Official Solution: The following table shows results of a quality inspection of a lot of 15 mirrors.

The difference between the median number of defects and the average number of defects in the sample checked is between:

A. -1 and 0

B. 0 and 0.5

C. 0.5 and 1

D. 1 and 1.5

E. 1.5 and 2

Sort the observations of the number of defects: 0 0 0 0 0 0 1 2 2 2 2 3 3 3 4

The median is the middle term, which is 2.

The average can be calculated as follows: \(\frac{0*6 + 1*1 + 2*4 + 3*3 + 4*1}{15} = \frac{22}{15}\)

The difference between the median and the average is \(2 -\frac{22}{15} = \frac{8}{15} = 0.53\).

Answer: C

Please advise.

..(No average number number of defects--gets me into thinking its the average of sum of frequency..)