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Bunuel
If x and y are integers and x − y is odd, which of the following must be true?

I. xy is even.
II. x^2 + y^2 is odd.
II. (x + y)^2 is even.

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


NEW question from GMAT® Quantitative Review 2019


(PS01120)


IMO D must be correct answer :-)

Let X = 7 and Y = 2

I. xy is even ( 7*2 = 14 ) correct :)

II. x^2 + y^2 is odd. \(7^2+2^2 = 53\) TRUE

II. (x + y)^2 is even. \((7+ 2)^2 = 49+4 =53\) FALSE

EDIT
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Bunuel
If x and y are integers and x − y is odd, which of the following must be true?

I. xy is even.
II. x^2 + y^2 is odd.
II. (x + y)^2 is even.

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


The only way to get an odd sum or difference of two integers is if one integer is odd and the other integer is even. Since x - y is odd, then x is even and y is odd OR x is odd and y is even.

We recall that even x odd = even. Thus, xy must be even. Thus, Roman numeral I is true.

Since odd + even = odd, we see that x^2 + y^2 must be odd, and (x + y)^2 must be odd. Thus, Roman numeral II is true and Roman numeral III is false.

Answer: D
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Bunuel
If x and y are integers and x − y is odd, which of the following must be true?

I. xy is even.
II. x^2 + y^2 is odd.
II. (x + y)^2 is even.

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


NEW question from GMAT® Quantitative Review 2019


(PS01120)

Can be solved much faster and without any substitution if we know that even - odd = odd. From this we know that one number must be even. What applies to subtraction in terms of even/odd applies to addition.

even * odd = even

Having a power does not change whether the number is odd or even.

only I and II are true.
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Input numbers 3&2 and 5&2.

Smash D
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Given
    • x and y are integers and x − y is odd
      o One of x and y is even and another is odd.

To find
    • The correct option.

Approach and Working out

I – xy is even
    • Multiplication of one even and one integer is always even.

II - x^2 + y^2 is odd.
    • Even ^2 + Odd^2 = Even + Odd = Odd

III - (x + y)^2 is even.
    • Odd^2 = Odd
    • Not true

Thus, option D is the correct answer.

Correct Answer: Option D
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EgmatQuantExpert
Given
    • x and y are integers and x − y is odd
      o One of x and y is even and another is odd.

To find
    • The correct option.

Approach and Working out

I – xy is even
    • Multiplication of one even and one integer is always even.

II - x^2 + y^2 is odd.
    • Even ^2 + Odd^2 = Even + Odd = Odd

III - (x + y)^2 is even.
    • Odd^2 = Odd
    • Not true

Thus, option D is the correct answer.

Correct Answer: Option D


Hi Payal

why don't we need to consider 0 here? it is an integer right?

3-0=3 but 3x0=0 is not even.
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\(\)If x and y are integers and x − y is odd, which of the following must be true?

For x - y to be odd, x and y must be odd/even or even/odd.

I. \(xy\) is even. -- MUST BE TRUE
II. \(x^2 + y^2\) is odd. -- MUST BE TRUE
II. \((x + y)^2\) is even. -- FALSE

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III

Answer is D.
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Asking the same question as perryzhu. Why isnt 0 considered here?
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LostGMATFellow
Asking the same question as perryzhu. Why isnt 0 considered here?

Quote:
3-0=3 but 3x0=0 is not even.

0 is considered even from a mathematical point of view. "3x0=0" would be even therefore.
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LostGMATFellow
Asking the same question as perryzhu. Why isnt 0 considered here?
Zero is an EVEN integer.

ZERO:

1. Zero is an INTEGER.

2. Zero is an EVEN integer.

3. Zero is neither positive nor negative (the only one of this kind)

4. Zero is divisible by EVERY integer except 0 itself (\(\frac{x}{0} = 0\), so 0 is a divisible by every number, x).

5. Zero is a multiple of EVERY integer (\(x*0 = 0\), so 0 is a multiple of any number, x)

6. Zero is NOT a prime number (neither is 1 by the way; the smallest prime number is 2).

7. Division by zero is NOT allowed: anything/0 is undefined.

8. Any non-zero number to the power of 0 equals 1 (\(x^0 = 1\))

9. \(0^0\) case is NOT tested on the GMAT.

10. If the exponent n is positive (n > 0), \(0^n = 0\).

11. If the exponent n is negative (n < 0), \(0^n\) is undefined, because \(0^{negative}=0^n=\frac{1}{0^{(-n)}} = \frac{1}{0}\), which is undefined. You CANNOT take 0 to the negative power.

12. \(0! = 1! = 1\).



2. Properties of Integers



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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