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Here is the link to this question: if-sr-t-what-is-the-value-of-r-223670.html

The reason Statement 1 is sufficient: Simplifying it yields two possible values for r, +25 and -25. But if r was -25, then t = s.r^1/2 would not be a real number. Not possible. Sq root doesn’t exist for a negative number on the GMAT (consider only real numbers). Thus, r cannot be -25. Meaning r is +25. Sufficient.

Hope this helps.
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r^1/2 has a domain of positive integer
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Purnank
and for x> 20, y>10 and z>20 give them already 21,11, 21 respectively then problem will change into x + y + z = 47
Thank You for the solution.
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is anyone else having trouble viewing gmat purchased content?
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pshreyan_17
please help : a-machine-ta ... 76970.html
Here, 8 kg of the product means 8 kg of the final product (after sorting), not pre-sorting output (directly after production). If we work with that, we will get choice B.
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List A consists of four numbers. The smallest possible average (arithmetic mean) of three of these four numbers is 30 and the largest possible average (arithmetic mean) of three of these four numbers is 40. What is the range of possible averages of list A?
I didnt get how to solve this, pls help anyone..
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It should be 33.5< mean < 37.5
Becoz least possible means would be when the first three numbers are same say x+x+x /3 = 30 where x is the smallest number

And maximum mean of three numbers would be when 3 numbers are equal to y which is the largest possible number
So y+y+y / 3= 40

So if u solve for x it’ll be equal to 30 and Y will be equal to 40

So min avg = 30+30+30+40/4 = 32.5
And max avg= 30+40+40+40/4 = 37.5
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Can someone please share a question bank for number system problems?
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Palak890
Can someone please share a question bank for number system problems?
search.php?selected_search_tags%5B%5D=59&t=0&search_tags=exact&submit=Search
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Help. I’m getting n value as infinity
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Its not asking for possible values for n
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Hi, is the answer for this questions option A? If yes I will provide my logic.
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use formulae for number of even divisor . i.e 2*(2^1*p^1) so number of divisor is 2*2 = 4

Total number of a divisor of a number x= a^n*b^m = ( n+1) *( m+1) given a and b are both prime
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prashi1503
Total number of a divisor of a number x= a^n*b^m = ( n+1) *( m+1) given a and b are both prime
According to this formula: (2+1)*(1+1)>> 3*2=6. But the answer is 4
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I don’t think you should use that formula.
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For e.g. for p=3 , you will get a total of 6 divisior : 1, 2, 3, 4, 6, 12. Out of this, if you use factors made 2 and 2 ^2 , you will get the value as 4
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