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Of the 1400 college teachers surveyed, 42% said they consid
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30 Mar 2010, 21:58
Question Stats:
51% (02:04) correct 49% (02:11) wrong based on 1195 sessions
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Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women? (1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal.
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Of the 1400 college teachers surveyed, 42% said they consid
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31 Mar 2010, 08:48




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31 Mar 2010, 09:03
Thanks for all the help, folks.



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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02 Sep 2014, 22:36
Hi Bunuel, I thought the first statement as 36% of the total men who participated in the survey and similar for women. The statement itself says In the survey 36% of men and 50% of women said...!! We cannot calculate the total no. of men and women. participated in the survey from the given information!! Confused!! Bunuel wrote: Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women?
(1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal.
(1) \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\). Two unknowns two equations. Sufficient. (2) From this we can calculate only that \(1400*0.42288=300\) women consider engaging in research activity an essential goal. No other info. Not sufficient.
Answer: A.
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Re: Of the 1400 college teachers surveyed, 42% said they consid
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03 Sep 2014, 04:13
scofield1521 In the above solution m = total number of men participated in the survey w = total number of women participated in the survey Clearly m+w=1400  Equation 1 and as per choice a (0.36 m) = total number of men that considered engaging in research an essential goal (0.5 w ) = total number of women that considered engaging in research an essential goal also 0.36 m + 0.5w = 0.42 (1400)  Equation 2 Hence, A is enough to get the answer.
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Re: Of the 1400 college teachers surveyed, 42% said they consid
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07 Sep 2014, 03:00
Hi , has anyone solved this problem using grid method. I am getting C as the answer by using grid method. Please help.



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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09 Oct 2014, 03:33
I (initially) got this wrong using the grid method because I failed to realise that W + M = 1400. I think it just goes to show that it's important to write pretty much everything down while doing a question, so you don't miss anything...



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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10 Oct 2014, 03:24
burnttwinky wrote: Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women?
(1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal. 42% of total teachers considered research essential. So 58% considered it not essential. Using stmnt 1, say the number of women is W. So number of men must be 1400  W. Attachment:
Ques3.jpg [ 13.04 KiB  Viewed 21463 times ]
36% of men and 50% of women consider research essential. We see that we get 36% * (1400  W) + 50% * W = 42% * 1400 We can solve it for the value of W and hence this statement alone is sufficient. Stmnt 2 doesn't tell us the number of women who consider research essential so it is not sufficient alone. Answer(A)
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Re: Of the 1400 college teachers surveyed, 42% said they consid
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27 Oct 2015, 22:55
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution. Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women? (1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal. If we modify the original condition, we can get a '2by2' table, which is one of the most common types of question in GMAT Math Attachment:
GC DS burmttwinky Of the 1400 college.png [ 3.6 KiB  Viewed 16886 times ]
When looking at the table, we can see that a+b+c+d=1400, a+b=1400*42%. There are 4 variables and 2 equations, so we need 2 more equations From condition 1, there are 2 equations (b=0.36(b+d), a=0.5(a+c)), so this is sufficient, whereas condition 2 only gives one condition (b=288), making this insufficient and the answer becomes (A).
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Of the 1400 college teachers surveyed, 42% said they consid
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17 Apr 2016, 04:32
Bunuel wrote: Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women?
(1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal.
(1) \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\). Two unknowns two equations. Sufficient. (2) From this we can calculate only that \(1400*0.42288=300\) women consider engaging in research activity an essential goal. No other info. Not sufficient.
Answer: A. In such a case, isn't it essential to check the following 2 things regarding statement (1)? : A. Whether integral solution exists for set of equations \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\) B. Whether only a single integral solution exists for the set of equations. In case the answer to any of the two questions is YES, wouldn't (1) be rendered NOT SUFFICIENT? PS: When I solved the question, I used the same methodology as yours, but consumed more time because I checked for the two questions mentioned above. Hence, I am interested to know whether you have a definite way of knowing that these 2 additional operations are not required.



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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17 Apr 2016, 04:55
bikographer wrote: Bunuel wrote: Of the 1400 college teachers surveyed, 42% said they considered engaging in research an essential goal. How many of the college teacher surveyed were women?
(1) In the survey 36% of men and 50% of women said that they consider engaging in research activity an essential goal. (2) In the survey 288 men said that they consider engaging in research activity an essential goal.
(1) \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\). Two unknowns two equations. Sufficient. (2) From this we can calculate only that \(1400*0.42288=300\) women consider engaging in research activity an essential goal. No other info. Not sufficient.
Answer: A. In such a case, isn't it essential to check the following 2 things regarding statement (1)? : A. Whether integral solution exists for set of equations \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\) B. Whether only a single integral solution exists for the set of equations. In case the answer to any of the two questions is YES, wouldn't (1) be rendered NOT SUFFICIENT? PS: When I solved the question, I used the same methodology as yours, but consumed more time because I checked for the two questions mentioned above. Hence, I am interested to know whether you have a definite way of knowing that these 2 additional operations are not required. Hi, Quote: A. Whether integral solution exists for set of equations \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\) all the % given are by the Q and nothing is being assumed by us, so if they have given 36% of men and 50% of women are ...., it will always be integer.. Rather you can use this property to home on to some info on m and w... .36m has to be an integer or 36m/100 is an integer 36m/100 = 9m/25.. this tells us that m has to be a multiple of 25.. there are other Q where you have to check for this but not here as the % are given by the Q.. Quote: B. Whether only a single integral solution exists for the set of equations. If you have two distinct linear equation and two variables, ans is YES
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Re: Of the 1400 college teachers surveyed, 42% said they consid
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17 Apr 2016, 05:52
Thanks, chetan2u! Quote: A. Whether integral solution exists for set of equations \(m+w=1400\) and \(1400*0.42=0.36*m+0.5*w\)
all the % given are by the Q and nothing is being assumed by us, so if they have given 36% of men and 50% of women are ...., it will always be integer.. Rather you can use this property to home on to some info on m and w... .36m has to be an integer or 36m/100 is an integer 36m/100 = 9m/25.. this tells us that m has to be a multiple of 25..
there are other Q where you have to check for this but not here as the % are given by the Q.. This is something that I wasn't aware of until now. I was under the impression that GMAC could intentionally give us cases where the quantities wouldn't turn out to be integers, just to test whether we would check them or not. I will remember this from now on. Quote: B. Whether only a single integral solution exists for the set of equations. If you have two distinct linear equation and two variables, ans is YES I now realize how stupid a question 'B' was! :D Thanks, once again.



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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17 Apr 2016, 06:01
bikographer wrote: Thanks, chetan2u! This is something that I wasn't aware of until now. I was under the impression that GMAC could intentionally give us cases where the quantities wouldn't turn out to be integers, just to test whether we would check them or not. I will remember this from now on. Another point.. If two variables are given without any info, it can be anything  integers or fraction , + or  example 15x + 12y = 350.... x and y can take any values....
But if it says that 36% are men OR 22% bikes OR 70% cars... all the things which have to be in integer quantity.. would mean 22% bikes are integer, 70% car is integer etc..
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17 Apr 2016, 23:37
Thanks everyone for explaining. So essentially it means that the survey's other group are those who do not consider engaging in resserch an essential goal? with this assumption it becomes a clear A... 250 level. So this is how we assume it in any question like this? Kudos awaits replies.
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17 Apr 2016, 23:37
Thanks everyone for explaining. So essentially it means that the survey's other group are those who do not consider engaging in resserch an essential goal? with this assumption it becomes a clear A... 250 level. So this is how we assume it in any question like this? Kudos awaits replies.
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18 Apr 2016, 01:41
Wao. i thought that there might be other groups like the undecided or indifferent: the Neithers. Damn GMAT! Bunuel don't worry, I've knocked your point into my skull. Thanks a lot. Posted from my mobile device



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01 Jun 2016, 09:28
Let M = men and W = Women
m + w = 1400 36m + 50w = 58800
Since we have 2 equations for 2 unknowns we can solve for either of the values hence 1 is sufficient. . For 2 it merely mentions total number of men and with the given data number of women cannot be found hence insufficient.
Answer choice is A



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Re: Of the 1400 college teachers surveyed, 42% said they consid
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31 Jan 2017, 17:31
stem: 42/100 x 1400 said that they considered engaging..., so 588 are considered engaging, 812 are not considered engaging... 2) of the 588, 288 are men, so 300 are women are engaging  but how many women are NOT considered engaging...? INSUFFICIENT harder of the 2 statements: 1) 36% of Men and 50% of Women are considered engaging...so 36/100 M + 50/100 W = 588 and M + W = 1400 2 distinct linear equations, 2 variables SUFFICIENT answer is A
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Re: Of the 1400 college teachers surveyed, 42% said they consid
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27 Apr 2017, 15:54
(2) M + W = 1400
who wants to research = 1400* .42 = (M+W)* .42 = 588 since 1400= M+W so we can replace M+W with 1400
now men who want to do research= 288 = .42M so .42(M+W )= 588 .42M +.42 W= 588 288 +.42 W = 588 so we can calculate W
so why this is wrong?




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