|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
09 Mar 2016, 13:32
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
48% (02:22) correct
52%
(02:24)
wrong
based on 149
sessions
History
Date
Time
Result
Not Attempted Yet
09 Mar 2016, 17:38
Kudos
Bookmarks
Is |a|>|b|
Statement 1:
\(\frac{1}{(a-b)} > \frac{1}{(b-a)}\)
Implies \(\frac{1}{(a-b)} - \frac{1}{(b-a)} > 0\)
i.e.\(\frac{2}{(a-b)} > 0\). This implies \(a-b > 0\) or a > b.
If a = 2 and b = -8; we have a No for the question.
Reversing values i.e. if a = 8 and b = -2 we have a Yes for the question.
Hence not sufficient.
Statement 2:
a + b < 0
Let a = -2 and b = -8; we have a + b = -10 <0 and |a| < |b|
Similarly, if a =-8 and b=-2; we have a+b = -10 <0 and |a|>|b|. Once again insufficient.
Combining statements:
i.e. a + b <0 and a - b>0 we can infer b<0. and a > b. This means that a is always to the right of b on the number line and its range varies between b and -b.
This means the question will always make the answer to the question stem NO.
Answer C.
Please do let me know if this approach is correct.
Statement 1:
\(\frac{1}{(a-b)} > \frac{1}{(b-a)}\)
Implies \(\frac{1}{(a-b)} - \frac{1}{(b-a)} > 0\)
i.e.\(\frac{2}{(a-b)} > 0\). This implies \(a-b > 0\) or a > b.
If a = 2 and b = -8; we have a No for the question.
Reversing values i.e. if a = 8 and b = -2 we have a Yes for the question.
Hence not sufficient.
Statement 2:
a + b < 0
Let a = -2 and b = -8; we have a + b = -10 <0 and |a| < |b|
Similarly, if a =-8 and b=-2; we have a+b = -10 <0 and |a|>|b|. Once again insufficient.
Combining statements:
i.e. a + b <0 and a - b>0 we can infer b<0. and a > b. This means that a is always to the right of b on the number line and its range varies between b and -b.
This means the question will always make the answer to the question stem NO.
Answer C.
Please do let me know if this approach is correct.
11 Mar 2016, 10:05
Kudos
Bookmarks
Bunuel
statement (1)
1/(a+b)>1/(b-a)
=( b-a-a+b)/(a-b)(b-a) > 0
= 2/(a-b)>0-----> a-b>0
as we dont know the sign of a & b so IaI can be > or < IbI
so insuff.
statement(2)
a+b<0
again as we dont know the sign of a & b so IaI can be > or < IbI
eg:- a=-12 b=-3 or vice versa.
combining
(a-b)>0
(a+b)<0
subtract both
a-b-a-b>0
-2b>0
b<0.
we don't know about sign/distance from 0, of a
so insuff
Ans E
