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Absolutely! Non-competitors are welcome to attempt the questions. However, why not join the competition? It’s free, requires just one click, and if your team wins, you’ll also get a share of the prize!

official answer is C (cannot be determined) answer is C ( cannot be determined)

I wish I can but I’m taking gmat in few weeks and still haven’t finished the course

Competition Questions December 16 Questions ( DAY 1 ): PS 12-days-of-christmas-gmat-competition-day-1-from-a-group-consisting-439078.html 12-days-of-christmas-gmat-competition-day-1-if-5x-2y-80-how-439075.html DS 12-days-of-christmas-gmat-competition-day-1-after-closing-the-439080.html 12-days-of-christmas-gmat-competition-day-1-david-deposits-money-439079.html CR 12-days-of-christmas-gmat-competition-day-1-production-of-hybrid-439077.html 12-days-of-christmas-gmat-competition-day-1-to-decrease-the-rate-of-439076.html TPA 12-days-of-christmas-gmat-competition-day-1-a-candy-jar-contains-439083.html 12-days-of-christmas-gmat-competition-day-1-a-sequence-of-integers-439081.html

reason is, because what if y = 0 , since 0 is also an integer, and we know anything to the power 0 is 1, which is odd. So, we cannot determine

Registration remains open even after the competition starts . Remember, this is a team-based event, so you have the opportunity to win and receive prizes simply by being part of a winning starts.

Had option B in mind but somehow typed A (explanation is correct and the remainder should be 1) yup, explanation seems correct.

hey everyone doing the prime factorization we get 12 but i struggle to find the answer 72=2^3*3^2=12 (3+1)+(2+1)=12 I MEANT (3+1)(2+1) =12 what’s the next step?

Check here: how-many-of-the-factors-of-72-are-divisible-by-100708.html

Why u mentioned -1 then 3 and 9 in ur answer if i may ask

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