If y is an even integer and x is an odd integer, which of the followin

IMO A.

If x is 1 and y is 2, answer is 4 which is even

Hi!......i could not understand....If you take example of 4 divided by 2 then it will give 2 or take example of 8 divided by 2

Notice the problem is a “could be” problem, not a “must be” problem. Let’s go through each answer choice, recalling that odd + odd = even, and odd + even = odd, and even + even = even.

A) 3x + y/2

3x is odd and y/2 could be odd (for example, if y = 6). Thus 3x + y/2 could be even.

The answer must be A. However, as an exercise, let’ verify that none of the other four choices could be even. That is, they will never be even.

B) (x + y)/2

x + y is odd and thus (x + y)/2 is not even an integer (no pun intended).

C) x + y

x + y is odd.

D) x/4 - y/2

x/4 is not an integer and y/2 is an integer, but their difference will not be an integer.

E) x^2 + y^2

x^2 is odd and y^2 is even, but their sum will be odd. Recall here that odd x odd = odd and even x even = even.

Answer: A

Hey 6 / 2 = 3 ( odd number ) but 8/2 &12/2 will give even number



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