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Bunuel
If -2 < a < 11 and 3 < b < 12, then which of the following is NOT always true?

A. 1 < a + b < 23
B. -14 < a - b < 8
C. -7 < b - a < 14
D. 1 < b + a < 23
E. -24 < a b < 132

A. 1 < a + b < 23 Using the values given we see that (a+b) ranges from (-2+3=1) to (11+12=23) hence This option is True
B. -14 < a - b < 8 Using the values given we see that (a-b) ranges from (-2-12=-14) to (11-3=8) hence This option is True
C. -7 < b - a < 14 Using the values given we see that (b-a) ranges from (3-11=-8) to (12-(-2)=14) hence This option is NOT true for lowest value of (b-a)
D. 1 < b + a < 23 Using the values given we see that (a+b) ranges from (-2+3=1) to (11+12=23) hence This option is True
E. -24 < a b < 132 Using the values given we see that (a.b) ranges from (-2*12=-24) to (11*12=132) hence This option is True

ANswer: option C
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If –2 < a < 11 and 3 < b < 12, then which of the following is NOT true?

A) 1 < a + b < 23
B) –14 < a – b < 8
C) –7 < b – a < 14
D) 1 < b + a < 23
E) –24 < ab < 132

Ans: C
My method is a bit calculative we need to find which one is not true and for that we need to do the calculation
for A: a's min + b's min <a+b< a's max + b's max = -2+3 <a+b<11+12= 1<a+b<23 True
for B: a's min - b'max <a-b< a's max- b's min= -2-12 <a-b< 11-3 = -14<a-b<8 True
for C: b's min-a' max <b-a<b's max- a's min= 3-11 <b-a<12-(-2) = -8<b-a<14 Not True
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selim
If –2 < a < 11 and 3 < b < 12, then which of the following is NOT true?

A) 1 < a + b < 23
B) –14 < a – b < 8
C) –7 < b – a < 14
D) 1 < b + a < 23
E) –24 < ab < 132

If we add the two inequalities together, we have:

1 < a + b < 23

Thus, A is true and since a + b = b + a, D is also true.

Multiplying the second inequality by -1, we have 3 > -b > -12 or -12 < -b < 3. Now, adding the latter to the first inequality, we have:

–14 < a – b < 8

So B is true.

Similarly, multiplying the first inequality by -1, we have 2 > -a > -11 or -11 < -a < 2. Now. adding the latter to the second inequality, we have:

–8 < b – a < 14

So C is NOT true since (b - a) could be -7.5, which does not fall into -7 < b - a < 14.

Answer: C
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I believe the wording of question is not correct, and can definitely be better to remove ambiguity.

If the range of b-a is: -8 to 14 (say, SET A) ...as explained in the above comments
Option C: -7 to 14 (say, SET B)

=> SET B is a subset of SET A. Hence, for all the values in range -7 to 14 (Option C), the value of b-a (range: -8 to 14) holds correctly.
Please note: Question asks to select an option which is NOT always true. But the option C will always hold true as it is the subset of A. Hence, Option C can surely not be the answer to this question.

Request Admin to kindly check this and correct the question wording.
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PANKAJ0901
I believe the wording of question is not correct, and can definitely be better to remove ambiguity.

If the range of b-a is: -8 to 14 (say, SET A) ...as explained in the above comments
Option C: -7 to 14 (say, SET B)

=> SET B is a subset of SET A. Hence, for all the values in range -7 to 14 (Option C), the value of b-a (range: -8 to 14) holds correctly.
Please note: Question asks to select an option which is NOT always true. But the option C will always hold true as it is the subset of A. Hence, Option C can surely not be the answer to this question.

Request Admin to kindly check this and correct the question wording.

This is not true. If b = 3.1 and a = 10.9, then b - a = 3.1 - 10.9 = -7.8.

P.S. Please do not use report button. A post is enough.
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PANKAJ0901
I believe the wording of question is not correct, and can definitely be better to remove ambiguity.

If the range of b-a is: -8 to 14 (say, SET A) ...as explained in the above comments
Option C: -7 to 14 (say, SET B)

=> SET B is a subset of SET A. Hence, for all the values in range -7 to 14 (Option C), the value of b-a (range: -8 to 14) holds correctly.
Please note: Question asks to select an option which is NOT always true. But the option C will always hold true as it is the subset of A. Hence, Option C can surely not be the answer to this question.

Request Admin to kindly check this and correct the question wording.


Taking your observation further.
Rather, Set A has to be subset of Set B for the option to be true and not vice versa.
We know from Set A that b-a can also be something from -8 to -7, but Set B misses on it.

For example.
Say c is a prime number.
A) c is an integer would be true.
B) But c is odd prime number will not although it is a subset of prime number. If c=2, the option will not stand.
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PANKAJ0901
I believe the wording of question is not correct, and can definitely be better to remove ambiguity.

If the range of b-a is: -8 to 14 (say, SET A) ...as explained in the above comments
Option C: -7 to 14 (say, SET B)

=> SET B is a subset of SET A. Hence, for all the values in range -7 to 14 (Option C), the value of b-a (range: -8 to 14) holds correctly.
Please note: Question asks to select an option which is NOT always true. But the option C will always hold true as it is the subset of A. Hence, Option C can surely not be the answer to this question.

Request Admin to kindly check this and correct the question wording.

Please find my remarks below in red and blue.

Taking your observation further.
Rather, Set A has to be subset of Set B for the option to be true and not vice versa.
We know from Set A that b-a can also be something from -8 to -7, but Set B misses on it.

For example.
Say c is a prime number. c={2,3,5,7,11....} Which of the following is NOT always true?
A) c is an integer would be true. {-3,-2,-1,0,1,...} are also integers, which need NOT ALWAYS be Prime numbers.
B) But c is odd prime number will not although it is a subset of prime number. {3,5,7,11,....} => Definitely true..as all these values are Prime numbers.
If c=2, the option will not stand. (That's Ok, but does c=2 make option B "WRONG" or "NOT RIGHT". I FAIL TO UNDERSTAND THIS!)
C) c is a complex number. => Not ALWAYS TRUE...similar to option A (as otherwise every solution in mathematics would be some complex number with imaginary part as 0 at most. Why should we even be zeroing down to a smaller set of range?)
D) c is a Natural number. => Not ALWAYS TRUE .....and so on....


I think, there are two ways to look these questions- and none of the two perspectives is completely wrong.
Thanks Bunuel and Chetan2u for the explanation (More Kudos to you guys). I understand that Option C doesn't capture the complete range, and that's not the point I am concerned with. It's clear that there could be more values of a,b (say, -10.9, 3.1, as mentioned by Bunuel). What I was trying to say here is something else. May be I need some break as despite a lot of thought I still couldn't quite comprehend.
As per the question, it says "..which of the following is NOT always true?" Option C is definitely always true! There could be more eligible values which are not captured in Option C (that's completely ok), my point is Option C is NOT WRONG. I had only pointed out for a clearer wording that doesn't leave any scope of ambiguity.

PS (For Bunuel)- Duly noted, report button will not be used. Thanks. :)
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PANKAJ0901

I think, there are two ways to look these questions- and none of the two perspectives is completely wrong.
Thanks Bunuel and Chetan2u for the explanation (More Kudos to you guys). I understand that Option C doesn't capture the complete range, and that's not the point I am concerned with. It's clear that there could be more values of a,b (say, -10.9, 3.1, as mentioned by Bunuel). What I was trying to say here is something else. May be I need some break as despite a lot of thought I still couldn't quite comprehend.
As per the question, it says "..which of the following is NOT always true?" Option C is definitely always true! There could be more eligible values which are not captured in Option C (that's completely ok), my point is Option C is NOT WRONG. I had only pointed out for a clearer wording that doesn't leave any scope of ambiguity.

PS (For Bunuel)- Duly noted, report button will not be used. Thanks. :)

The question is correct and there is only one correct interpretation

The question asks: If -2 < a < 11 and 3 < b < 12, then which of the following is NOT always true?

Only option C is NOT always true. I don't see any ambiguity whatsoever.
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Given:

-2 < a < 11

and

3 < b < 12

The question is asking the following:

Which of the Answer Choice Ranges does NOT Always have to be true for EVERY Value that the expression can take?

-C-

-7 < b - a < 14

(1st) Find the MINIMUM Lower Bound of the expression (b - a) given the Ranges in the Q Prompt

We want to first Minimize the Value that (b - a) can take.

Since a is being subtracted from b ——-> we accomplish this by making b as LOW a VALUE as we can ——- and by making a as HIGH a VALUE as we can

The Lower Value Limit for b is: +3

The Upper Value Limit for a is: +11

Thus, the expression (b - a) can take Values greater than >

+3 - +11 = (-)8

(-)8 < (b - a)


However, the Range given by Answer C is:

(-)7 < (b - a) < +14

Answer C is NOT Always a True Statement.

For example, (b - a) can equal a Value like (-)7.5 or (-)7.6 and the Range in Answer Choice C would NOT cover these Values


Therefore, the answer is C

C does NOT always have to be True

Posted from my mobile device
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Bunuel,

Could you please check what is wrong with my reasoning:

B) -14<a-b<8
if we take min of a-b, we get a little more than -14(a is more than -2, and b is less than 12)
if we take max of a-b, we get a little less than 8 (a is a little less than 11 and b is a little more than 3)
----> So B is always correct

E) -24<ab<132
If we take min of ab, we get a little more than -24 (a is a little larger than -2, b is a little smaller than 12)
If we take max of ab, we get a little less than 132 (a is a little smaller than 11, b is a little smaller than 12)
---> So E is also correct as per my logic. Could you please be so kind to point out my mistake. Much appreciated in advance!
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mira93
Bunuel,

Could you please check what is wrong with my reasoning:

B) -14<a-b<8
if we take min of a-b, we get a little more than -14(a is more than -2, and b is less than 12)
if we take max of a-b, we get a little less than 8 (a is a little less than 11 and b is a little more than 3)
----> So B is always correct

E) -24<ab<132
If we take min of ab, we get a little more than -24 (a is a little larger than -2, b is a little smaller than 12)
If we take max of ab, we get a little less than 132 (a is a little smaller than 11, b is a little smaller than 12)
---> So E is also correct as per my logic. Could you please be so kind to point out my mistake. Much appreciated in advance!

The question asks: ...which of the following is NOT always true?

A, B, D and E are always true.

E is not always true.
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Bunuel
If -2 < a < 11 and 3 < b < 12, then which of the following is NOT always true?

A. 1 < a + b < 23
B. -14 < a - b < 8
C. -7 < b - a < 14
D. 1 < b + a < 23
E. -24 < a b < 132

A. a+b= 1 < a + b < 23
B. a-b = -14 < a - b < 8 [1,-5,8,-14 we take 8 and -14]
C. b-a= -8 < b - a < 14 [Given is -7 < b - a < 14 ] [1,5,-8,14 we can take 14 and -8]
D. 1 < b + a < 23 [Same as A]
E. -24 < a b < 132 [The four values are -6,132,-24,33; we take extreme values 132 as upper limit and -24 as lower limit]

So C is not True. Answer is C
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