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what if I assume that y=1 and vary x = 2,3,.... For all those options ST1 not sufficient as X can be odd or even. Please correct me.
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what if I assume that y=1 and vary x = 2,3,.... For all those options ST1 not sufficient as X can be odd or even. Please correct me.

Hi ANGHOS82,

Notes:-

1) An odd number can be prime. (Example 1, 3,7,11 etc)
2) An even number can be prime. (Example only 2)
3) 1 is not prime.
4) 1 is odd.
5) 1 raised to the power any positive integer is equal to 1.

As per your picked numbers,

y=1, x=2; so \(y^x=1^2=1\) , which is not a prime number, violating statement 1.

So, we can't pick y=1.

Hope it helps.
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Bunuel

GMAT CLUB'S FRESH QUESTION



If x and y are positive integers, is x even?

(1) y^x is a prime number
(2) x*y is a prime number


Hi, I tested x=0, to get that raising anything to 0 will result in a prime number, 1. Raising a prime number to 1, will result (obviously) to that same prime number. Hence, x could be either 0 or 1.

I made a silly mistake since it clearly stated that x and y are positive integers, so that would eliminate 0 as an option and make statement 1 sufficient (always odd). Just writing down my question helped to spot where I went wrong.
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Bunuel

GMAT CLUB'S FRESH QUESTION



If x and y are positive integers, is x even?

(1) y^x is a prime number
(2) x*y is a prime number

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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Bunuel

GMAT CLUB'S FRESH QUESTION



If x and y are positive integers, is x even?

(1) y^x is a prime number
(2) x*y is a prime number

#1:
3^1 or 2^1 prime no so x has to be 1 only sufficient

#2: x*y= prime x can be either even or odd in case of 2*1 so in sufficient

IMOA
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Bunuel

GMAT CLUB'S FRESH QUESTION



If x and y are positive integers, is x even?

(1) y^x is a prime number
(2) x*y is a prime number

Statement 1) a prime no has only 2 factors, 1 and itself. So, if y^x is prime. No of factors=x+1, x+1=2, x=1, x is odd. Sufficient.
Statement 2) x can 1 or the prime number. If xy=2, x can be 1 or 2. Either odd or even. Insufficient.
Hence, Option A is correct.
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