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sananoor
If the average (arithmetic mean) of six numbers j, k, m, n, p, and q is 56, how many of the numbers are equal to 56?

(1) The sum of j and p is 128.
(2) The sum of m, n, and q is 152.

I would go for E

Since 1) J and P can be any value ( No idea about M, N and P) Insufficient
2) same as above M, N, Q can be any value ( No idea about J and P) Insufficient

both 1 and 2 ( J, P, M, N, Q) can again be any value to make the sum 290 Insufficient
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sananoor
If the average (arithmetic mean) of six numbers j, k, m, n, p, and q is 56, how many of the numbers are equal to 56?

(1) The sum of j and p is 128.
(2) The sum of m, n, and q is 152.

St 1:
I can have j as 128 and p as 0

St 2:
I can have m and n as 0 and q as 152.

Combined: I can still have 3 zeros and the average as 56.

Not a great question but has a trap
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