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If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

If the price of a computer were reduced by 16 percent, which of the fo [#permalink]

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28 Apr 2016, 00:06

Bunuel wrote:

If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

I go with E. Basically i checked for the divisibility since 84 = 4*3*7
_________________

Aiming for a 3 digit number with 7 as hundredths Digit

If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

I go with E. Basically i checked for the divisibility since 84 = 4*3*7

Hi Balaji,

Your method is correct but application is NOT.. since the final price has to be a multiple of 84 or 4*3*7, easiest is to check for div by 3.. E is correct as the total is 1+2+6+4+2 = 15, div by 3.. ans will be A 844.10..SUM = 8+4+4+1 = 17, NOT div by 3.. ans A
_________________

Re: If the price of a computer were reduced by 16 percent, which of the fo [#permalink]

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10 May 2016, 11:46

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This post was BOOKMARKED

Bunuel wrote:

If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

Let X be the initial price of computer without discount then price (final) after discount should be=X(1-16/100)------->X(21/25)=A(say) means X=A*(25/21)..... so initial price to be integer(As per stem) final price must be multiple of 21(3 or 7) if we check options all were divisible by 3 except option (A)..which is Ans. Ans A

Re: If the price of a computer were reduced by 16 percent, which of the fo [#permalink]

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10 May 2016, 12:13

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This post received KUDOS

1

This post was BOOKMARKED

Bunuel wrote:

If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

Price is reduced by 16% i.e the new price is 84% of the old price. Hence the new price is multiple of 2X2X3X7 Check the divisibility by 3 as this is the easiest to do. It will give 'A' as the right choice.
_________________

I welcome critical analysis of my post!! That will help me reach 700+

Re: If the price of a computer were reduced by 16 percent, which of the fo [#permalink]

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10 Jul 2017, 23:12

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Re: If the price of a computer were reduced by 16 percent, which of the fo [#permalink]

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11 Aug 2017, 03:30

Bunuel wrote:

If the price of a computer were reduced by 16 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)

A. $844.10 B. $896.70 C. $1,056.30 D. $1,136.10 E. $1,264.20

Let price of the computer P$ = 100*P cents. If the price were reduced by 16 % . The final price will be 84P cents.

So, the options *100 must be a multiple of 84

Now 84 = 2*2*3*7

All the options are divisible by 2 Lets check divisibility by 3 A. 8+4+4+1+0 = 17 not divisible by 3 B. 8+9+6+7+0 = 30 which is divisible by 3 C. 1+0+5+6+3+0 = 15 which is divisible by 3 D. 1+1+3+6+1+0 = 12 which is divisible by 3 E. 1+2+6+4+2+0 = 15 which is divisible by 3.