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Bunuel
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Is a > b? (1) 6 + a/3 = b 8 (2) 9b^2 16 29 Apr 2016, 02:47
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55% (hard)

Question Stats:

60% (02:25) correct 40% (02:03) wrong based on 63 sessions

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Is \(a > b\)?


(1) \(−6 + \frac{a}{3} = b − 8\)

(2) \(9b^2 ≥ 16\)
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E
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Balajikarthick1990
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Is a > b? (1) 6 + a/3 = b 8 (2) 9b^2 16 30 Apr 2016, 04:29
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Bunuel
Is a > b?

(1) −6 + a/3 = b − 8
(2) 9b^2 ≥ 16
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I will go with C

i took b=2 and -2 and substituted in Eq1 ---- for both cases it resulted in NO
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Is a > b? (1) 6 + a/3 = b 8 (2) 9b^2 16 30 Apr 2016, 06:12
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Balajikarthick1990
Bunuel
Is a > b?

(1) −6 + a/3 = b − 8
(2) 9b^2 ≥ 16

I will go with C

i took b=2 and -2 and substituted in Eq1 ---- for both cases it resulted in NO
Show more

Hi balaji don't take two values and if they give you answer YES or NO, believe it to be suff, there may be other pair which may give you opposite answer..
Always solve equation when required..

lets see the statements-


(1) \(−6 + \frac{a}{3} = b − 8\)
-18+a=3b-24..
a-3b= -6...
(i) a>b if b>3
(ii) a<b if b<3
(iii) a=b if b=3
Insuff

(2) \(9b^2 ≥ 16\)
\(b^2≥ \frac{16}{9}\)........\(|b|≥\frac{4}{3}\)
So, \(b≥ \frac{4}{3}\) or \(b<= - \frac{4}{3}\)..
Again nothing about 'a'..
Insuff

Combined..
\(b<= - \frac{4}{3}\), then a<b
\(b>3≥ \frac{4}{3}\), then a>b
Insuff
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Balajikarthick1990
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Is a > b? (1) 6 + a/3 = b 8 (2) 9b^2 16 30 Apr 2016, 06:23
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chetan2u
Balajikarthick1990
Bunuel
Is a > b?

(1) −6 + a/3 = b − 8
(2) 9b^2 ≥ 16

I will go with C

i took b=2 and -2 and substituted in Eq1 ---- for both cases it resulted in NO

Hi balaji don't take two values and if they give you answer YES or NO, believe it to be suff, there may be other pair which may give you opposite answer..
Always solve equation when required..

lets see the statements-


(1) −6 + a/3 = b − 8
-18+a=3b-24..
a-3b= -6...
a>b if both are +ive and b>3 otherwise a<b ..
a<b if both are -ive
Insuff

(2) \(9b^2 ≥ 16\)
b^2≥ 16/9..
so b≥ 4/3 or b<= - 4/3..
again nothing about 'a'..
Insuff

Combined..
b can take both -ive and +ive values and a > or < will depend on that..
Insuff
E
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Sure sir...its been a bad day to me...making lot of mistakes
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Is a > b? (1) 6 + a/3 = b 8 (2) 9b^2 16 25 Mar 2022, 10:37
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