R is evenly divisible by 3?

1. 2R is divisible by 3; it can only happen when R is divisible by 3. sufficient 2. 3R is divisible by 3; R ma or may not be divisible by 3, as 3 is divisible by 3. Insufficient

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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05 Apr 2015, 02:04

Bunuel wrote:

If R is an integer, is R evenly divisible by 3?

(1) 2R is evenly divisible by 3 (2) 3R is evenly divisible by 3

Kudos for a correct solution.

Answer=A 1. 2R is evenly divisible by 3. R has to be a multiple of 3. 2. 3R is evenly divisible by 3. R may/may not be a mutilple of 3. Not sufficient.

If R is an integer, is R evenly divisible by 3? [#permalink]

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05 Apr 2015, 02:12

If R is an integer, is R evenly divisible by 3?

(1) 2R is evenly divisible by 3 (2) 3R is evenly divisible by 3

IMO answer is A

Evenly divisible means ---> The quotient after division done should leave NO REMAINDER ---> Simply means perfectly divisible 1) 2R is evenly divisible by 3--> Here 3 cannot divide 2 , definitely R must be divisible and as such EVENLY divisible as quoted so A sufficient

2) 3 R is evenly divisible----> Here 3 can be divided by 3 and We cannot quote about R without ambiguity if it can divide 3 or not B is NOT SUFFICIENT

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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05 Apr 2015, 20:34

Bunuel looks like a simple question, but i'm a bit confused in the Question "is R evenly divisible by 3?" Does it mean simply that R is divisible by 3? or Does it mean that R is evenly divisible, ie R/3 = some Even integer. so when R = 3, R is divisible by 3, but R is not evenly divisible by 3.
_________________

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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11 Aug 2017, 22:51

I have a query for all the explanations that are given and with the answer as well.

If we decide that answer is A, we accept that A is 'evenly divisible' means that integer should be divisible with an even integer, with remainder 0.

But then why we are avoiding the word 'evenly' in question as well.

If we take A, that means that '3' can be the value of R. Which is not evenly divisible by 3, as it is divisible by 1.

This means that statement A is not sufficient.

I think answer should be 'C', as when we combine both statement, that 2R and 3R both evenly divisible by 3, we are left with only one value of R i.e. 6, which is evenly divisible by 3.

Someone kindly explain to me why I should avoid the word 'evenly' in the question or not mean it divisible by an integer which is even.

I have a query for all the explanations that are given and with the answer as well.

If we decide that answer is A, we accept that A is 'evenly divisible' means that integer should be divisible with an even integer, with remainder 0.

But then why we are avoiding the word 'evenly' in question as well.

If we take A, that means that '3' can be the value of R. Which is not evenly divisible by 3, as it is divisible by 1.

This means that statement A is not sufficient.

I think answer should be 'C', as when we combine both statement, that 2R and 3R both evenly divisible by 3, we are left with only one value of R i.e. 6, which is evenly divisible by 3.

Someone kindly explain to me why I should avoid the word 'evenly' in the question or not mean it divisible by an integer which is even.

Evenly divisible = simply divisible, it does not mean that the result of division should be even.
_________________

Re: If R is an integer, is R evenly divisible by 3? [#permalink]

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13 Aug 2017, 09:16

1) 2R is divisible by 3 2R can be 0,6,12,18 .... and so on positive and negative R can be 0,3,6,9....... so on, both positive and negative clearly R is divisible by 3. so A,D can be answer. 2) 3R is divisible by 3 3R can be 0,3,6,9,12,15.....and so on both positive and negative R can be 0,1,2,3,4,5.......and so on both positive and negative 1 is not divisible by 3 , whereas 3 is divisible by 3. INSUFFICIENT D is Ruled out and Answer is A _________________

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