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M28-13

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Math Expert
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Joined: 02 Sep 2009
Posts: 56300
M28-13  [#permalink]

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New post 16 Sep 2014, 01:28
2
7
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

72% (01:40) correct 28% (01:28) wrong based on 261 sessions

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Math Expert
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Joined: 02 Sep 2009
Posts: 56300
Re M28-13  [#permalink]

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New post 16 Sep 2014, 01:28
1
2
Official Solution:

If \(x^4 = 29x^2 - 100\), then which of the following is NOT a product of three possible values of \(x\)?
I. -50

II. 25

III. 50


A. \(I\) only
B. \(II\) only
C. \(III\) only
D. \(I\) and \(II\) only
E. \(I\) and \(III\) only


Re-arrange and factor for \(x^2\): \((x^2-25)(x^2-4)=0\).

So, we have that \(x=5\), \(x=-5\), \(x=2\), or \(x=-2\).

\(-50=5*(-5)*2\);.

\(50=5*(-5)*(-2)\);

Only 25 is NOT a product of three possible values of \(x\)


Answer: B
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Re M28-13  [#permalink]

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New post 17 Feb 2015, 13:25
I think this question is poor.
it is 29 in the question ,but factoring shows 25!!!
Math Expert
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Re: M28-13  [#permalink]

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New post 17 Feb 2015, 13:29
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Re M28-13  [#permalink]

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New post 22 Aug 2017, 12:25
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I think this is a high-quality question and I agree with explanation.
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Re: M28-13  [#permalink]

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New post 06 Jul 2018, 09:23
Viktorijakm wrote:
I think this question is poor.
it is 29 in the question ,but factoring shows 25!!!


The factoring is correct though, as you are looking for numbers which add to -29 and multiply to 100 respectively.

I think the question is of high quality and similar to stuff I have seen on the GMAC prep tests.
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Re M28-13  [#permalink]

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New post 28 Aug 2018, 08:17
I think this is a high-quality question.
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Re M28-13   [#permalink] 28 Aug 2018, 08:17
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