saurabh9gupta wrote:

Bunuel wrote:

If the figure above is drawn to scale, which of the following could be the equation of line l?

(A) \(y = 4x + 4\)

(B) \(y = 4x - 4\)

(C) \(y = x - 6\)

(D) \(y = x + \frac{1}{2}\)

(E) \(y = -x - 3\)

My logic is :

Since the line is upward sloping.. the slope will be positive, E is out

Also the line cuts the Y axis on the negative side , therefore c <0

Eqn from is y = mx + c

so now just B and C remain.. I took a guess then marked C

chetan2u anything that i am missing here?

Yes, you are absolutely correct with your approach but you don't have to guess when you get down to B and C..

B is 4x-4=y..

So when y=0, 4x-4=0.....X=1

When x=0, y=4

So y intercept should be at a distance of 4 times more than x-intercept, but figure is drawn to scale and it shows almost same..

C is y=x-6.

So when y=0, X=6

When x=0, y=-6

So y intercept should be at same distance from origin as x-intercept, and figure is drawn to scale and it also shows almost same..

So C

_________________

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