carcass wrote:
Last year \(\frac{3}{5}\) of the members of a certain club were males. This year the members of the club include all the members from last year plus some new members. Is the fraction of the members of the club who are males greater this year than last year?
Last YearTotal Members -> T
Male Members -> \(\frac{3}{5}\)*T => In other words M : T = 3 : 5
This YearTotal Members -> T + N
New Male Members -> m
Is \(\frac{(M + m)}{(T+N)}\) > \(\frac{3}{5}\) ?
Quote:
(1) More than half of the new members are male.
(2) The number of members of the club this year is \(\frac{6}{5}\) the number of members last year.
1) m > 0.5N
N = 10, m = 6,7,8..
Ratio will change according to the number of males added
=> Let's say T = 10 => M = 6
and N = 10 => m = 6,7,8..
If m = 6
=> \(\frac{(M + m)}{(T+N)}\) = \(\frac{3}{5}\)
(Ratio is the same)If m = 7
=> \(\frac{(M + m)}{(T+N)}\) = \(\frac{7}{10}\)
(Ratio is greater)Hence, Insufficient.
2) T + N = 1.2T
=> N = 0.2T
We don't know the value of N or T. Plus, we cannot derive the values of M and m.
Insufficient.
1+2)
We gain no additional information, so we still don't know the value of N,T,M or m.
Insufficient.
E is the answer.
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