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horrorslive
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horrorslive
is there some conceptual understanding of some topic is required for the above question?

I'd say it's more of a logic-based word problem, so it doesn't fall under a specific topic.
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Hi, is there any reduction in topics in Quants of FE?
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IshtarthUmesh
Hi, is there any reduction in topics in Quants of FE?
Yes - Geometry has been removed in the GMAT FE.
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Yes - Geometry has been removed in the GMAT FE.
Thanks for the info.
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can anyone help me understand what is the fundamental difference between these two qs of worst case scenario and why cant i use the same method in both

There are 15 black chips and 5 white chips in a jar. What is the least number of chips we should pick to guarantee that we have 2 chips of the same color?
A. 3
B. 5
C. 6
D. 16
E. 19 A box contains 10 tablets of Medicine A and 15 tablets of Medicine B. What is the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted?
A. 12
B. 15
C. 17
D. 19
E. 21
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can anyone explain me the solution of this math

*When 10 is divided by a positive integer n, the remider is n-4, which of the following could be the value of n?

A. 3
B. 4
C. 7
D. 8
E. None of these
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how did you understand its 7? what shall i do with the similar type of maths
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Try each of those number one by one
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can anyone explain me the solution of this math

*When 10 is divided by a positive integer n, the remider is n-4, which of the following could be the value of n?

A. 3
B. 4
C. 7
D. 8
E. None of these

When 10 is divided by the positive integer n, the remainder is n - 4. Which of the following could be the value of n?

(A) 3
(B) 4
(C) 7
(D) 8
(E) 12

Positive integer \(a\) divided by positive integer \(d\) yields a reminder of \(r\) can always be expressed as \(a=qd+r\), where \(q\) is called a quotient and \(r\) is called a remainder, note here that \(0\leq{r}<d\) (remainder is non-negative integer and always less than divisor).

Original question says that when 10 is divided by the positive integer n, the remainder is n-4, so \(10=nq+(n-4)\) and also \(n-4\geq{0}\) or \(n\geq{4}\) (remainder must be non-negative).

\(10=nq+n-4\) --> \(14=n(q+1)\) --> as \(14=1*14=2*7\) and \(\geq{4}\) then --> \(n\) can be 7 or 14.

Answer: C.

More here: https://gmatclub.com/forum/when-10-is-d ... 68775.html
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There are 15 black chips and 5 white chips in a jar. What is the least number of chips we should pick to guarantee that we have 2 chips of the same color? A. 3 B. 5 C. 6 D. 16 E. 19 A box contains 10 tablets of Medicine A and 15 tablets of Medicine B. What is the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted? A. 12 B. 15 C. 17 D. 19 E. 21
Can anyone please help with this, why is the answer not 17 in both questions or 3 in both questions?
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There are 15 black chips and 5 white chips in a jar. What is the least number of chips we should pick to guarantee that we have 2 chips of the same color?

A. 3 B. 5 C. 6 D. 16 E. 19

A box contains 10 tablets of Medicine A and 15 tablets of Medicine B. What is the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted?

A. 12 B. 15 C. 17 D. 19 E. 21

Can anyone please help with this, why is the answer not 17 in both questions or 3 in both questions?

In the first question, if it were phrased as "What is the least number of chips we should pick to guarantee that we have at least 2 chips of each color?" the answer would be 17. This is because, in the worst-case scenario, we might pick 15 black chips and then 1 white chip, which still doesn't give us 2 chips of each color. However, the next chip we draw would definitely be white, ensuring we have at least 2 chips of each color.

As it stands, the question asks for either two black (BB) or two white (WW) chips. In the worst-case scenario, the first two chips drawn are of different colors. But the third chip will inevitably match one of the first two, guaranteeing that we have at least two chips of the same color. Thus, the answer is 3.

Regarding the second question, it asks for "the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted." In this case, the answer is 17 (15 tablets of one type plus 2 of the other). This aligns with the rephrased version of the first question.

Hope it's clear.

P.S. Check other Worst Case Scenario Questions from our Special Questions Directory to practice.
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Bunuel
In the first question, if it were phrased as "What is the least number of chips we should pick to guarantee that we have at least 2 chips of EACH color?" the answer would be 17. This is because, in the worst-case scenario, we might pick 15 black chips and then 1 white chip, which still doesn’t give us 2 chips of each color. However, the next chip we draw would definitely be white, ensuring we have at least 2 chips of each color. As it stands, the question asks for either two black (BB) or two white (WW) chips. In the worst-case scenario, the first two chips drawn are of different colors. But the third chip will inevitably match one of the first two, guaranteeing that we have at least two chips of the same color. Thus, the answer is 3. Regarding the second question, it asks for "the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted." In this case, the answer is 17 (15 tablets of one type plus 2 of the other). This aligns with the rephrased version of the first question. Hope it’s clear. P.S. Check other Worst Case Scenario Questions from our Special Questions Directory to practice.
Thanks a lot Bunnel. This really helps.
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"If x^2 = x + 1, which of the following is equal to x ^ 3? A) x +2 B) x+3 C) 2x D) 2x +1 E) 4x + 2. " Hey guys I got this question incorrect. Can someone please help explain why the answer is 2x + 1 (D?)
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( X^2 = X+1 ) now multiple both sides by X ... (X^3= X^2+X) ...now replace value of X^2 that from eq1 is ( X^2 = X+1 ) and so you get X^3 = 2X+1
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Bunuel
In the first question, if it were phrased as "What is the least number of chips we should pick to guarantee that we have at least 2 chips of EACH color?" the answer would be 17. This is because, in the worst-case scenario, we might pick 15 black chips and then 1 white chip, which still doesn’t give us 2 chips of each color. However, the next chip we draw would definitely be white, ensuring we have at least 2 chips of each color. As it stands, the question asks for either two black (BB) or two white (WW) chips. In the worst-case scenario, the first two chips drawn are of different colors. But the third chip will inevitably match one of the first two, guaranteeing that we have at least two chips of the same color. Thus, the answer is 3. Regarding the second question, it asks for "the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted." In this case, the answer is 17 (15 tablets of one type plus 2 of the other). This aligns with the rephrased version of the first question. Hope it’s clear. P.S. Check other Worst Case Scenario Questions from our Special Questions Directory to practice.
hello.

Bunuel
In the first question, if it were phrased as "What is the least number of chips we should pick to guarantee that we have at least 2 chips of EACH color?" the answer would be 17. This is because, in the worst-case scenario, we might pick 15 black chips and then 1 white chip, which still doesn’t give us 2 chips of each color. However, the next chip we draw would definitely be white, ensuring we have at least 2 chips of each color. As it stands, the question asks for either two black (BB) or two white (WW) chips. In the worst-case scenario, the first two chips drawn are of different colors. But the third chip will inevitably match one of the first two, guaranteeing that we have at least two chips of the same color. Thus, the answer is 3. Regarding the second question, it asks for "the minimum number of tablets that need to be removed from the box to guarantee that at least two tablets of each type are among the ones extracted." In this case, the answer is 17 (15 tablets of one type plus 2 of the other). This aligns with the rephrased version of the first question. Hope it’s clear. P.S. Check other Worst Case Scenario Questions from our Special Questions Directory to practice.
regarding this one, why do we not consider 12? since it’s asking least number, why do we not consider that you might pick up 10 of type A and then 2 of B?
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Five different balls are to be distributed in 2 different boxes, red and blue. If each box needs to contain at least one ball, what is the total number of ways of distribution?

What is the solution for this type

If the question was that each box can have 0 balls also. Then it would be 2^5
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Five different balls are to be distributed in 2 different boxes, red and blue. If each box needs to contain at least one ball, what is the total number of ways of distribution?
What is the answer? Is it 15?
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