Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 12 May 2011
Posts: 17
Location: london
Schools: cambridge, oxford

List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
02 May 2012, 00:27
21
This post received KUDOS
219
This post was BOOKMARKED
Question Stats:
38% (02:09) correct 62% (02:14) wrong based on 2146 sessions
HideShow timer Statistics
List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E  S ? I. 16 II. 6 III. 10 A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III
Official Answer and Stats are available only to registered users. Register/ Login.



Intern
Joined: 25 Apr 2012
Posts: 15

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
02 May 2012, 01:04
7
This post received KUDOS
10
This post was BOOKMARKED
First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)20(1) = (sum of all 30 integer parts)10 Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4 ES ranges between (ESmax) to (ESmin) = 36 to 14IMO, the answer option " A" is correct, as 16 only lies in this range.
_________________
Ravi Sankar Vemuri



Intern
Joined: 12 May 2011
Posts: 17
Location: london
Schools: cambridge, oxford

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
02 May 2012, 04:07
2
This post was BOOKMARKED
vsrsankar wrote: First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)20(1) = (sum of all 30 integer parts)10
Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4 ES ranges between (ESmax) to (ESmin) = 36 to 14
IMO, the answer option "A" is correct, as 16 only lies in this range. The answer I gave is the official guide answer. Plus I dont understand how you chose 0.8 and 0.9, can you elaborate on that? also the sum of E , shouldnt it be 10 ( x) +20(y) ....instead of minus as you indicated above. Perhaps I am missing something, and would appreciate further clarification. thanks Shamanth



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7960
Location: Pune, India

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
02 May 2012, 07:13
57
This post received KUDOS
Expert's post
58
This post was BOOKMARKED
shamanth25 wrote: List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E  S ?
I. 16 II. 6 III. 10
A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III
what is the best way to solve this question.
many thanks S This is how I would solve it: Even tenth digit  Round up  10 numbers Odd tenth digit  Round down  20 numbers E  S can take many values so how do we figure which ones it cannot take? We need to find the range of E  S  the minimum value it can take and the maximum value it can take. Minimum value of E  S => E is much less than S. How do we make E much less than S? By doing 2 things: 1. When I round up, the difference between actual and estimate should be little. Say the numbers are something like 3.8999999 (very close to 3.9) and they will be rounded up to 4 i.e. the estimate gains 0.1 per number. Since there are 10 even tenth digit numbers, the estimate will be apprx .1*10 = 1 more than actual 2. When I round down, the difference between actual and estimate should be huge. Say the numbers are something like 3.999999 (very close to 4) and they will be rounded down to 3 i.e. the estimate loses apprx 1 per number. Since there are 20 such numbers, the estimate is 1*20 = 20 less than actual. Overall, the estimate will be apprx 20  1 = 19 less than actual E  S = 19 Maximum value of E  S => E is much greater than S. How do we make E much greater than S? By doing 2 things: 1. When we round up, the difference between actual and estimate should be very high. Say the numbers are something like 3.000001 (very close to 3) and they will be rounded up to 4 i.e. the estimate gains 1 per number. Since there are 10 even tenth digit numbers, the estimate will be apprx 1*10 = 10 more than actual 2. When we round down, the difference between actual and estimate should be very little. Say the numbers are 3.1. They will be rounded down to 3 i.e. the estimate loses apprx 0.1 per number. Since there are 20 such numbers, the estimate is 0.1*20 = 2 less than actual. Maximum value of E  S = 10  2 = 8 So 10 cannot be the value of E  S.
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Status: Preparing myself to break the sound( 700 )barrier!
Affiliations: IFC  Business Edge, Bangladesh Enterprise Institute
Joined: 15 Feb 2011
Posts: 206

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
30 May 2012, 16:45
45
This post received KUDOS
28
This post was BOOKMARKED
IMO, the best solution is shown by M Dabral of GMAT Quantum in one of its video explanations. Here is the link: http://www.gmatquantum.com/og13/218pro ... ition.htmlAlthough NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet.



Manager
Joined: 12 May 2012
Posts: 79
Location: India
Concentration: General Management, Operations
GMAT 1: 650 Q51 V25 GMAT 2: 730 Q50 V38
GPA: 4
WE: General Management (Transportation)

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
31 May 2012, 03:30
2
This post received KUDOS
1
This post was BOOKMARKED
Schawjibb wrote: IMO, the best solution is shown by M Dabral of GMAT Quantum in one of its video explanations. Here is the link: http://www.gmatquantum.com/og13/218pro ... ition.htmlAlthough NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet. good one when you consider in exam conditions



MBA Section Director
Joined: 19 Mar 2012
Posts: 4835
Location: India
GPA: 3.8
WE: Marketing (NonProfit and Government)

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
30 Jul 2012, 23:11
33
This post received KUDOS
Expert's post
28
This post was BOOKMARKED
Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34 ES min = 40  56 = 16 ES max = 40  34 = 6 Thus, the min/max of E is 16 and 6, so I , II apply. For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III.
_________________
Have an MBA application Question? ASK ME ANYTHING!
My Stuff: Four Years to 760  MBA Trends for Indian Applicants
My GMAT Resources V30V40: How to do it!  GMATPrep SC  GMATPrep CR  GMATPrep RC  Critical Reasoning Megathread  CR: Numbers and Statistics  CR: Weaken  CR: Strengthen  CR: Assumption  SC: Modifier  SC: Meaning  SC: SV Agreement  RC: Primary Purpose  PS/DS: Numbers and Inequalities  PS/DS: Combinatorics and Coordinates
My MBA Resources Everything about the MBA Application  OverRepresented MBA woes  Fit Vs Rankings  Low GPA: What you can do  Letter of Recommendation: The Guide  Indian B Schools accepting GMAT score  Why MBA?
My Reviews Veritas Prep Live Online



Intern
Joined: 25 Oct 2012
Posts: 6

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
19 Dec 2012, 02:49
shamanth25 wrote: vsrsankar wrote: First let us find the value of E: "1/3 of the decimals in T have a tenths digit that is even" => 10 numbers have an even tenths digit and remaining 20 numbers have an odd tenths digit. => E = (sum of all 30 integer parts) +10(1)20(1) = (sum of all 30 integer parts)10
Now let us come to "S": The maximum possible value of S occurs when ten numbers have '8' as tenths digit and remaining 20 numbers have '9' as tenths digit. Smax = (sum of all 30 integer parts) +10(0.8)+20(0.9) = (sum of all 30 integer parts)+26 The minimum possible value of S occurs when ten numbers have '2' as tenth digit and remaining 20 numbers have '1' as tenth digit. Smin = (sum of all 30 integer parts) +10(0.2)+20(0.1) = (sum of all 30 integer parts)+4 ES ranges between (ESmax) to (ESmin) = 36 to 14
IMO, the answer option "A" is correct, as 16 only lies in this range. The answer I gave is the official guide answer. Plus I dont understand how you chose 0.8 and 0.9, can you elaborate on that? also the sum of E , shouldnt it be 10 ( x) +20(y) ....instead of minus as you indicated above. Perhaps I am missing something, and would appreciate further clarification. thanks Shamanth I am not sure whether you´ll still need this explanation of how the values of 0.8 an 0.9 account into the equation, but I had the same question after I realized that 0.8 is the highest even value the decimals can have (smallest even is 0.2) and 0.9 is the highest odd value the decimal can have (smallest odd is 0.1). By using these figures in the equation one will be able to compute for highest /lowest possible value At leat thats how I understood it



Manager
Joined: 07 Jan 2010
Posts: 143
Location: So. CA
WE 1: 2 IT
WE 2: 4 Software Analyst

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
23 Mar 2013, 12:00
souvik101990 wrote: Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34
ES min = 40  56 = 16 ES max = 40  34 = 6 Thus, the min/max of E is 16 and 6, so I , II apply.
For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III. To clarify, when you got E = 40 1.xxx rounded up, 2 x 10 (even) = 20 1.xxx rounded down, 1 x 20 (odd) = 20 is that correct?



Manager
Joined: 07 Feb 2011
Posts: 105

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
25 Mar 2013, 03:00
3
This post received KUDOS
Damn this is OG. Seems fair once I read the solution but God forbid I get a problem like this on a test XD Key Deduction is to figure out this is a range problem and how to min and max like Karishma said
_________________
We appreciate your kudos'



GMAT Tutor
Joined: 15 Nov 2013
Posts: 59

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
15 Nov 2013, 03:27
38
This post received KUDOS
Expert's post
37
This post was BOOKMARKED
Ok, so I don't normally post here, but one of my private tutoring students pointed me to this thread. So yeah, there are a lot of words in this problem, and it looks complicated. And if you actually start thinking about "E" and "S" separately  as most people on this thread seem to be doing  then it becomes quite complicated indeed. But ... we don't care about E, and we don't care about S. We care about E  S. That's a HUGE difference. (Analogy: I drive my car 54 miles. Do you know the starting odometer mileage? Nope. Do you know the ending odometer mileage? Nope. Do you know the difference between them? Yep, 54 miles.) What affects E  S? To figure that out, temporarily forget that there are 30 numbers, and pretend there's just 1 number. * If the number is rounded up, then E  S is positive. It's the amount by which the number is rounded up. (If you round 14.87 up to 15, then E  S is 0.13.) * If the number is rounded down, then E  S is negative. It's the amount by which the number is rounded down. (If you round 14.77 down to 14, then E  S is 0.77.) Thinking this way, we can see that it's a waste of time to consider the "integer part" at all. If you round 14.87 up to 15, or 99.87 up to 100, or anything point 87 up to the next integer, you're still looking at +0.13. Now that we know that, things are more transparent. * 10 numbers are rounded up. The most by which they can be rounded up is just barely less than 1 each (if you start with x.00001 type thing). The least by which they can be rounded up is just barely more than 0.1 each (if you start with x.89999 type thing). * 20 numbers are rounded down. The most by which they can be rounded down is just barely less than 1 each (if you start with x.99999 type thing). The least by which they can be rounded down is 0.1 each (if you start with x.1). To make E  S as big as possible, make the positive contributions as big as possible: 10 * (approximately +1) = approximately +10. Make the negative contributions as small as possible: 20 * 0.1 = 2. So, the maximum value of E  S is somewhere around 8. To make E  S as small as possible, make the positive contributions as small as possible: 10 * (approximately 0.1) = approximately +1. Make the negative contributions as big as possible: 20 * (approximately 1) = approximately 20. So, the minimum value of E  S is somewhere around 19. There you go. The point here is that you should think about whatever the problem actually asks you for. In those terms, it sounds stupidly simple, but look at what's happening in this thread  everyone is thinking separately about E and S, even though we only care about E  S. (Think about the odometer.) Oops. Focus! This idea is even more important on data sufficiency problems. (If a data sufficiency problem asks for something minus something else, and you try to find the individual values of "something" and "something else" rather than just finding the difference, you're practically certain to get the problem wrong, even if your math is all correct.)  Ron Purewal ManhattanGMAT Un bon vêtement, c'est un passeport pour le bonheur.Yves SaintLaurent
_________________
Please visit my corners of the web: http://www.RonPurewal.com http://www.facebook.com/RonPurewalGMAT __
Pueden hacerle preguntas a Ron en castellano Potete fare domande a Ron in italiano On peut poser des questions à Ron en français Voit esittää kysymyksiä Ron:lle myös suomeksi __
Un bon vêtement, c'est un passeport pour le bonheur. —Yves SaintLaurent



Intern
Joined: 02 Jan 2014
Posts: 12

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
15 Jan 2014, 17:39
7
This post received KUDOS
11
This post was BOOKMARKED
I found the responses in this question very helpful, but I think I found another way to explain it that I can understand better... hopefully someone finds this useful someday.
** As the question ask for the difference between S and E, the actual "integer" portions are negligible as they will cancel each other out in the minus () operation (e.g. 15.9  15 = 0.9) . If it helps in understanding, we can also assume that all numbers in the list T are 0.xxxx (as the minus operation cancels the "integer" portion anyway).
Let's recap: S = Real sum E = Estimated sum, 10 are rounded up, 20 are rounded down
We can also first establish that there is only one value of E, as we are given in the question that 10 of them WILL be rounded up, and 20 WILL be rounded down. There is no Emax or Emin. To solve for E and assuming that numbers in list T are 0.xxx as per above point, E = 10 x (T values rounded up) + 20 x (T values rounded down) = 10 x (0.2) + 20 x (0.9) > doesnt matter what the values are, they can be any even / odd combinations at the tenth = 10 x (1) + 20 x (0), after performing round up/down operations = 10
There are however Smax and Smin, as these are possible ranges prior to the round up/down operations.
Smax = 10 x (maximum even tenth) + 20 x (maximum odd tenth) = 10 x (0.8) + 20 x (0.9) = 8 + 18 = 26
Smin = 10 x (minimum even tenth) + 20 x (minimum odd tenth) = 10 x (0.2) + 20 x (0.1) = 2 + 2 = 4
The largest range of E  S is therefore E  Smin = 10  4 = 6
The lowest range of E  S is therefore E  Smax = 10  26 = 16
Unlike some contributions here, I found it absolutely necessary to solve for E and S. The previous solution by RonPurewal looks sound, but when you look closer, it assumes that E  S = (10 round up values  20 round down values), which is not true, and therefore the answers are not exactly to the range given by the question. The full algebraic equation of his solution should have been:
 Largest range of E  S = (10x round up + 20x round down)  (10x Minimum round up + 20x minimum round down)  Lowest range of E  S = (10x round up + 20x round down)  (10x Maximum round up + 20x maximum round down)
Essentially calling for the need to resolve for E and S individually, eventually. I apolgise if I sound rude  its 130am in the morning and I had just spent an hour just analyzing just this question alone, and my heart hurts! Irregardless, I have learn plenty just by analyzing everyone's solution to help me arrive to this way of looking into this problem. Many thanks!



Intern
Joined: 10 Jan 2014
Posts: 4
Location: India
Concentration: General Management, Operations
GMAT Date: 12062014
GPA: 3.61
WE: Engineering (Computer Hardware)

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
31 Jan 2014, 07:22
2
This post received KUDOS
2
This post was BOOKMARKED
The two extremes can be calculated as: 1. Highest tenths place 0.9 and 0.8
so E = S +(10*0.2  20*0.9) >>>> Change from 0.1 to 1 is 0.2(increase) & 0.9 to 0 is 0.9(decreased) = S +(218) ES = 16
2. Lowest tenths place 0.1 & 0.2 >>>> Change from 0.2 to 1 is 0.8 & 0.1 to 0 is 0.1 so E = S+(10*0.8  20*.2) E S = (82) ES = 6
Hence answer is B!!



Intern
Joined: 04 Feb 2014
Posts: 16

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
31 Mar 2014, 10:31
Schawjibb wrote: IMO, the best solution is shown by M Dabral of GMAT Quantum in one of its video explanations. Here is the link: http://www.gmatquantum.com/og13/218pro ... ition.htmlAlthough NOT most of GMAT Quantum's video explanations/solutions are up to the par, I found that this one along with some others (e.g., PS 178) is the best video explanation floating out there in the internet. it only explains the E i dont understand how he moved to S



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7960
Location: Pune, India

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
31 Mar 2014, 19:40
kedusei wrote: it only explains the E i dont understand how he moved to S Try out the solution given here: http://www.veritasprep.com/blog/2014/01 ... thegmat/
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Intern
Joined: 07 Aug 2013
Posts: 1
Location: India
Concentration: Finance, International Business

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
02 Sep 2014, 02:29
Let the number with even tenths place be denoted by x and the number with odd tenths place digit by y.
We can further split these decimals into their integer and decimal parts denoted by x(i) and x(d) respectively. Similarly, y can be split and written as y(i) and y(d).
Now, according to question, >>>>> S = x(i) + x(d) + y(i) + y(d) ........................... (1)
And, since E comprises only of the integer values >>>> E = x(i) +10 + y(i) ............................(2) { because, the number with even tenths place digit is rounded up and the number with odd tenths place digit is rounded down }
Now, from (1) and (2) E  S = x(i) +10 + y(i)  { x(i) + x(d) + y(i) + y(d) } = 10 { x(d) + y(d) }
Therefore, the final value is always going to be less than 10, and there are only two options in the question that support this result .
Please let me know if there is any problem with this approach.



Intern
Joined: 01 Jan 2014
Posts: 6
Location: United States

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
03 Sep 2014, 14:45
shamanth25 wrote: List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E  S ?
I. 16 II. 6 III. 10
A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III Please let me know if it is correct! Thanks. OA is B. My approach: a. Since 1./3rd of the decimals in T have a tenths digit that is even, those will be rounded "up" to the nearest integer. Example: 3.67 will be rounded up to 4; 5.28 to 6. b. But since each decimal in T whose tenths digits is odd is rounded down to the nearest integer, it will look like: 5.37 rounded down to 5. 7.99 to 7. from point (a), it is clear that the estimated sum of 1/3rd (10) of the decimals in the list T will exceed by 10, thus increasing the actual summation by 10. So, E is always greater that S (E>S) by 10, i.e. ES>0 Always This made me eliminate the negative result of ES. So, the answer can be 6 and 10. (B)



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7960
Location: Pune, India

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
03 Sep 2014, 20:55
Sen1120 wrote: from point (a), it is clear that the estimated sum of 1/3rd (10) of the decimals in the list T will exceed by 10, thus increasing the actual summation by 10. So, E is always greater that S (E>S) by 10, i.e. ES>0 Always
This made me eliminate the negative result of ES. So, the answer can be 6 and 10. (B)
Not correct. E  S can be negative. Answer can be 16 and 6 but not 10 which is (B). Please look at the explanation given here: http://www.veritasprep.com/blog/2014/01 ... thegmat/
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Intern
Joined: 10 Sep 2014
Posts: 4

Re: List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
24 Sep 2014, 16:17
souvik101990 wrote: Assume T = (1.a, 1.b,...etc) All units equal 1.xx. E = 40 (due to rounding of ten even and 20 odd) S max = 30 + 10(.8) + 20(.9) = 56 S min = 30 + 10(.2) + 20(.1) = 34
ES min = 40  56 = 16 ES max = 40  34 = 6 Thus, the min/max of E is 16 and 6, so I , II apply.
For (III. 10) to be true, S min/max in our equation above needs to equal 30. This is impossible since the question states T consists of 30 positive decimals. Therefore eliminate III. You're missing something here, Souvik. First of all, I approached this differently than you, although that doesn't matter. I first looked at the differential irrespective of S. E is either going to be a net (+) or () based on the observations' tenth'sdigits, and the magnitude of gain due to rounding. BUT! (x.2) doesn't represent the maximum net gain from an even tenth'sdigit rounded up to the nearest integer, (x.0) does. Thus, deltaE(max) = 10(1)  20(.1) = 8 (=ES max) deltaE(min) = 10(.2)  20(.9) = (16) (=ES min) Inconsequential in the scheme of the answer choices, but something worth noting. Cheers!



Director
Joined: 07 Aug 2011
Posts: 578
Concentration: International Business, Technology

List T consist of 30 positive decimals, none of which is an [#permalink]
Show Tags
24 Mar 2015, 10:39
3
This post was BOOKMARKED
shamanth25 wrote: List T consist of 30 positive decimals, none of which is an integer, and the sum of the 30 decimals is S. The estimated sum of the 30 decimals, E, is defined as follows. Each decimal in T whose tenths digit is even is rounded up to the nearest integer, and each decimal in T whose tenths digits is odd is rounded down to the nearest integer. If 1/3 of the decimals in T have a tenths digit that is even, which of the following is a possible value of E  S ?
I. 16 II. 6 III. 10
A. I only B. I and II only C. I and III only D. II and III only E. I, II, and III At first glance question may look difficult but in reality it can be solved in 2 mins .. \(E_m_a_x = S + ( 20*(0.1) + 10*0.8) = S+6\) so ES=6 \(E_m_i_n = S + ( 20*(0.9) + 10*0.2) = S16\) so ES=16 Answer B.
_________________
Thanks, Lucky
_______________________________________________________ Kindly press the to appreciate my post !!




List T consist of 30 positive decimals, none of which is an
[#permalink]
24 Mar 2015, 10:39



Go to page
1 2 3 4
Next
[ 68 posts ]



