Last visit was: 26 Sep 2026, 22:15 It is currently 26 Sep 2026, 22:15
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Sep 2026
Posts: 113,941
Own Kudos:
843,812
 [1]
Given Kudos: 111,838
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,941
Kudos: 843,812
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
LauraOrion
Joined: 19 Jul 2018
Last visit: 29 Apr 2019
Posts: 95
Own Kudos:
80
 [1]
Given Kudos: 9
Posts: 95
Kudos: 80
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 26 Sep 2026
Posts: 11,319
Own Kudos:
46,277
 [2]
Given Kudos: 340
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,319
Kudos: 46,277
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,727
Own Kudos:
37,402
 [6]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,727
Kudos: 37,402
 [6]
1
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
Baten80
Is xy > 0?

(1) x - y > -2
(2) x - 2y < -6

Target question: Is xy > 0?

Statement 1: x - y > -2
Let's TEST some values.
There are several values of x and y that satisfy statement 1. Here are two:
Case a: x = 5 and y = 1. In this case, xy = (5)(1) = 5. So, the answer to the target question is YES, xy IS greater than 0
Case b: x = 5 and y = -1. In this case, xy = (5)(-1) = -5. So, the answer to the target question is NO, xy is NOT greater than 0
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x - 2y < -6
Let's TEST some values again.
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 1 and y = 10. In this case, xy = (1)(10) = 10. So, the answer to the target question is YES, xy IS greater than 0
Case b: x = -1 and y = 10. In this case, xy = (-1)(10) = -10. So, the answer to the target question is NO, xy is NOT greater than 0
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
IMPORTANT: There’s a useful inequality property that says If two inequalities have their inequality symbols facing the SAME DIRECTION, we can ADD the inequalities.
We have:
x - y > -2
x - 2y < -6

Take the BOTTOM equation and multiply both sides by -1 to get:
x - y > -2
-x + 2y > 6 [since we multiplied both sides by a NEGATIVE value, we REVERSED the direction of the inequality symbol]

Now ADD the equations to get: y > 4
In other words, y is POSITIVE

Now take:
x - y > -2
-x + 2y > 6

Take the TOP equation and multiply both sides by 2 to get:
2x - 2y > -4
-x + 2y > 6

Now ADD the equations to get: x > 2
In other words, x is POSITIVE

Since x and y are both POSITIVE, we know that xy IS positive
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer: C

RELATED VIDEOS

User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 26 Sep 2026
Posts: 6,139
Own Kudos:
6,126
 [1]
Given Kudos: 164
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 6,139
Kudos: 6,126
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Baten80
Is xy > 0?

(1) x - y > -2
(2) x - 2y < -6

Is xy>0

1) x-y > -2
x>y-2
xy>y(y-2)=y^2-2y
Value of y is unknown
NOT SUFFICIENT

2) x-2y < -6
x<2y-6
xy<y(2y-6)=2y^2-6y
Value of y is unknown
NOT SUFFICIENT

Combining (1) & (2)
1) x-y > -2
x>y-2. (3)
2) x-2y < -6
x<2y-6
-x>-2y+6 (4)
Adding (3) & (4)
0>-y+4
y>4>0 (5)
From equation (3)
x>y-2>4-2=2>0
x>2>0 (6)
xy>0
SUFFICIENT

IMO C
User avatar
avigutman
Joined: 17 Jul 2019
Last visit: 27 Jun 2026
Posts: 1,285
Own Kudos:
Given Kudos: 66
Location: Canada
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Expert
Expert reply
GMAT 3: 770 Q50 V45
Posts: 1,285
Kudos: 922
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Video solution from Quant Reasoning (starts at 0:00:25):
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
User avatar
UserMaple5
Joined: 27 Apr 2021
Last visit: 24 Jul 2022
Posts: 41
Own Kudos:
Given Kudos: 259
Posts: 41
Kudos: 13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EgmatQuantExpert Bunuel JeffTargetTestPrep

Hi experts. I tend to get these types of questions right but they take me WAY TOO LONG to do. I normally test cases and it takes a while. Are there any strategies other than testing cases that I can use for these kind of questions to help improve timing?

Thank you in advance!
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 Sep 2026
Posts: 7,388
Own Kudos:
17,563
 [3]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 7,388
Kudos: 17,563
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
MHIKER
Is xy > 0?

(1) x - y > -2
(2) x - 2y < -6

Question; Is xy > 0?

STatement 1: x - y > -2

@x = 1, y may be +1 i.e. xy > 0
@x = 1, y may be -1 i.e. xy < 0

NOT SUFFICIENT

STatement 2:x - 2y < -6

@x = 1, y may be +4 i.e. xy > 0
@x = -1, y may be +4 i.e. xy < 0

NOT SUFFICIENT

Combining the statements
Rule of Inequalities:
- Two inequalities may be added if their inequality signs are identical
- Two inequalities may be Subtracted if their inequality signs are Opposite

Rule 1 is enough
:)

Now we have
x - y > -2 and x - 2y < -6
ie.. x - y > -2 and -x + 2y > 6 (multiplied -1 both sides in second inequation)

Adding the two inequations
x - y -x + 2y > -2+6
i.e. y > 4
Substituting it in inequation 1
x - y > -2 i.e. x > -2+y i.e. x > 2

SInce both x and y are positive, therefore xy > 0

Answer: Option C
User avatar
avigutman
Joined: 17 Jul 2019
Last visit: 27 Jun 2026
Posts: 1,285
Own Kudos:
922
 [2]
Given Kudos: 66
Location: Canada
GMAT 1: 780 Q51 V45
GMAT 2: 780 Q50 V47
GMAT 3: 770 Q50 V45
Expert
Expert reply
GMAT 3: 770 Q50 V45
Posts: 1,285
Kudos: 922
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
UserMaple5
EgmatQuantExpert Bunuel JeffTargetTestPrep

Hi experts. I tend to get these types of questions right but they take me WAY TOO LONG to do. I normally test cases and it takes a while. Are there any strategies other than testing cases that I can use for these kind of questions to help improve timing?

Thank you in advance!

UserMaple5 yes, you can use number line reasoning to avoid having to test cases. You can see how I do that in the first part of the video from this post:
https://gmatclub.com/forum/is-xy-0-1-x- ... l#p2686547
User avatar
CrackverbalGMAT
User avatar
Major Poster
Joined: 03 Oct 2013
Last visit: 26 Sep 2026
Posts: 4,849
Own Kudos:
9,381
 [15]
Given Kudos: 230
Affiliations: CrackVerbal
Location: India
Expert
Expert reply
Posts: 4,849
Kudos: 9,381
 [15]
11
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
This is a question which is a great example of what the GMAT expects from test takers in terms of combining statements in a DS question on Inequalities.

It is also an excellent question to learn how to prove/disprove the individual statements in a DS question.

Breaking down the question stem, we can rephrase the question as “Are x and y of the same signs?”. The answers to this question could be,

Yes – which means x and y are either both positive or both negative
No – which means one of them could be positive and the other could be negative OR ZERO (many of us ignore ZERO at our own peril).

From statement I alone, x-y > -2. Let us take some values to find out if this information is sufficient to answer the main question.
If x = 10 and y = 5, x-y = 5 which is definitely greater than -2. For these values of x and y, we answer the main question with a Yes.
If x = 10 and y = -5, x-y = 15 which is also greater than -2. For these values of x and y, we answer the main question with a No.

Statement I alone is insufficient to answer the question with a definite YES or NO. Answer options A and D can be eliminated. Possible answer options are B, C or E.

From statement II alone, x-2y < -6. Again, as in the first statement, let us test some values.
If x = 5, y = 10, x – 2y = -15 which is less than -6. These values give a YES to the main question.
If x = -5, y = 10, x – 2y = -25 which is less than -6. These values give a NO to the main question.

Statement II alone is insufficient to answer the question with a definite YES or NO. Answer options B can be eliminated. Possible answer options are C or E.

Now, at this stage, we are required to combine the statements I and II. Here’s where GMAT expects you to combine the statements using an important property of inequalities and that is – Two inequalities can be added if they have the same inequality sign.

The two inequalities are: x – y > -2 and x – 2y < -6.

When we multiply the first inequality with -2, we obtain -2x + 2y < 4. Now, since the inequality sign is the same as the second inequality, we can add these inequalities.
Adding the inequalities, 2y and -2y cancel out each other and we have –x < -2 which can be rewritten as x > 2.

When we multiply the second inequality with -1, we obtain –x + 2y > 6. Since the inequality sign is the same as the first, we can add these inequalities.
Adding them, x and –x cancel out each other and we have y > 4.

This means xy > 0 and we can answer the main question with a Yes. The combination of statements is sufficient, answer option E can be eliminated.

The correct answer option is E.

Remember that inequalities can be added as long as they have the same sign.

Hope that helps!
Aravind B T
avatar
JuliaMaria123
Joined: 13 Jun 2021
Last visit: 22 Jul 2021
Posts: 1
Given Kudos: 2
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think it should be possible to skip all the calculations and graphical solutions and number line drawings and just think about this for a few moments.

So it is clear by just picking a few numbers that neither (1) nor (2) are sufficient by itself.

So now the big question is - are they sufficient together?

We have: x - y > -2 and x - 2y < -6 from statement (1) and (2).

We can rewrite statement (2): x - y - y < -6 and the red-coloured part much be larger than -2, as it is given by statement (1). But statement (2) must be smaller than -6. We can only achieve that if y is positive (notice the negative sign) and must be great than 4 to make statement (2) smaller than -6).

So now we know that y is positive and greater than 4 and we can go back to (1): x - y > -2. If y is greater than 4, we now know that x must be positive so that (1) is great than -2.
User avatar
GMATGuruNY
Joined: 04 Aug 2010
Last visit: 25 Sep 2026
Posts: 1,348
Own Kudos:
3,986
 [2]
Given Kudos: 9
Schools:Dartmouth College
Expert
Expert reply
Posts: 1,348
Kudos: 3,986
 [2]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
MHIKER
Is xy > 0?

(1) x - y > -2
(2) x - 2y < -6

Do x and y have the same sign?

Statement 1, rephrased: x > y-2
Clearly, x and y can have the same sign or different signs.
INSUFFICIENT

Statement 2, rephrased: x < 2y-6
Clearly, x and y can have the same sign or different signs.
INSUFFICIENT.

Inequalities with multiple variables can be ADDED TOGETHER.
Before adding, we must ensure that the inequality symbol faces the same direction in each inequality.

Statements combined:
Adding together x > y-2 and 2y-6 > x, we get:
x+2y-6 > y-2+x
y > 4

Adding together y > 4 and x > y-2, we get:
y+x > 4+y-2
x > 2

Since x>2 and y>4, x and y have the same sign.
Thus, the answer to the question stem is YES.
SUFFICIENT.

User avatar
Bambi2021
Joined: 13 Mar 2021
Last visit: 23 Dec 2021
Posts: 303
Own Kudos:
Given Kudos: 226
Posts: 303
Kudos: 148
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Taken together:

Subtracting inequalities of different signs -->

(x-y)-(x-2y) > (-2)-(-6)

y > 4

From s1 it is now obvious that x must also be positive.

Posted from my mobile device
User avatar
forrever
Joined: 15 Mar 2023
Last visit: 03 Sep 2025
Posts: 65
Own Kudos:
Given Kudos: 18
Location: India
GMAT 1: 690 Q50 V34
GMAT 1: 690 Q50 V34
Posts: 65
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Is xy>0?

Note that question basically asks whether \(x\) and \(y\) have the same sign.

(1) x-y > -2 --> we can have an YES answer, if for example \(x\) and \(y\) are both positive (\(x=10\) and \(y=1\)) as well as a NO answer, if for example \(x\) is positive and \(y\) is negative (\(x=10\) and \(y=-10\)). Not sufficient.

(2) x-2y <-6 --> again it' easy to get an YES answer, if for example \(x\) and \(y\) are both positive (\(x=1\) and \(y=10\)) as well as a NO answer, if for example \(x\) is negative and \(y\) is positive (\(x=-1\) and \(y=10\)). Not sufficient.

You can get that the the two statement individually are not sufficient in another way too: we have (1) \(y<x+2\) and (2) \(y>\frac{x}{2}+3\). We are asked whether \(x\) and \(y\) have the same sign or whether the points (x,y) are in the I or III quadrant ONLY. But all (x,y) points below the line \(y=x+2\) (for 1) and all (x, y) points above the line \(y=\frac{x}{2}+3\) cannot lie only in I or III quadrant: points above or below some line (not parallel to axis) lie at least in 3 quadrants.

(1)+(2) Now, remember that we can subtract inequalities with the signs in opposite direction --> subtract (2) from (1): \(x-y-(x-2y)>-2-(-6)\) --> \(y>4\). As \(y>4\) and (from 1) \(x>y-2\) then \(x>2\) (because we can add inequalities when their signs are in the same direction, so: \(y+x>4+(y-2)\) --> \(x>2\)) --> we have that \(y>4\) and \(x>2\): both \(x\) and \(y\) are positive. Sufficient.

Answer: C.

Hey Bunuel!
I am a bit slow when it comes to thinking of numbers to solve DS Questions like these. I am quite strong in visualising the graphs when it comes to equations. So I started by plotting both the lines after quickly ruling out answer choices (A) and (B). After plotting, I selected the common area i.e the intersection of x - y > -2 and x - 2y < -6 and the common area of these two equations lies completely in the first quadrant, therefore, both x and y will always be positive and we can conclude that (C) is the correct answer. Is there any downside to this approach? I know all the graphs of the basic equations that I have seen on 750, or 700 level questions, what other graphs should I know about if I want to solve problems like these using the graph approach?
avatar
Engineer1
Joined: 01 Jan 2014
Last visit: 29 Jun 2026
Posts: 193
Own Kudos:
Given Kudos: 457
Location: United States
Concentration: Strategy, Finance
Posts: 193
Kudos: 897
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel


Is xy > 0?

\(xy>0\) means that x and y must have the same sign, so point (x, y) must be either in the first or the third quadrant (green regions).

(1) x-y > -2 --> \(y<x+2\) --> the area below blue line (\(y=x+2\)). (x, y) may or may not be in green region. Not sufficient.

(2) x-2y < -6 --> \(y>\frac{x}{2}+3\) --> the area above red line (\(y>\frac{x}{2}+3\)). (x, y) may or may not be in green region. Not sufficient.

(1)+(2) Below blue line and above red line, is yellow region, which is entirely in I quadrant (where \(y>4\) and \(x>2\)) --> \(xy>0\). Sufficient.

Answer: C.

Hope it helps.

Attachment:
xy.png


Bunuel KarishmaB MartyMurray
Generic question:
I did get it right in my practice exam (1:34) and I plugged in numbers as couple of the solutions show in this discussion. But I typically do not feel confident mostly because I don't want to keep spending time to cross check / revise. What should I do? What is a recommended method to save time and also inadvertently cross check solution for inequality question types? I don't think I have "problem" with the concept and if I have more time, I do these questions well. Thank you.
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 25 Sep 2026
Posts: 16,669
Own Kudos:
81,549
 [1]
Given Kudos: 492
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,669
Kudos: 81,549
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Engineer1
Bunuel


Is xy > 0?

\(xy>0\) means that x and y must have the same sign, so point (x, y) must be either in the first or the third quadrant (green regions).

(1) x-y > -2 --> \(y<x+2\) --> the area below blue line (\(y=x+2\)). (x, y) may or may not be in green region. Not sufficient.

(2) x-2y < -6 --> \(y>\frac{x}{2}+3\) --> the area above red line (\(y>\frac{x}{2}+3\)). (x, y) may or may not be in green region. Not sufficient.

(1)+(2) Below blue line and above red line, is yellow region, which is entirely in I quadrant (where \(y>4\) and \(x>2\)) --> \(xy>0\). Sufficient.

Answer: C.

Hope it helps.

Attachment:
xy.png


Bunuel KarishmaB MartyMurray
Generic question:
I did get it right in my practice exam (1:34) and I plugged in numbers as couple of the solutions show in this discussion. But I typically do not feel confident mostly because I don't want to keep spending time to cross check / revise. What should I do? What is a recommended method to save time and also inadvertently cross check solution for inequality question types? I don't think I have "problem" with the concept and if I have more time, I do these questions well. Thank you.

The graphical solution Bunuel has given above is a 1 min solution and that would be my method of choice.
Plugging in numbers is generally not a good strategy for DS questions. At most, it can help you arrive at the pattern in a question.
User avatar
vibhasharma
Joined: 14 Nov 2021
Last visit: 09 May 2025
Posts: 2
Given Kudos: 162
Location: India
GPA: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,

Could you please help with this? Are we missing something here?

Tpral
Hello Bunuel,

I arrive to y>4.

When you replace it in (1) it makes x>2: OK

But

When you replace it in (2) it makes x - 2(4) < -6 ; so x <2 and so can be negative or positive.

Could you advise when replacing in (1) X>2 (answer =C) and when replacing in (2) we have answer (E) as x<2.

Thanks in advance,
User avatar
vibhasharma
Joined: 14 Nov 2021
Last visit: 09 May 2025
Posts: 2
Given Kudos: 162
Location: India
GPA: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,

Could you please help with this? Are we missing something here?

Tpral
Hello Bunuel,

I arrive to y>4.

When you replace it in (1) it makes x>2: OK

But

When you replace it in (2) it makes x - 2(4) < -6 ; so x <2 and so can be negative or positive.

Could you advise when replacing in (1) X>2 (answer =C) and when replacing in (2) we have answer (E) as x<2.

Thanks in advance,
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Sep 2026
Posts: 113,941
Own Kudos:
Given Kudos: 111,838
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,941
Kudos: 843,812
Kudos
Add Kudos
Bookmarks
Bookmark this Post
vibhasharma
Hi Bunuel,

Could you please help with this? Are we missing something here?

Tpral
Hello Bunuel,

I arrive to y>4.

When you replace it in (1) it makes x>2: OK

But

When you replace it in (2) it makes x - 2(4) < -6 ; so x <2 and so can be negative or positive.

Could you advise when replacing in (1) X>2 (answer =C) and when replacing in (2) we have answer (E) as x<2.

Thanks in advance,

That doubt has already been addressed here: https://gmatclub.com/forum/is-xy-0-1-x- ... l#p1989838
   1   2 
Moderator:
Math Expert
113941 posts