Last visit was: 20 Nov 2025, 05:12 It is currently 20 Nov 2025, 05:12
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
KaranB1
Joined: 17 Aug 2018
Last visit: 22 Oct 2025
Posts: 121
Own Kudos:
190
 [16]
Given Kudos: 153
Location: India
Schools: IIMA WBS '22
GMAT 1: 640 Q46 V32
GMAT 2: 710 Q49 V38
Products:
Schools: IIMA WBS '22
GMAT 2: 710 Q49 V38
Posts: 121
Kudos: 190
 [16]
2
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 19 Nov 2025
Posts: 4,145
Own Kudos:
10,990
 [15]
Given Kudos: 99
Expert
Expert reply
Posts: 4,145
Kudos: 10,990
 [15]
10
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
KaranB1
Joined: 17 Aug 2018
Last visit: 22 Oct 2025
Posts: 121
Own Kudos:
190
 [7]
Given Kudos: 153
Location: India
Schools: IIMA WBS '22
GMAT 1: 640 Q46 V32
GMAT 2: 710 Q49 V38
Products:
Schools: IIMA WBS '22
GMAT 2: 710 Q49 V38
Posts: 121
Kudos: 190
 [7]
3
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
General Discussion
User avatar
aj3001
Joined: 14 Sep 2016
Last visit: 18 Dec 2021
Posts: 28
Own Kudos:
Given Kudos: 26
Location: India
GPA: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can someone please elaborate about the part wherein we ascertain x>20..?

Posted from my mobile device
User avatar
keshavmishra
Joined: 13 Oct 2012
Last visit: 23 Nov 2020
Posts: 27
Own Kudos:
Given Kudos: 56
Location: India
Schools: IIMA PGPX'22
WE:Operations (Manufacturing)
Schools: IIMA PGPX'22
Posts: 27
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
|x - 10| > |x - 30| ???

essentially question means distance b/w a point x and 10 is greater than distance b/w x and 30. => x is closer to 30 than it is to 10. For that to be true, x needs to be greater than the midpoint of 10 and 30, so x needs to be greater than 20.
So question can be inferred as is x > 20?
statement 1 - x can be less that 20 & greater than 20. Not sufficient (cancel DA)
Statement 2 states x>25. in all cases sufficient

Answer B

Posted from my mobile device
avatar
embaiii
Joined: 09 Sep 2020
Last visit: 01 Jul 2025
Posts: 3
Own Kudos:
4
 [2]
Given Kudos: 11
Posts: 3
Kudos: 4
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is |x-10| > |x-30|

Here's mathematical try
Square both side (since both sides are positive)
(x-10)^2 > (x-30)^2
(x^2+100-20x)>(x^2+900-60x)
(60x-20x)>(900-100)
40x>800
x>20

Hence, only St. 2 satisfy i.e x>25
User avatar
a191291r
Joined: 20 Dec 2023
Last visit: 22 Jul 2025
Posts: 40
Own Kudos:
42
 [1]
Given Kudos: 57
Location: India
Concentration: Finance, Leadership
GMAT Focus 1: 615 Q82 V81 DI79
GMAT Focus 2: 665 Q85 V83 DI81
WE:Operations (Other)
GMAT Focus 2: 665 Q85 V83 DI81
Posts: 40
Kudos: 42
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
 
aj3001
Can someone please elaborate about the part wherein we ascertain x>20..?

Posted from my mobile device
 
  • Draw a number line and mark the points 0, 10 and 30 on the number line.
  • Pick any arbitrary point on the number line and mark it as x.
  • The distance of this point x from point 10 would be |x - 10| and distance of this point x from point 30 would be |x - 30|.
Check Statement 1:
\(x>10\)
  • The arbitrary point x can be anywhere on right side of the 10
  • If point x lies between 10 and the midpoint of 10 and 30 (i.e., 20), we can confidently say |x-10| < |10-30|
  • If point x lies anywhere on the right side of this midpoint (i.e, 20), we can confidently say |x-10| > |10-30|
Therefore, insufficient.

Check Statement 2:
\(x>25\)
  • The arbitrary point x lies anywhere on right side of the 25
  • Earlier, we have deduced that for all points on right side of 20, |x-10| > |x-30|
Therefore, sufficient.  ­
User avatar
AnuK2222
Joined: 17 Sep 2023
Last visit: 13 Oct 2025
Posts: 124
Own Kudos:
104
 [1]
Given Kudos: 845
Location: India
Schools: ISB '25
GPA: 3.8
WE:Project Management (Pharmaceuticals and Biotech)
Schools: ISB '25
Posts: 124
Kudos: 104
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
a191291r

aj3001
Can someone please elaborate about the part wherein we ascertain x>20..?

Posted from my mobile device
 

  • Draw a number line and mark the points 0, 10 and 30 on the number line.
  • Pick any arbitrary point on the number line and mark it as x.
  • The distance of this point x from point 10 would be |x - 10| and distance of this point x from point 30 would be |x - 30|.
Check Statement 1:
\(x>10\)

  • The arbitrary point x can be anywhere on right side of the 10
  • If point x lies between 10 and the midpoint of 10 and 30 (i.e., 20), we can confidently say |x-10| < |10-30|
  • If point x lies anywhere on the right side of this midpoint (i.e, 20), we can confidently say |x-10| > |10-30|
Therefore, insufficient.

Check Statement 2:
\(x>25\)

  • The arbitrary point x lies anywhere on right side of the 25
  • Earlier, we have deduced that for all points on right side of 20, |x-10| > |x-30|
Therefore, sufficient.  ­
­Great explaination, I tend to struggle whenever ineuqalities and modulus are together in any question. this is neat approach
User avatar
a191291r
Joined: 20 Dec 2023
Last visit: 22 Jul 2025
Posts: 40
Own Kudos:
Given Kudos: 57
Location: India
Concentration: Finance, Leadership
GMAT Focus 1: 615 Q82 V81 DI79
GMAT Focus 2: 665 Q85 V83 DI81
WE:Operations (Other)
GMAT Focus 2: 665 Q85 V83 DI81
Posts: 40
Kudos: 42
Kudos
Add Kudos
Bookmarks
Bookmark this Post
 
AnuK2222

a191291r

aj3001
Can someone please elaborate about the part wherein we ascertain x>20..?

Posted from my mobile device
 



  • Draw a number line and mark the points 0, 10 and 30 on the number line.
  • Pick any arbitrary point on the number line and mark it as x.
  • The distance of this point x from point 10 would be |x - 10| and distance of this point x from point 30 would be |x - 30|.
Check Statement 1:
\(x>10\)



  • The arbitrary point x can be anywhere on right side of the 10
  • If point x lies between 10 and the midpoint of 10 and 30 (i.e., 20), we can confidently say |x-10| < |10-30|
  • If point x lies anywhere on the right side of this midpoint (i.e, 20), we can confidently say |x-10| > |10-30|
Therefore, insufficient.

Check Statement 2:
\(x>25\)



  • The arbitrary point x lies anywhere on right side of the 25
  • Earlier, we have deduced that for all points on right side of 20, |x-10| > |x-30|
Therefore, sufficient.  ­
­Great explaination, I tend to struggle whenever ineuqalities and modulus are together in any question. this is neat approach
­Same! I struggle a lot with moduli and inequalities as well. Youtube playlists of Khan Academy and PatrickJMT on Linear inequalities helped me a lot. Just type it in the search box on Youtube. I could share the links, but I am new to this forum so I am not allowed to post urls.
User avatar
sayan640
Joined: 29 Oct 2015
Last visit: 10 Nov 2025
Posts: 1,179
Own Kudos:
Given Kudos: 783
GMAT 1: 570 Q42 V28
Products:
GMAT 1: 570 Q42 V28
Posts: 1,179
Kudos: 813
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Easiest approach:-

Whenever you see |a|=|b| ,
either a=b or a=-b ;
Apply this here ,
Either x -10 > x-30 ( ignore as -10 is always greater than-30)
or x -10 > - (x-30)
x -10 > -x + 30
x> 20
Hence the question asks
is x >20 ?

Option A does not give a definite answer as x can be 15 or 25 .
Option B does give a definite answer as x is greater than 25 means it will obviously be greater than 20.
B is the answer.

Posted from my mobile device
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,598
Own Kudos:
Posts: 38,598
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105414 posts
496 posts