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What about n = 0 OR 2?
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RayanCHB
for statement 1 : n could be equal to 2 so n x (n-2) is not divisible by 4 and yet n is not odd.

statements 1 + 2 : n is definitely odd hence I believe it should be C.
exactly. it should be c

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RayanCHB
for statement 1 : n could be equal to 2 so n x (n-2) is not divisible by 4 and yet n is not odd.

statements 1 + 2 : n is definitely odd hence I believe it should be C.
exactly. it should be c

Posted from my mobile device

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RayanCHB
for statement 1 : n could be equal to 2 so n x (n-2) is not divisible by 4 and yet n is not odd.

statements 1 + 2 : n is definitely odd hence I believe it should be C.

if n=2, n x (n-2) =2*0=0, 0 is DIVISIBLE by 4, resulting 0 as quotient
Zero is divisible by every integer, and so zero is a multiple of all numbers (x*0 = 0, so 0 is a multiple of any number, x)
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HarshiSingh
What about n = 0 OR 2?


Is the integer n odd?

(1) n^2 - 2n is not a multiple of 4.
(2) n is a multiple of 3.

Statement 1-
If n=0, n*(n-2)=0*-2 =0 which is multiple of 4,
If n=2, n*(n-2)=2*0 =0 which is multiple of 4

Zero is divisible by every integer, and so zero is a multiple of all numbers (x*0 = 0, so 0 is a multiple of any number, x)

If n is even(including n=0 or 2), n-2 will also be even, and so it will be divisible for 4
but if n is odd, n-2 will be odd as well, and its product will not be divisible by 4.

Only second case works for Statement1, n=odd, so anwer is YES always

A is the answer
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