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Math Revolution GMAT Instructor
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If set A={a,b,c,d,e}, what is the number of subsets that must include
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27 Jun 2017, 01:05
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92% (00:49) correct 8% (00:47) wrong based on 57 sessions
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If set A={a,b,c,d,e}, what is the number of subsets that must include only 3 elements? A. 8 B. 10 C. 12 D. 15 E. 18
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Re: If set A={a,b,c,d,e}, what is the number of subsets that must include
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27 Jun 2017, 01:06
Chosing 3 elements out of 5 : 5c3 = 10 = B
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If set A={a,b,c,d,e}, what is the number of subsets that must include
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27 Jun 2017, 01:21
MathRevolution wrote: If set A={a,b,c,d,e}, what is the number of subsets that must include only 3 elements?
A. 8 B. 10 C. 12 D. 15 E. 18 Set A={a,b,c,d,e}
Number of ways to select 3 elements from set of 5 elements \(= \frac{5!}{3!(53)!}\)
\(\frac{5!}{3!2!} = \frac{5 * 4* 3*2}{3*2 * 2} = 5 * 2 = 10\). Answer (B)..._________________ Please Press "+1 Kudos" to appreciate.



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If set A={a,b,c,d,e}, what is the number of subsets that must include
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27 Jun 2017, 05:47
Question asks how many ways can you choose 3 items out of 5 = 5C3 = 10 Answer B



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Re: If set A={a,b,c,d,e}, what is the number of subsets that must include
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29 Jun 2017, 02:59
==> You get 5C3=5C2=(5)(4)/2!=10. The answer is b. Answer: B
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Re: If set A={a,b,c,d,e}, what is the number of subsets that must include
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29 Jun 2017, 15:19
If set A={a,b,c,d,e}, what is the number of subsets that must include only 3 elements?\(= 5C2\) \(= \frac{5!}{2! * 3!}\) \(= 5 * 2\) \(= 10\) Hence, Answer is B
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Re: If set A={a,b,c,d,e}, what is the number of subsets that must include
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29 Jun 2017, 15:19






