Is k odd? (1) 6k is an even number (2) 7k is an odd number

Question: Is k = Odd?

Statement 1: 6k is an even number

@k = 1/3, 6k is even but k is not even
@k = 2, 6k is even but k is even

NOT SUFFICIENT

Statement 2: 7k is an Odd number

@k = 1/7, 7k is odd but k is not even
@k = 1, 7k is odd but k is not even

Alternatively: k=odd/7. and odd / odd = ODD or a non integer but Never an even integer
hence

NOT SUFFICIENT


COmbining the statements

Denominator of k must be a factor of 6 as well as a factor of 7 if it's in fraction i.e. HCF of 6 and 7 which is 1

i.e. k MUST be ODD

SUFFICIENT

Answer: Option C

This question is missing the options. Kindly check.

Hi,

This is a data sufficiency question. Options for DS questions are always the same and usually omitted on the site.

The data sufficiency problem consists of a question and two statements, labeled (1) and (2), in which certain data are given. You have to decide whether the data given in the statements are sufficient for answering the question. Using the data given in the statements, plus your knowledge of mathematics and everyday facts (such as the number of days in July or the meaning of the word counterclockwise), you must indicate whether—

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.

I suggest you to go through the following post ALL YOU NEED FOR QUANT.

Hope this helps.

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