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In 2010, a basketball team won 30 percent of its 20 basketball games.

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In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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New post 20 Dec 2015, 06:25
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In 2010, a basketball team won 30 percent of its 20 basketball games. In 2011, the team won 28 percent of its 25 basketball games. What was the percent increase from 2010 to 2011 in the number of basketball games the team won?

A. 5%
B. 14 2/7%
C. 16 2/3%
D. 23 1/3%
E. 60%

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In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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New post 20 Dec 2015, 06:34
Bunuel wrote:
In 2010, a basketball team won 30 percent of its 20 basketball games. In 2011, the team won 28 percent of its 25 basketball games. What was the percent increase from 2010 to 2011 in the number of basketball games the team won?

A. 5%
B. 14 2/7%
C. 16 2/3%
D. 23 1/3%
E. 60%


30% of 20 = 6 and 28% of 25 = 7, so percent increase \(= \frac{7-6}{6}= 16.6 %\) Answer C
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Re: In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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New post 17 May 2017, 04:23
In 2010, a basketball team won 30 percent of its 20 basketball games. In 2011, the team won 28 percent of its 25 basketball games. What was the percent increase from 2010 to 2011 in the number of basketball games the team won?

In 2010 Team won 30% of 20 games = \(\frac{30}{100}\) x 20 = 6
In 2011 Team won 28% of 25 games = \(\frac{28}{100}\) x 25 = 7
Increase in games won from 2010 to 2011 = 7-6 = 1

Percent increase = Change in games won / Initial games won x 100 = \(\frac{1}{6}\) x 100 = \(\frac{50}{3}\) = 16\(\frac{2}{3}\)
Answer C...

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Re: In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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New post 21 Jun 2017, 04:49
Bunuel wrote:
In 2010, a basketball team won 30 percent of its 20 basketball games. In 2011, the team won 28 percent of its 25 basketball games. What was the percent increase from 2010 to 2011 in the number of basketball games the team won?

A. 5%
B. 14 2/7%
C. 16 2/3%
D. 23 1/3%
E. 60%


We can apply a few simple formulas to solve this

(.3)(20)= 6

25(.28)= 7

7-6/6 = 1/6 x 100 = 16 2/3

Thus
"C"
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Re: In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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New post 21 Jun 2017, 07:36
Bunuel wrote:
In 2010, a basketball team won 30 percent of its 20 basketball games. In 2011, the team won 28 percent of its 25 basketball games. What was the percent increase from 2010 to 2011 in the number of basketball games the team won?

A. 5%
B. 14 2/7%
C. 16 2/3%
D. 23 1/3%
E. 60%


Games won in 2010 is 6
Games won in 2011 is 7

Percentage increase is \(\frac{1}{6}*100 = 16 \frac{2}{3}\) %

Thus, answer will be (C)
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Re: In 2010, a basketball team won 30 percent of its 20 basketball games.  [#permalink]

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Re: In 2010, a basketball team won 30 percent of its 20 basketball games.   [#permalink] 26 Mar 2019, 12:59
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