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If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 19:29
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42% (02:00) correct 58% (01:57) wrong based on 201 sessions
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If xy > 0 and both x and y are even numbers, is x > y? (1) x > y  2 (2) x  y > 4 New question!!!..
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 20:26
chetan2u wrote: If xy>0 and both x and y are even numbers, is x>y? (I) x>y2 (II) xy>4
New question!!!.. OE to follow.. xy>0..... x and y are even... 1) x>y2 x+2>y So y <x in all cases except when x=y.. Example say x=6, y<x+2 or y<6+2 that is y<8 but y cannot be 7 as y is even, so (I) y will be 6 or x=y OR (II) y can be 4,2 etc or X>y Insufficient 2) xy>4 We cannot say if y>x or x>y but surely \(x\neq{y}\) Insufficient Combined.. We know from statement I that either x=y or X>y But statement II tells us that \(x\neq{y}\) So only possibility x>y Sufficient C
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 20:51
chetan2u wrote: If xy>0 and both x and y are even numbers, is x>y? (I) x>y2 (II) xy>4
New question!!!.. The answer is C . since xy>0; here is my list of values from statement 1: x=2; y= 8 x=4; y =4 statement 1 is insufficient from statement 2: x=2; y=8 x=8; y=2 x=2; y=8 x=8; y=2 statement 2 is insufficient combining both makes it sufficient. C



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 21:31
Xy>0 means either x ND y r both ve or both are positive. 1) not sufficient.as x can be bigger/smaller than y or equal 2) sufficient: xy >4 or yx < 4; for both +ve ND ve x> y AnswerB Sent from my Redmi 5 Plus using GMAT Club Forum mobile app



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 22:01
deepverma wrote: Xy>0 means either x ND y r both ve or both are positive. 1) not sufficient.as x can be bigger/smaller than y or equal 2) sufficient: xy >4 or yx < 4; for both +ve ND ve x> yAnswerB Sent from my Redmi 5 Plus using GMAT Club Forum mobile appyou will have to recheck highlighted portion xy>4 two cases 1) \(xy\geq{0}\) xy>0 2) \(xy<{0}\) (xy)>4.......yx>4 both xy >4 and yx < 4 are SAME
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 22:38
chetan2u wrote: If xy>0 and both x and y are even numbers, is x>y? (I) x>y2 (II) xy>4
New question!!!.. Given: both x and y are even numbers xy>0: This means both x & y have same sign. Statement 1: x>y2 Case 1 both x,y >0 eg 8>62 x>y Yes Case 2: both x,y<0 eg 8>82 x>y No Hence InsuficientStatement 1: xy>4 that means the distance between x & y is 4, but we dont know their relative positions. Hence Insufficient.Considering both Statement 1 &2 10>62 Sufficient.Answer: C
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Re: If xy > 0 and both x and y are even numbers, is x > y?
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10 Sep 2018, 22:42
Ya got it. thanks. Should be xy >4 or xy < 4 ND not sufficient. Combining 1)ND 2) gives ultimate xy > 4 which means x>y . So answer is C Sent from my Redmi 5 Plus using GMAT Club Forum mobile app



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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17 Sep 2018, 02:33
How does the "even" information come into play?
Once I consider 2 conditions together, it was hard to see if it satisfies x > y. x y > 2 AND x y > 4
I had to guess it is C because I picked a pair of different sign x and y ( x=5, y =1) and it could not satisfy both conditions > probably they must be same sign. Kinda not sure about this one.



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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17 Sep 2018, 03:37
In the posted solutions above where A is determined as insufficient, there was the assumption that X can equal y. My question is , when you are told x and y are even number(s), doesn't that mean that these numbers are different numbers?



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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17 Sep 2018, 12:03
GmatDaddy wrote: chetan2u wrote: If xy>0 and both x and y are even numbers, is x>y? (I) x>y2 (II) xy>4
New question!!!.. Given: both x and y are even numbers xy>0: This means both x & y have same sign. Statement 1: x>y2 Case 1 both x,y >0 eg 8>62 x>y Yes Case 2: both x,y<0 eg 8>82 x>y No Hence InsuficientStatement 1: xy>4 that means the distance between x & y is 4, but we dont know their relative positions. Hence Insufficient.Considering both Statement 1 &2 10>62 Sufficient.Answer: CUnderstood why A and B is not an answer but still not able to understand why C is an answer, GmatDaddy could you please elaborate how both equation together are sufficient.
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Re: If xy > 0 and both x and y are even numbers, is x > y?
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17 Sep 2018, 12:37
parthos wrote: Understood why A and B is not an answer but still not able to understand why C is an answer, GmatDaddy could you please elaborate how both equation together are sufficient. We have to judge if X>Y such that both the conditions mentioned in Statement 1 and 2 are met.. If you will try to choose values accordingly, you will see that X>Y Eg: We know from 2 that the difference between X and Y is 4. Now select values of X and Y such that X>Y2 ie Y<X+2 let y be 6 now x can take either 2 or 10 Lets try both the cases 6<10+2, the answer to our ultimate question X>Y is Yes 6<2+2, this equality is absurd. similarly the other case when both X and Y are ve
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If xy > 0 and both x and y are even numbers, is x > y?
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17 Sep 2018, 17:45
Given xy>0 (Same signs). we have to check x>y or xy>0?
St 1: x>y2, xy>2. Insufficient as xy could be negative, zero or greater than 0.
St 2: xy>4 or xy<4. Insufficient as Inequality 1 gives us Yes answer while Inequality 2 gives us No Answer.
Combining st 1 & 2, we have three inequalities: xy>2 xy>4 xy<4
From here on, if anyone can explain how both statements together are sufficient it would help me in error correction. Please explain algebraic approach.



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If xy > 0 and both x and y are even numbers, is x > y?
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18 Sep 2018, 03:29
chetan2u wrote: If xy > 0 and both x and y are even numbers, is x > y?
(1) x > y  2 (2) x  y > 4
New question!!!.. xy>0..... x and y are even... 1) x>y2 x+2>y So y <x in all cases except when x=y.. Example say x=6, y<8 but y cannot be 7 as y is even, so y will be 6 or <6.. Insufficient as x can be y AND X can be >y 2) xy>4 We cannot say if y>x or x>y but \(x\neq{y}\) Insufficient Combined.. We know from statement I that either x=y or X>y But statement II tells us that \(x\neq{y}\) So only possibility x>y Sufficient C
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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If xy > 0 and both x and y are even numbers, is x > y?
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20 Oct 2018, 03:40
chetan2u wrote: chetan2u wrote: If xy > 0 and both x and y are even numbers, is x > y?
(1) x > y  2 (2) x  y > 4
New question!!!.. xy>0..... x and y are even... 1) x>y2 x+2>y So y <x in all cases except when x=y.. Example say x=6, y<8 but y cannot be 7 as y is even, so y will be 6 or <6.. Insufficient as x can be y AND X can be >y 2) xy>4 We cannot say if y>x or x>y but \(x\neq{0}\) Insufficient Combined.. We know from statement I that either x=y or X>y But statement II tells us that \(x\neq{0}\) So only possibility x>y Sufficient C Hi chetan2uFrom St.2, how did you derive x<>0? If x = 0 & y = 6, Modulus (0(6)) = 6 ==> 6>4 x<>0 can be derived from the question stem itself, because xy>0. So what value is statement 2 adding here? Didn't quite get it... Awaiting your explanation.. Thanks. Also, is this a 700+ level question?



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Re: If xy > 0 and both x and y are even numbers, is x > y?
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20 Oct 2018, 05:40
ankitamundhra28 wrote: chetan2u wrote: chetan2u wrote: If xy > 0 and both x and y are even numbers, is x > y?
(1) x > y  2 (2) x  y > 4
New question!!!.. xy>0..... x and y are even... 1) x>y2 x+2>y So y <x in all cases except when x=y.. Example say x=6, y<8 but y cannot be 7 as y is even, so y will be 6 or <6.. Insufficient as x can be y AND X can be >y 2) xy>4 We cannot say if y>x or x>y but \(x\neq{0}\) Insufficient Combined.. We know from statement I that either x=y or X>y But statement II tells us that \(x\neq{0}\) So only possibility x>y Sufficient C Hi chetan2uFrom St.2, how did you derive x<>0? If x = 0 & y = 6, Modulus (0(6)) = 6 ==> 6>4 x<>0 can be derived from the question stem itself, because xy>0. So what value is statement 2 adding here? Didn't quite get it... Awaiting your explanation.. Thanks. Also, is this a 700+ level question? Hi... Although combined too I have worked on \(x\neq{y}\) but have mentioned 0 instead of y... \(x\neq{y}\) is correct as xy cannot be 0
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1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
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Re: If xy > 0 and both x and y are even numbers, is x > y?
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21 Oct 2018, 06:05
amresh09 wrote: Given xy>0 (Same signs). we have to check x>y or xy>0?
St 1: x>y2, xy>2. Insufficient as xy could be negative, zero or greater than 0.
St 2: xy>4 or xy<4. Insufficient as Inequality 1 gives us Yes answer while Inequality 2 gives us No Answer.
Combining st 1 & 2, we have three inequalities: xy>2 xy>4 xy<4
From here on, if anyone can explain how both statements together are sufficient it would help me in error correction. Please explain algebraic approach. I arrived in the same point with the 3 equations and I combined the two first equations: xy>2 xy>4 >>> 2x  2y > 2 >>> x  y > 1 >>> x > y +1The only way to satisfy x > y +1 is when x>y. I think I didn't use those information: x and y are even and xy > 0, so we know y and x are different to zero and or both are positive or both are negative. Or am I missing some step and should I had used ?




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