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Bunuel
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Practice Questions Chat 22 Dec 2024, 00:22
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Notmycoffee
pl explain?
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This question is discussed here: the-first-boy-enters-the-room-and-found-6-hats-he-gets-313411.html
Hope it helps.
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Ddefines
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Bunuel
In the meantime, you can practice questions from other competitions below:


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Hi Bunuel, in this the PS competiotion question link is taking us to the Sentence correction tab, it’s not working properly.
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Bunuel
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Bunuel
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Hi Bunuel, in this the PS competiotion question link is taking us to the Sentence correction tab, it’s not working properly.
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Fixed the links:

In the meantime, you can practice questions from other competitions below:


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Hi, can someone please explain me this?
if-the-fraction-m-n-is-negative-which-of-the-following-cannot-be-true-367835.html


The explanation by BrentGMAT says ’If mn
m
n
is negative, we know that m ≠ 0 and n ≠ 0.
Next, if n ≠ 0, then we know that n2
n
2
is positive.’

How do we figure our that n^2 is positive?
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December 22nd Quant Question of the Day





Answer and Explanation | Subscribe via E-mail, Forum, Instagram, or YouTube
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Edoua
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Jujumamavudoo
Hi, can someone please explain me this?
if-the-fract ... 67835.html


The explanation by BrentGMAT says ’If mn
m
n
is negative, we know that m ≠ 0 and n ≠ 0.
Next, if n ≠ 0, then we know that n2
n
2
is positive.’

How do we figure our that n^2 is positive?
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m/n <0 means either m or n is negative not both

D) mn^3 <0
If m is negative and n positive—>n^3 is positive then mn^3 is negative

If m is positive and n negative—> n-^3 is negative then mn^3 is negative
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Registration for 12 Days of Christmas 🎅 GMAT Competition with Lots of Prizes & Fun ($40,000 Prize Fund . Dec 16 - 27, 2024) remains open even after the competition starts. Remember, this is a team-based event, so you have the opportunity to win and receive prizes simply by being part of a winning starts.

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20 men can work the same as 30 women and 5 women can work the same as 10 children. If 10 men and 10 women can finish a work in 30 days, in how many days will 10 women and 10 children to do the same work?

30

40

50

60

How to solve this
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20M=30W
10M=15W
10C=5W
10M+10W=1/30
25W=1/30


10C=5W
10C+10W=15W


15W=15/(30*25)
15W=1/50

Answer : (D) 50
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Competition Questions

December 23 Questions (DAY 6):

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A small swimming pool is filled by two pipes. The first and the second pipe can fill the pool individually in 30 hours and 20 hours respectively. Both the pipes are opened together, but the second pipe is closed for the last 5 hours. What is the total time taken to fill the swimming pool?

pl share full solution
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Let x be the total time in which pool is filled
So,
(X/30)+((x-5)/20)=1
(As second pipe worked for 5 less hours)
Upon solving,x=15
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A,B,C enter into a partnership by investing 1500 , 2500 , 3000 Rs respectively. A as a manager gets one-tenth profit and remaining profit is decided Among the three the three in the ratio of their investment. If A’s total share is Rs 369. Find the share of C and B respectively.
A) 405, 486
B) 486, 405
C) 385, 325
D) 396, 475

How do I solve this math
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Can someone help me understand this... Even after reading it multiple times , i just donot understand this
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AfifaAhana888
A,B,C enter into a partnership by investing 1500 , 2500 , 3000 Rs respectively. A as a manager gets one-tenth profit and remaining profit is decided Among the three the three in the ratio of their investment. If A’s total share is Rs 369. Find the share of C and B respectively.
A) 405, 486
B) 486, 405
C) 385, 325
D) 396, 475
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Answer is A

369 = 1/10P + 3/14(9/10)P

solving would give P = 9 * 140

anshgupta433
Answer is A
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answer is B share of B is 405
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Practice Questions Chat 24 Dec 2024, 03:31
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PriyankaGmatIMD
Can someone help me understand this... Even after reading it multiple times , i just donot understand this
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It states that given set has 50 different integers. And statement 1 gives 2 details that median = 50 and range = 50.

If median is 50 for a set with even number of integers then middle 2 integers need to be 49 and 51 to minimize the range of the set because selecting any other pair would by default increase the overall range, which means you have 24 integers less than 49 and 24 integers greater than 51.

Now you are given that range is 50, which means highest number - lowest number = 50. so if you pick all 24 consecutive numbers below 49 (25, 26, 27, ...., 48, 49) it will give you 25 integers which is the first half of the set and if you pick all 24 consecutive numbers above 51 (51,52,53, ...., 74,75) it will give you 25 integers which is the second half of the set, you will get an exact range of 50(highest - lowest = 75 - 25 = 50).

This is the optimal selection of 24 integers both below and above the numbers pivoted around median. If we lower our lower limit or increase our upper limit, you can verify that range constraint won’t match. Hence this selection would be the only optimal and unique selection for the given constraints.
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There are 20 tables in bfc. These tables can accommodate a total 300 people. Some tables are for 10 people and some can accommodate 20 people. What is the ratio of 10 people tables and to that of the number of 20 person tables
A)1:1
B)1:2
C)1:4
D)3:1
E) none of these

How to solve this math??
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Tables accommodating 10 people =a
Tables accommodating 20 people = b

a+b= 20
10a + 20b = 300
a + 2b = 30
Now a= 20-b
Therefore, 20-b +2b = 30
b = 10
Therefore a= 10
Ratio 1:1
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1. let number of tables for 10 people x and number of tables for 20 people y
2. Form two equations
x+y=10
10x+20y=30
3. solve it
you will get 10 for x and y both.
thus ratio will be 1:1
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hr1212
It states that given set has 50 different integers. And statement 1 gives 2 details that median = 50 and range = 50.

If median is 50 for a set with even number of integers then middle 2 integers need to be 49 and 51 to minimize the range of the set because selecting any other pair would by default increase the overall range, which means you have 24 integers less than 49 and 24 integers greater than 51.

Now you are given that range is 50, which means highest number - lowest number = 50. so if you pick all 24 consecutive numbers below 49 (25, 26, 27, ...., 48, 49) it will give you 25 integers which is the first half of the set and if you pick all 24 consecutive numbers above 51 (51,52,53, ...., 74,75) it will give you 25 integers which is the second half of the set, you will get an exact range of 50(highest - lowest = 75 - 25 = 50).

This is the optimal selection of 24 integers both below and above the numbers pivoted around median. If we lower our lower limit or increase our upper limit, you can verify that range constraint won’t match. Hence this selection would be the only optimal and unique selection for the given constraints.
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But why are we taking numbers in such a way... I mean numbers could be anything right... last number could be 1000 we need range.. What I didn’t understand is why are we on this logic that these are the only numbers that would work
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