Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

02 Sep 2013, 11:33

4

This post received KUDOS

18

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

62% (01:28) correct
38% (01:14) wrong based on 491 sessions

HideShow timer Statistics

Attachment:

ABCDE.png [ 1.41 KiB | Viewed 11726 times ]

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

The distance between E and C is \(9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}\);

The distance between A and D is 1.5 times the distance between C and E, thus it equal to \(120*9^{11}\)

Answer: E.

Similar question to practice:

Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

09 Sep 2013, 09:45

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

09 Sep 2013, 17:26

3

This post received KUDOS

WholeLottaLove wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E -- (9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

10 Sep 2013, 11:09

GPabla wrote:

WholeLottaLove wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E -- (9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

Wow! Such a simple mistake! I guess that's why my example is incorrect.

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

16 Sep 2014, 09:04

Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

The distance between E and C is \(9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}\);

The distance between A and D is 1.5 times the distance between C and E, thus it equal to \(120*9^{11}\)

Answer: E.

Similar question to practice:

Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

The distance between A and D is 1.5 times the distance between C and E, thus it equal to \(120*9^{11}\)- I have not understood, can you explain the logic?

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

The distance between E and C is \(9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}\);

The distance between A and D is 1.5 times the distance between C and E, thus it equal to \(120*9^{11}\)

Answer: E.

Similar question to practice:

Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

The distance between A and D is 1.5 times the distance between C and E, thus it equal to \(120*9^{11}\)- I have not understood, can you explain the logic?

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

20 Sep 2015, 02:36

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

23 Dec 2015, 13:14

Bunuel wrote:

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?
_________________

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?

It is getting multiplied by everything.

You are doing 1.5*80*9^11 but now as the answer options are all in the form A*9^11, it is better to keep 9^11 as such as you end up with : \

1.5*80*9^11 = (1.5*80)*9^11 = 120*9^11 .

In multiplication, A*B*C = (A*B)*C or A*(B*C) etc.

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

23 Dec 2015, 13:20

Engr2012 wrote:

redfield wrote:

Bunuel wrote:

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?

It is getting multiplied by everything.

You are doing 1.5*80*9^11 but now as the answer options are all in the form A*9^11, it is better to keep 9^11 as such as you end up with : \

1.5*80*9^11 = (1.5*80)*9^11 = 120*9^11 .

In multiplication, A*B*C = (A*B)*C or A*(B*C) etc.

Hope this helps.

Well I feel silly, very much overcomplicated it in my head thank you for breaking it down.
_________________

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

06 Jan 2017, 01:39

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

06 Jan 2017, 14:11

crackjack wrote:

WholeLottaLove wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

Let us first find the distance between C and E -- (9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

After 9^11(80) I could not think of divide value by 2 and multiply with 3 to get answer

and How The distance between A and D is 1.5 times the distance between C and E, thus it equal to 120∗911

Pls reply. Thanks
_________________

I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you

In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

17 May 2017, 06:12

pavan2185 wrote:

Attachment:

The attachment ABCDE.png is no longer available

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

The trap in this question is baiting the test taker to think that these lines represent a series of consistently increasing/decreasing exponents (e.x A= 9^9, B =9^10, C=9^11, D=9^12, E =9^13) with answer choice "A." Yet this is an evenly spaced set ; in other words, if we have say E as 2^5 and C as 2^3 then the distance between those two points is 24 so A cannot be 2^1 because 2^3-24 is -16. More fundamentally, the distance between any two points spaced two letter apart would be 24. In our example, the distance between E and C is

9^13-9^11 (9^2) 9^11- (1) 9^11 - do not forget that there is always an assumed one when subtracting exponents (81-1) 9^11 (80)9^11

Now the distance between any two lines spaced two letters apart must be (80)9^11 - the distance between A and C must also be (80)9^11 as well as the distance between B and D and D and E; however, the distance between and D is 3 spaces which is 1.5 the distance between C and E or moreover - A and C, C and D , B and D, D and E - conceptually, another way of understanding the problem is also that half of- (80) 9^11 or alternatively (80) 9^11 /2 - would be the distance between two sequential spaces {e.x distance between A, B, or C, B or D,E} so 3 (1/2) (80) 9^11 or (3)(80)9^11/2 would also be another method of calculating the distance. I guess you could also imagine that the spaces between letters in this evenly spaced set form a puzzle piece- so the distance between a set of letters would be the length of that puzzle piece ( example: the distance between A and B would be the length of puzzle piece AB)

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

We can let the space between each pair of consecutive points = n.

Thus, the space from C to E is n + n = 2n. So, we can create the following equation:

9^11 + 2n = 9^13

2n = 9^13 - 9^11

2n = 9^11(9^2 - 1)

2n = 9^11(80)

n = 9^11(40)

Since the distance from A to D = 3n:

3n = 3(9^11)(40) = 120(9^11)

Answer: E
_________________

Scott Woodbury-Stewart Founder and CEO

GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: In the figure, points A, B, C, D, and E are evenly spaced [#permalink]

Show Tags

08 Jul 2017, 12:04

pavan2185 wrote:

Attachment:

ABCDE.png

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3 B. 9^9 C. (120)(9^9) D. 9^11 E. (120)(9^11)

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

As the points are equidistant, lets assume, the distance between one unit = \(x\)

So Distance between C and E \(= 2x\)

\(2x = 9^{13} - 9^{11}\)

\(2x = 9^{11} (9^2 - 1)\)

\(2x = 9^{11} * (81 - 1)\)

\(2x = 9^{11} * 80\)

\(x = 9^{11} * 40\)

As the distance between A and D \(= 3x\)

\(3x = 9^{11} * 40 * 3\)

\(3x = 9^{11} * 120\)

Hence, Answer is E _________________

Kudos - I hope you liked the post, if you have liked the post, please do not hesitate to show your appreciation and support with a simple click on Kudos, it will make me happy and encourage me to support more people.

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Version 8.1 of the WordPress for Android app is now available, with some great enhancements to publishing: background media uploading. Adding images to a post or page? Now...

“Keep your head down, and work hard. Don’t attract any attention. You should be grateful to be here.” Why do we keep quiet? Being an immigrant is a constant...

“Keep your head down, and work hard. Don’t attract any attention. You should be grateful to be here.” Why do we keep quiet? Being an immigrant is a constant...