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# multiple of 100

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Manager
Joined: 09 Oct 2008
Posts: 93

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22 Oct 2008, 07:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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Manager
Joined: 14 Oct 2008
Posts: 160

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22 Oct 2008, 07:42
Out of C and E it has to be E .

I am thinking , any number for x like 499 which has 500 as the closest multiple of 100 , and any number like 399 which has 400 as closest multiple of 100 , and 499 < 500 and 399 < 400 then x+y = 898 , so closest multiple will be 900.

Now lets take the lowest possible numbers for x and y.
if we take x = 451 and y = 351 then x+y = 802 then closest multiple would be 800 , hence we cannot answer this qs, so its E.

Let me know the answer .
Current Student
Joined: 28 Dec 2004
Posts: 3342
Location: New York City
Schools: Wharton'11 HBS'12

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22 Oct 2008, 07:46
i say e as well

say if x=499 and y=399 then x+y= 898...so you 900 is the closest multiple

if x=451 and y=351 then x+y=802 then 800 is the closest multiple
Manager
Joined: 14 Oct 2008
Posts: 160

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22 Oct 2008, 07:49
bingo fresinha !
SVP
Joined: 17 Jun 2008
Posts: 1529

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22 Oct 2008, 23:34
From the question, 450 < x < 550 and 350 < y < 450.

Hence, 800 < x+y < 1000.

Now, multiple of 100 that is closest to (x+y) could be 800, 900 or 1000.

From stmt1: 450 < x < 500 and hence 800 < x+y < 950....and multiple could be 800 or 900...insufficient.

From stmt2: 350 < y > 400 and again, 800 < x+y < 950....and multiple could be 800 or 900....insufficient.

Combining the two, 800 < x+y < 900 and again multiple could be 800 or 900 and hence insufficient.

Hence E.
Retired Moderator
Joined: 18 Jul 2008
Posts: 959

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23 Oct 2008, 09:07
Good explanation. It's actually easier than the way it reads.

scthakur wrote:
From the question, 450 < x < 550 and 350 < y < 450.

Hence, 800 < x+y < 1000.

Now, multiple of 100 that is closest to (x+y) could be 800, 900 or 1000.

From stmt1: 450 < x < 500 and hence 800 < x+y < 950....and multiple could be 800 or 900...insufficient.

From stmt2: 350 < y > 400 and again, 800 < x+y < 950....and multiple could be 800 or 900....insufficient.

Combining the two, 800 < x+y < 900 and again multiple could be 800 or 900 and hence insufficient.

Hence E.
Re: multiple of 100   [#permalink] 23 Oct 2008, 09:07
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# multiple of 100

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