If the first term in an arithmetic sequence is 15 and the 132th term

Question

If the first term in an arithmetic sequence is 15 and the 132th term is 3,290, what is the common difference between any two consecutive terms?

A. 10
B. 15
C. 25
D. 30
E. 35

chipsy · Answer

a+131d = 3290
Since a = 15

15+131d = 3290
 d = 3275/131
 d = 25

Option C

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v12345 · Answer

132 term = 3290
=> a + 131d = 3290
=> 131d = 3275
=> d = 25

Hence, OA is (C).

SIDDHARTH1901 · Answer

Difference between 1st term and 132nd term is 131*d.

Therefore, 131*d= 3290 - 15
 131*d= 3275
 d= 25.

Hence, option C , 25 is the common difference.

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MathRevolution · Answer

a = 15 and a + 131d = 3,290

=> 15 + 131d = 3,290

=> 131d = 3,290 - 15 = 3,275

=> d = 25

Answer C

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