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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
3
Kudos
1) the information about those who took both tells us nothing about the breakdown of the 60% who took only one of two (it could be anywhere between 0% and 60% only veg). . Insufficient!
2) once again, this only tells the size of the "both" group, not the "only veg". insufficient!

Combined - both statements describe the "both" group in different ways, so we know that 20% of the total equals 25% of the veg group. If we call the only veg group y, this gives us the following equation:
y/4=(60 + y/4)/5
5y/4=60+y/4
4y/4=60
y=60
sufficient!
Read Only User
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
deushyant wrote:
Can someone please help me out? The second statement completely threw me off.

Posted from my mobile device

I am also cofused with statmenent 2. I am requesting experts to expain this.
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
deushyant wrote:
Can someone please help me out? The second statement completely threw me off.

Posted from my mobile device

check my response out - tell me if it helps
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
DavidTutorexamPAL wrote:
deushyant wrote:
Can someone please help me out? The second statement completely threw me off.

Posted from my mobile device

check my response out - tell me if it helps



Still not understanding the answer. Please Help
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
2
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TarunTilokani wrote:
Attachment:
New Doc 2019-06-11 13.12.32.jpg


Please note a minor correction in the two equations:

Statement 1: 25% of the people who had Veg also had Non–Veg.
Person who had veg according to vein diagram= a+b
i.e. 25%*(a+b)=b
i.e. 25%a=75%b
b=a/3
cannot solve further, Not sufficient

Statement 2: 20% of the people who had at least one of the two variants had both the variants.

i.e. 20% * ( a+b+c) =b
or 20% *60=80%b
b=15
Cannot solve for a, Not sufficient

Combining
a=3*15 = 45

Answer: C
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
TarunTilokani wrote:
Attachment:
New Doc 2019-06-11 13.12.32.jpg

Hey as per question, isnt a+c -b = 60. Cause they mentioned exactly one variant. and a -> all who ate Veg and b -> all who ate non veg. a+b = all veg + all non veg. This would include those who ate veg + non veg twice. So we need to subtract b. Is my understanding correct?
Intern
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
1
Kudos
I think this is a poor quality question since you don't how how many people didn't take neither Vegan nor Non-vegan food. Without that information you can't know the answer...
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Re: In a party both Veg and Non–Veg variants were served. [#permalink]
TarunTilokani wrote:
Attachment:
New Doc 2019-06-11 13.12.32.jpg

The second statement says that 20% of the people who had at least one variant, so. shouldn't the equation be 20% of (a+b+c)?
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Re: In a party both Veg and NonVeg variants were served. [#permalink]
Can someone please explain why aren't we considering the case of so guests who did not have any of the variant? Since there is no evidence that each had guest had at least one variant.
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Re: In a party both Veg and NonVeg variants were served. [#permalink]
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