GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Feb 2019, 13:49

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
• ### Free GMAT Prep Hour

February 20, 2019

February 20, 2019

08:00 PM EST

09:00 PM EST

Strategies and techniques for approaching featured GMAT topics. Wednesday, February 20th at 8 PM EST

February 21, 2019

February 21, 2019

10:00 PM PST

11:00 PM PST

Kick off your 2019 GMAT prep with a free 7-day boot camp that includes free online lessons, webinars, and a full GMAT course access. Limited for the first 99 registrants! Feb. 21st until the 27th.

# In the figure above, points A, B, C, D, and E are evenly spaced along

Author Message
TAGS:

### Hide Tags

Manager
Joined: 15 Apr 2013
Posts: 68
Location: India
Concentration: Finance, General Management
Schools: ISB '15
WE: Account Management (Other)
In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

02 Sep 2013, 10:33
5
30
00:00

Difficulty:

45% (medium)

Question Stats:

69% (02:00) correct 31% (02:06) wrong based on 570 sessions

### HideShow timer Statistics

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3

B. 9^9

C. (120)(9^9)

D. 9^11

E. (120)(9^11)

Attachment:

ABCDE.png [ 1.41 KiB | Viewed 16186 times ]
Math Expert
Joined: 02 Sep 2009
Posts: 53020
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

02 Sep 2013, 12:48
5
5

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.
_________________
Intern
Joined: 15 Oct 2012
Posts: 21
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

02 Sep 2013, 11:18
8
5
First find out the Distance Between E and C i.e 9^13 - 9^11 = 9^11(9^2 - 1) = 9^11 * 80

Now this (9^11 * 80) is the distance between C to D and D to E i.e Two Slots distance.

As its is given the in the equation that points on the Number line is equal distance so.... 9^11*80/2 = 9^11*40

Now we have to find the distance between A to D - Three slot distance = 3 * 9^11 * 40 = 120 * 9^11
##### General Discussion
Manager
Status: How easy it is?
Joined: 09 Nov 2012
Posts: 89
Location: India
Concentration: Operations, General Management
GMAT 1: 650 Q50 V27
GMAT 2: 710 Q49 V37
GPA: 3.5
WE: Operations (Other)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

03 Sep 2013, 22:54
Bunuel, can you help me with this.

I tried to solve it using Arithmetic Progression.

We are given that E = $$9^13$$, so a+4d= $$9^13$$
and, C = $$9^11$$, so a+3d= $$9^11$$

Solving this we get, a=2$$9^11$$-$$9^13$$
d= {$$9^13$$-$$9^11$$}/2

No distance from A to D is 4a+6d. Substituting the values I am getting negative value.

Anything wrong with this?
Math Expert
Joined: 02 Sep 2009
Posts: 53020
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

04 Sep 2013, 02:16
nitin6305 wrote:
Bunuel, can you help me with this.

I tried to solve it using Arithmetic Progression.

We are given that E = $$9^13$$, so a+4d= $$9^13$$
and, C = $$9^11$$, so a+3d= $$9^11$$

Solving this we get, a=2$$9^11$$-$$9^13$$
d= {$$9^13$$-$$9^11$$}/2

No distance from A to D is 4a+6d. Substituting the values I am getting negative value.

Anything wrong with this?

Since you don't get the correct answer then obviously there is something wrong.

The distance from A to D should be simply 3d.
_________________
Senior Manager
Joined: 13 May 2013
Posts: 421
In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

09 Sep 2013, 08:45
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!
Intern
Joined: 23 Mar 2011
Posts: 40
Location: India
Concentration: Marketing, Operations
Schools: Schulich '16 (A)
GMAT 1: 690 Q48 V36
WE: Operations (Telecommunications)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

09 Sep 2013, 16:26
3
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)
Intern
Joined: 15 Jul 2012
Posts: 39
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

16 Sep 2014, 08:04
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$- I have not understood, can you explain the logic?
Math Expert
Joined: 02 Sep 2009
Posts: 53020
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

16 Sep 2014, 13:06
anu1706 wrote:
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$- I have not understood, can you explain the logic?

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.
_________________
Current Student
Joined: 18 Aug 2014
Posts: 324
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

23 Dec 2015, 12:14
Bunuel wrote:
The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?
_________________

CEO
Joined: 20 Mar 2014
Posts: 2629
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

23 Dec 2015, 12:18
1
redfield wrote:
Bunuel wrote:
The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?

It is getting multiplied by everything.

You are doing 1.5*80*9^11 but now as the answer options are all in the form A*9^11, it is better to keep 9^11 as such as you end up with : \

1.5*80*9^11 = (1.5*80)*9^11 = 120*9^11 .

In multiplication, A*B*C = (A*B)*C or A*(B*C) etc.

Hope this helps.
Manager
Joined: 25 Mar 2013
Posts: 239
Location: United States
Concentration: Entrepreneurship, Marketing
GPA: 3.5
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

06 Jan 2017, 13:11
crackjack wrote:
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

After 9^11(80) I could not think of divide value by 2 and multiply with 3 to get answer

and How The distance between A and D is 1.5 times the distance between C and E, thus it equal to 120∗911

_________________

I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you

Director
Joined: 12 Nov 2016
Posts: 725
Location: United States
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
GPA: 2.66
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

17 May 2017, 05:12
pavan2185 wrote:
Attachment:
The attachment ABCDE.png is no longer available
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

The trap in this question is baiting the test taker to think that these lines represent a series of consistently increasing/decreasing exponents (e.x A= 9^9, B =9^10, C=9^11, D=9^12, E =9^13) with answer choice "A." Yet this is an evenly spaced set ; in other words, if we have say E as 2^5 and C as 2^3 then the distance between those two points is 24 so A cannot be 2^1 because 2^3-24 is -16. More fundamentally, the distance between any two points spaced two letter apart would be 24. In our example, the distance between E and C is

9^13-9^11
(9^2) 9^11- (1) 9^11 - do not forget that there is always an assumed one when subtracting exponents
(81-1) 9^11
(80)9^11

Now the distance between any two lines spaced two letters apart must be (80)9^11 - the distance between A and C must also be (80)9^11 as well as the distance between B and D and D and E; however, the distance between and D is 3 spaces which is 1.5 the distance between C and E or moreover - A and C, C and D , B and D, D and E - conceptually, another way of understanding the problem is also that half of- (80) 9^11 or alternatively (80) 9^11 /2 - would be the distance between two sequential spaces {e.x distance between A, B, or C, B or D,E} so 3 (1/2) (80) 9^11 or (3)(80)9^11/2 would also be another method of calculating the distance. I guess you could also imagine that the spaces between letters in this evenly spaced set form a puzzle piece- so the distance between a set of letters would be the length of that puzzle piece ( example: the distance between A and B would be the length of puzzle piece AB)
Attachments

image1.JPG [ 1.73 MiB | Viewed 5236 times ]

image1.JPG [ 1.73 MiB | Viewed 5234 times ]

Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 4938
Location: United States (CA)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

19 May 2017, 05:23
pavan2185 wrote:
Attachment:
ABCDE.png
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

We can let the space between each pair of consecutive points = n.

Thus, the space from C to E is n + n = 2n. So, we can create the following equation:

9^11 + 2n = 9^13

2n = 9^13 - 9^11

2n = 9^11(9^2 - 1)

2n = 9^11(80)

n = 9^11(40)

Since the distance from A to D = 3n:

3n = 3(9^11)(40) = 120(9^11)

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Retired Moderator
Joined: 19 Mar 2014
Posts: 934
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.5
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

08 Jul 2017, 11:04
pavan2185 wrote:
Attachment:
ABCDE.png
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

As the points are equidistant, lets assume, the distance between one unit = $$x$$

So Distance between C and E $$= 2x$$

$$2x = 9^{13} - 9^{11}$$

$$2x = 9^{11} (9^2 - 1)$$

$$2x = 9^{11} * (81 - 1)$$

$$2x = 9^{11} * 80$$

$$x = 9^{11} * 40$$

As the distance between A and D $$= 3x$$

$$3x = 9^{11} * 40 * 3$$

$$3x = 9^{11} * 120$$

_________________

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475

Manager
Joined: 26 May 2013
Posts: 94
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

21 Aug 2017, 18:31
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: http://gmatclub.com/forum/the-integers- ... 06968.html

Hope it helps.

Hi - I have two questions on this problem.

1) how come C does not equal 3*(9^11)*40

2) why can't you just add C + "one distance" unit = 9^11 + (9^11)*40... to arrive at point D?

I'm unable to reconcile both 1 and 2 here...

Answering my own question here, would appreciate if you could chime in though: the distance between does not equal the distance from zero. C is 9^11 from 0, however we're just interested in calculating the distance between A --> D. The distance from A --> C indeed does equal 80*9^11, and this implies that A is a negative number since 9^11 < (9^11 * 80)
Intern
Joined: 17 Apr 2017
Posts: 11
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

23 Sep 2017, 05:32
crackjack wrote:
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

Hi,

As per this - D = 9^12 and A = 9^9? If yes then the answer should be arrived at by subtracting the two but this is not the case. Any thoughts on where I am wrong?
Math Expert
Joined: 02 Sep 2009
Posts: 53020
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

23 Sep 2017, 06:15
Richak91 wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Hi,

As per this - D = 9^12 and A = 9^9? If yes then the answer should be arrived at by subtracting the two but this is not the case. Any thoughts on where I am wrong?

The distance between two consecutive points is $$40*9^{11}$$, thus:

$$A = -79*9^{11}$$

$$B = -39*9^{11}$$

$$C = 1*9^{11}$$

$$D = 41*9^{11}$$

$$E = 81*9^{11} = 9^{13}$$

Completer solution is here: https://gmatclub.com/forum/in-the-figur ... l#p1263035
_________________
Non-Human User
Joined: 09 Sep 2013
Posts: 9867
Re: In the figure above, points A, B, C, D, and E are evenly spaced along  [#permalink]

### Show Tags

11 Oct 2018, 07:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: In the figure above, points A, B, C, D, and E are evenly spaced along   [#permalink] 11 Oct 2018, 07:27
Display posts from previous: Sort by