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Bunuel
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VarunBhardwaj
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Hi Bunuel
B cannot be the answer!

If i put X= 0.5 which is X > -1, Then the
L.H.S = 1
And R.H.S = 0.5.
R.H.S is not greater than L.H.S
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VarunBhardwaj
Hi Bunuel
B cannot be the answer!

If i put X= 0.5 which is X > -1, Then the
L.H.S = 1
And R.H.S = 0.5.
R.H.S is not greater than L.H.S

x cannot be 0.5 because it does not satisfy given condition that \(\frac{x}{|x|} \lt x\). Please re-read the solution.
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I think this is a high-quality question.
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Hello, thanks for interesting question.

how can |x| = -x when x<0? if x <0 then |-x|=x?

I think when x<0, -x/|x|<-x. isn't it?

Please explain the flaws in my logic.

thank u!
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I think this is a high-quality question and I agree with explanation.
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I think this the explanation isn't clear enough, please elaborate. I understood the algebraic method but I had a doubt. An inequality problem can be solved by plugging in values also right? If we try to plug-in values into option A, the -0.5 value which we arrive by solving algebraically, will go against the statement itself. Is it that we can't solve some inequality problems by plugging in?
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I think this the explanation isn't clear enough, please elaborate. I understood the algebraic method but I had a doubt. An inequality problem can be solved by plugging in values also right? If we try to plug-in values into option A, the -0.5 value which we arrive by solving algebraically, will go against the statement itself. Is it that we can't solve some inequality problems by plugging in?

I'll try again.

The question asks if \(-1 \lt x \lt 0\) or \(x \gt 1\), then which of the following must be true.

Since \(-1 \lt x \lt 0\) or \(x \gt 1\), then it must be true to say about x that x > -1.

For example, x can be, among many other values, -0.9, -0.89292838, -0.76539, -0,5, ... (because \(-1 \lt x \lt 0\)) as well as x can be 3, \(\pi\), 4.17, \(\sqrt{71}\), ... (because \(x \gt 1\)). Any of them is greater than -1. For ANY possible x, so for ANY x from \(-1 \lt x \lt 0\) and \(x \gt 1\), it will be true to say that x is greater than -1.

Option A, which says that \(x \gt 1\), is NOT always true because if x is from \(-1 \lt x \lt 0\), say if x is -0.14, then \(x \gt 1\) will NOT be true.

Hope it's clear.
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I think this is a high-quality question and I agree with explanation. Brilliant
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I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;
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I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;

We know that −1 < x < 0 or x > 1. The question asks to determine which of the options MUST be true.

A says: x > 1. This options is NOT always true because x could be from any number from −1 < x < 0, and if it is, then x > 1 won't be true. Please re-read the whole discussion again and follow the links provided there.

Similar questions to practice:
https://gmatclub.com/forum/if-it-is-tru ... 81702.html
https://gmatclub.com/forum/if-xy-0-and- ... 39194.html
https://gmatclub.com/forum/if-it-is-true ... 29093.html
https://gmatclub.com/forum/if-it-is-tru ... 66196.html
https://gmatclub.com/forum/if-4x-12-x-9- ... 01732.html
https://gmatclub.com/forum/if-4-7-x-3-w ... 68681.html
https://gmatclub.com/forum/if-5-x-0-whi ... 31556.html
https://gmatclub.com/forum/if-it-is-tru ... -9602.html
https://gmatclub.com/forum/if-m-0-which ... 54150.html
https://gmatclub.com/forum/if-x-0-which ... 76331.html
https://gmatclub.com/forum/if-x-3-1-2-w ... 29673.html
https://gmatclub.com/forum/if-x-12-then ... 61430.html
https://gmatclub.com/forum/if-it-is-tru ... 52933.html
https://gmatclub.com/forum/if-x-1-4-so-252054.html
https://gmatclub.com/forum/if-z-2-4z-5- ... 52017.html

Hope it helps.
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I think this is a high-quality question and I agree with explanation. This is a very insightful question and I loved the explanation. It took some time for me to understand that why the correct answer is correct.
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I think this is a high-quality question and I agree with explanation.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Bunuel
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Hi Bunuel
B cannot be the answer!

If i put X= 0.5 which is X > -1, Then the
L.H.S = 1
And R.H.S = 0.5.
R.H.S is not greater than L.H.S

x cannot be 0.5 because it does not satisfy given condition that \(\frac{x}{|x|} \lt x\). Please re-read the solution.

Solving the equation gives value of x>1 and x>-1. Although, The values in 0<x<1 don't work for this equation.
So, how we can say anything x>-1 will always be true? (must be question)
This was the reason I selected last option, as that particular range will always work for given equation.
Thanks for such question though!
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Bunuel
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Hi Bunuel
B cannot be the answer!

If i put X= 0.5 which is X > -1, Then the
L.H.S = 1
And R.H.S = 0.5.
R.H.S is not greater than L.H.S

x cannot be 0.5 because it does not satisfy given condition that \(\frac{x}{|x|} \lt x\). Please re-read the solution.

Solving the equation gives value of x>1 and x>-1. Although, The values in 0<x<1 don't work for this equation.
So, how we can say anything x>-1 will always be true? (must be question)
This was the reason I selected last option, as that particular range will always work for given equation.
Thanks for such question though!

\(\frac{x}{|x|} \lt x\) implies that \(-1 \lt x \lt 0\) or \(x \gt 1\). This is explained in the solution in detail, so I won't repeat myself. You can plug in the values to check. If you're still finding it tough to understand, I strongly recommend practicing with similar logic-based questions from this helpful collection: Trickiest Inequality Questions Type: Confusing Ranges.

Hope this clears things up for you!
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I agree with explanation.
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Bunuel

How is it that X/−X < X simplifies to −1 < X? Can you please elaborate on that?


Thanks in Advance!
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