It is currently 22 Feb 2018, 20:29

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In the figure above, points A, B, C, D, and E are evenly spaced along

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Manager
Joined: 15 Apr 2013
Posts: 83
Location: India
Concentration: Finance, General Management
Schools: ISB '15
WE: Account Management (Other)
In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

02 Sep 2013, 10:33
4
KUDOS
20
This post was
BOOKMARKED
00:00

Difficulty:

45% (medium)

Question Stats:

62% (01:26) correct 38% (01:13) wrong based on 510 sessions

### HideShow timer Statistics

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3

B. 9^9

C. (120)(9^9)

D. 9^11

E. (120)(9^11)

[Reveal] Spoiler:
Attachment:

ABCDE.png [ 1.41 KiB | Viewed 13905 times ]
[Reveal] Spoiler: OA
Intern
Joined: 15 Oct 2012
Posts: 25
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

02 Sep 2013, 11:18
6
KUDOS
5
This post was
BOOKMARKED
First find out the Distance Between E and C i.e 9^13 - 9^11 = 9^11(9^2 - 1) = 9^11 * 80

Now this (9^11 * 80) is the distance between C to D and D to E i.e Two Slots distance.

As its is given the in the equation that points on the Number line is equal distance so.... 9^11*80/2 = 9^11*40

Now we have to find the distance between A to D - Three slot distance = 3 * 9^11 * 40 = 120 * 9^11
Math Expert
Joined: 02 Sep 2009
Posts: 43887
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

02 Sep 2013, 12:48
5
KUDOS
Expert's post
4
This post was
BOOKMARKED

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.
_________________
Manager
Status: How easy it is?
Joined: 09 Nov 2012
Posts: 119
Location: India
Concentration: Operations, General Management
GMAT 1: 650 Q50 V27
GMAT 2: 710 Q49 V37
GPA: 3.5
WE: Operations (Other)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

03 Sep 2013, 22:54
Bunuel, can you help me with this.

I tried to solve it using Arithmetic Progression.

We are given that E = $$9^13$$, so a+4d= $$9^13$$
and, C = $$9^11$$, so a+3d= $$9^11$$

Solving this we get, a=2$$9^11$$-$$9^13$$
d= {$$9^13$$-$$9^11$$}/2

No distance from A to D is 4a+6d. Substituting the values I am getting negative value.

Anything wrong with this?
Math Expert
Joined: 02 Sep 2009
Posts: 43887
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

04 Sep 2013, 02:16
nitin6305 wrote:
Bunuel, can you help me with this.

I tried to solve it using Arithmetic Progression.

We are given that E = $$9^13$$, so a+4d= $$9^13$$
and, C = $$9^11$$, so a+3d= $$9^11$$

Solving this we get, a=2$$9^11$$-$$9^13$$
d= {$$9^13$$-$$9^11$$}/2

No distance from A to D is 4a+6d. Substituting the values I am getting negative value.

Anything wrong with this?

Since you don't get the correct answer then obviously there is something wrong.

The distance from A to D should be simply 3d.
_________________
Senior Manager
Joined: 13 May 2013
Posts: 456
In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

09 Sep 2013, 08:45
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!
Intern
Joined: 23 Mar 2011
Posts: 40
Location: India
Concentration: Marketing, Operations
Schools: Schulich '16 (A)
GMAT 1: 690 Q48 V36
WE: Operations (Telecommunications)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

09 Sep 2013, 16:26
3
KUDOS
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)
Intern
Joined: 15 Jul 2012
Posts: 41
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

16 Sep 2014, 08:04
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$- I have not understood, can you explain the logic?
Math Expert
Joined: 02 Sep 2009
Posts: 43887
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

16 Sep 2014, 13:06
anu1706 wrote:
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: the-integers-a-b-c-and-d-shown-on-the-number-line-above-a-106968.html

Hope it helps.

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$- I have not understood, can you explain the logic?

The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.
_________________
Senior Manager
Joined: 18 Aug 2014
Posts: 302
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

23 Dec 2015, 12:14
Bunuel wrote:
The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?
_________________

Current Student
Joined: 20 Mar 2014
Posts: 2683
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

23 Dec 2015, 12:18
1
KUDOS
redfield wrote:
Bunuel wrote:
The distance between A and D is 3 units and the distance between C and E is 2 units, hence the distance between A and D is 3/2=1.5 times the distance between C and E.

Hope it's clear.

If 2 units if 9^11 * 80 and you want 3 units, why do you only multiply the "80" by 1.5 but not also the "9^11"?

It is getting multiplied by everything.

You are doing 1.5*80*9^11 but now as the answer options are all in the form A*9^11, it is better to keep 9^11 as such as you end up with : \

1.5*80*9^11 = (1.5*80)*9^11 = 120*9^11 .

In multiplication, A*B*C = (A*B)*C or A*(B*C) etc.

Hope this helps.
Senior Manager
Joined: 25 Mar 2013
Posts: 272
Location: United States
Concentration: Entrepreneurship, Marketing
GPA: 3.5
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

06 Jan 2017, 13:11
crackjack wrote:
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

After 9^11(80) I could not think of divide value by 2 and multiply with 3 to get answer

and How The distance between A and D is 1.5 times the distance between C and E, thus it equal to 120∗911

_________________

I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you

Director
Joined: 12 Nov 2016
Posts: 790
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

17 May 2017, 05:12
pavan2185 wrote:
Attachment:
The attachment ABCDE.png is no longer available
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Spoiler Alert: Veritasprep Mock test

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

The trap in this question is baiting the test taker to think that these lines represent a series of consistently increasing/decreasing exponents (e.x A= 9^9, B =9^10, C=9^11, D=9^12, E =9^13) with answer choice "A." Yet this is an evenly spaced set ; in other words, if we have say E as 2^5 and C as 2^3 then the distance between those two points is 24 so A cannot be 2^1 because 2^3-24 is -16. More fundamentally, the distance between any two points spaced two letter apart would be 24. In our example, the distance between E and C is

9^13-9^11
(9^2) 9^11- (1) 9^11 - do not forget that there is always an assumed one when subtracting exponents
(81-1) 9^11
(80)9^11

Now the distance between any two lines spaced two letters apart must be (80)9^11 - the distance between A and C must also be (80)9^11 as well as the distance between B and D and D and E; however, the distance between and D is 3 spaces which is 1.5 the distance between C and E or moreover - A and C, C and D , B and D, D and E - conceptually, another way of understanding the problem is also that half of- (80) 9^11 or alternatively (80) 9^11 /2 - would be the distance between two sequential spaces {e.x distance between A, B, or C, B or D,E} so 3 (1/2) (80) 9^11 or (3)(80)9^11/2 would also be another method of calculating the distance. I guess you could also imagine that the spaces between letters in this evenly spaced set form a puzzle piece- so the distance between a set of letters would be the length of that puzzle piece ( example: the distance between A and B would be the length of puzzle piece AB)
Attachments

image1.JPG [ 1.73 MiB | Viewed 3381 times ]

image1.JPG [ 1.73 MiB | Viewed 3376 times ]

Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 2192
Location: United States (CA)
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

19 May 2017, 05:23
Expert's post
1
This post was
BOOKMARKED
pavan2185 wrote:
Attachment:
ABCDE.png
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

We can let the space between each pair of consecutive points = n.

Thus, the space from C to E is n + n = 2n. So, we can create the following equation:

9^11 + 2n = 9^13

2n = 9^13 - 9^11

2n = 9^11(9^2 - 1)

2n = 9^11(80)

n = 9^11(40)

Since the distance from A to D = 3n:

3n = 3(9^11)(40) = 120(9^11)

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Verbal Forum Moderator
Joined: 19 Mar 2014
Posts: 992
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.5
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

08 Jul 2017, 11:04
pavan2185 wrote:
Attachment:
ABCDE.png
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Spoiler Alert: Veritasprep Mock test

I could not understand how to solve this question. Did not undertsand theofficial explanation also.

As the points are equidistant, lets assume, the distance between one unit = $$x$$

So Distance between C and E $$= 2x$$

$$2x = 9^{13} - 9^{11}$$

$$2x = 9^{11} (9^2 - 1)$$

$$2x = 9^{11} * (81 - 1)$$

$$2x = 9^{11} * 80$$

$$x = 9^{11} * 40$$

As the distance between A and D $$= 3x$$

$$3x = 9^{11} * 40 * 3$$

$$3x = 9^{11} * 120$$

Hence, Answer is E
_________________

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475

Manager
Joined: 26 May 2013
Posts: 97
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

21 Aug 2017, 18:31
Bunuel wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

The distance between E and C is $$9^{13}-9^{11}=9^{11}*(9^2-1)=80*9^{11}$$;

The distance between A and D is 1.5 times the distance between C and E, thus it equal to $$120*9^{11}$$

Similar question to practice:
Quote:

The integers A, B, C, and D shown on the number line above are all equally spaced. If C and D are equal to 5^12 and 5^13, respectively, what is the value of A?

A. 5^11
B. 5^10
C. -5^12
D. (-7)5^12
E. (-12)5^13

Discussed here: http://gmatclub.com/forum/the-integers- ... 06968.html

Hope it helps.

Hi - I have two questions on this problem.

1) how come C does not equal 3*(9^11)*40

2) why can't you just add C + "one distance" unit = 9^11 + (9^11)*40... to arrive at point D?

I'm unable to reconcile both 1 and 2 here...

Answering my own question here, would appreciate if you could chime in though: the distance between does not equal the distance from zero. C is 9^11 from 0, however we're just interested in calculating the distance between A --> D. The distance from A --> C indeed does equal 80*9^11, and this implies that A is a negative number since 9^11 < (9^11 * 80)
Intern
Joined: 17 Apr 2017
Posts: 13
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

23 Sep 2017, 05:32
crackjack wrote:
WholeLottaLove wrote:
In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

If E = 9^13 and C = 9^11 and all points are evenly spaced, then D = 9^12 and A = 9^9.

9^12 - 9^9 = 9^9*(9^3 - 1) = 9^9*(80)

I don't understand why the 1.5*80 comes into play. If we know that point D = 9^12 and A = 9^9 then why isn't this a simply subtraction problem?

In other words, let's pretend E=60 and C=40, so D = 50, B = 30, A = 20. The distance between D and A is simply 30. It happens to be 1.5 times the distance between E and C (which is 20) but we don't then multiply 30 by 1.5 to get the distance between D and A.

Any help would be greatly appreciated!

Thanks!

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Taking an example of 2^1, 2^2, 2^3, 2^4, 2^5 i.e 2,4,8,16,32 can not be equally spaced as the distance keeps on increasing between each subsequent point of 2,4,8,16,32. Thus to find the distance between two closest individual points, subtract C from E and then divide the result by 2 i.e.

Let us first find the distance between C and E --
(9^13 - 9^11) =9^11 (9^2-1) = 9^11(81-1)=9^11(80)

Now divide this by 2 to find distance between any two closest points i.e between A&B or B&C or C&D or D&E =9^11(40)

Multiply this result by 3 to find distance between A & D =9^11(120)

Hi,

As per this - D = 9^12 and A = 9^9? If yes then the answer should be arrived at by subtracting the two but this is not the case. Any thoughts on where I am wrong?
Math Expert
Joined: 02 Sep 2009
Posts: 43887
Re: In the figure above, points A, B, C, D, and E are evenly spaced along [#permalink]

### Show Tags

23 Sep 2017, 06:15
Richak91 wrote:

In the figure above, points A, B, C, D, and E are evenly spaced along the number line. If E = 9^13 and C = 9^11, what is the distance from point A to point D?

A. 9^3
B. 9^9
C. (120)(9^9)
D. 9^11
E. (120)(9^11)

Hi,

As per this - D = 9^12 and A = 9^9? If yes then the answer should be arrived at by subtracting the two but this is not the case. Any thoughts on where I am wrong?

The distance between two consecutive points is $$40*9^{11}$$, thus:

$$A = -79*9^{11}$$

$$B = -39*9^{11}$$

$$C = 1*9^{11}$$

$$D = 41*9^{11}$$

$$E = 81*9^{11} = 9^{13}$$

Completer solution is here: https://gmatclub.com/forum/in-the-figur ... l#p1263035
_________________
Re: In the figure above, points A, B, C, D, and E are evenly spaced along   [#permalink] 23 Sep 2017, 06:15
Display posts from previous: Sort by

# In the figure above, points A, B, C, D, and E are evenly spaced along

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.