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PrabhatKC
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How is this person equating 10^k-12 to Integer?
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TheVDR
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RcikDey
the MCQ choices are: a> 3/41; b> 10/41; c> 17/63 d> 15/63
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17/63

Total ways -
Case - 1: Neither of the Sams, Martins or James make it to the party. So 4 seats, 6 options. 6C4 ways

Case 2 : Only 1 group of Sams, Martins or James make it to the party with 2 out of the other 6 uniquely named people. 3C1 * 6C2 ways

Case 3 : 2 of the 3 groups of Sams, Martins or James make it to the party. 3C2 ways

Case (1 + 2 + 3) = 15 + 45 + 3 = 63 ways

Ways in which SAMs made it to the party -

Case - 1 : 0 (all uniquely named people)

Case - 2 : 2 spots for SAMs and 2 spots for uniquely named people = 6C2 ways = 15

Case - 3 : SAMs + MARTINs...OR...SAMs + JAMESs = 2

Total = 17 ways

Probability = 17 / 63
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PrabhatKC
How is this person equating 10^k-12 to Integer?
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Why don’t you try a few examples on your own, then you will identify the reason behind the logic?
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TheVDR
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PrabhatKC
8C1 I thought was like, 8 pawns choosing 1 square to move forward
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8 pawns choosing 1 square + 8 pawns choosing 2 squares? It may work here mathematically but this can give you trouble in real GMAT questions
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TheVDR
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indian1724
My ans is 20kg
And given ans is 111.11kg
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20 kg seems fine. 18 kg Water, 2 kg everything else.....changes to 8 kg water and 2 kg everything else (assuming everything else doesn’t evaporate). 8 kg / 8 + 2kg = 80%.....Math checks out for 20 kg. On the contrary, this isn’t true for 111.11 kg.
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TheVDR
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PrabhatKC
How is this person equating 10^k-12 to Integer?
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Because (25^3) * 10^(k-12) is an integer.....for this to be 100% true, it must be that 10^(k-12) as an integer [given that k is also an integer]
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TheVDR
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indian1724
My ans is 20kg
And given ans is 111.11kg
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111.11 is the answer if we assume that originally water was 90% of the original watermelon and then it became 80% OF THE ORIGINAL WATERMELON. Which means a 10kg decrease in water was equal to 10%...thus signalling there was 100 kg water in the original watermelon and 100/0.9 = 111.11 kg was the original weight. Certainly, 80% is of the "weight reduced watermelon" and not of the original watermelon.
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Aug 2, 2024
Hi has someone applied for international applications for masters (direct admissions) onself .? I need to know the details. Thanks in advance
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Hi has someone applied for international applications for masters (direct admissions) onself .? I need to know the details. Thanks in advance
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Do you mean without an admissions consultant or what do you mean by oneself?
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Hi, in this question, can someone please explain why will we take both cases for RHS - negative and positive both? I had consider RHS as only = x+2 and got the wrong answer. As per solution, both cases; = X+2 and =-x-2 will give the right answer. Can someone please explain why?

My reasoning was the RHS cannot be negatve since LHS is a square
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RHS cannot be negative, but x can. At x = -3, we still get LHS = RHS (both positive)
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Nidhi1715
Hi, in this question, can someone please explain why will we take both cases for RHS - negative and positive both? I had consider RHS as only = x+2 and got the wrong answer. As per solution, both cases; = X+2 and =-x-2 will give the right answer. Can someone please explain why?

My reasoning was the RHS cannot be negatve since LHS is a square
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We need to consider 3 cases-
1. X > -2 {Value within modulus operator is +ve and it will return +ve value, so RHS +ve}
2. X = -2 {LHS = RHS = 0}
3. X < -2 {Value within modulus operator is -ve and it will return +ve value, so RHS -ve}.
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Nidhi1715
Hi, in this question, can someone please explain why will we take both cases for RHS - negative and positive both? I had consider RHS as only = x+2 and got the wrong answer. As per solution, both cases; = X+2 and =-x-2 will give the right answer. Can someone please explain why?

My reasoning was the RHS cannot be negatve since LHS is a square
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x can take negative as well as positive values. To simplify the logic, let x+2 = p.

Now we are given that,
p^2 = |p|

This is where we apply our logic and make cases where this is possible. One immediate solution is p = 0. Also, p = 1....but we also see that p = -1 should also suffice.

p = x + 2 = 0, 1, -1.

Rest is just basic math.
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PriyankaGmatIMD
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is parabala concept worth studying
I don’t want to
I am planning to leave this parabola concept
What do you guys suggest
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AbaidWaleedKhan
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You can skip a topic I guess
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PriyankaGmatIMD
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yea... Coordinate geometry I don’t see in OG also... so I’m planning on skipping this
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