Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
24 Dec 2024, 06:19
Kudos
Bookmarks
PriyankaGmatIMD, in statement 1 it is given that median is 50 and range is 50; now total nos are 50, so median will be the avg of 25th and 26th;
PriyankaGmatIMD, in statement 1 it is given that median is 50 and range is 50; now total nos are 50, so median will be the avg of 25th and 26th; and it also provided that range is 50; so max - min = 50;
now lets take extreme conditions for the 25th and 26th place. 49+51; 0+100;
Here, 49+51: Till now the range is 51-49=2, however, for 0+100: range would be 100-0=100;
in view of the above, 49+51; would have margin for the range;
24 integers than 25th and 26th than 24 integers;
so the min int would be 25 and maximum would be 75;
do remember the statement has provided that all the integers are different, if they would be same then their would be multiple maximum and minimum.
PriyankaGmatIMD, in statement 1 it is given that median is 50 and range is 50; now total nos are 50, so median will be the avg of 25th and 26th; and it also provided that range is 50; so max - min = 50;
now lets take extreme conditions for the 25th and 26th place. 49+51; 0+100;
Here, 49+51: Till now the range is 51-49=2, however, for 0+100: range would be 100-0=100;
in view of the above, 49+51; would have margin for the range;
24 integers than 25th and 26th than 24 integers;
so the min int would be 25 and maximum would be 75;
do remember the statement has provided that all the integers are different, if they would be same then their would be multiple maximum and minimum.
24 Dec 2024, 06:42
Kudos
Bookmarks
PriyankaGmatIMD
Yes numbers could be anything but for median to be 50, the two numbers which you select whose average is 50, should be your middle two numbers in a sorted set of 50 integers. So let’s say if you pick 0 and 100 to be your middle two integers in your sorted set whose average is 50 then you still need to select 24 integers which are smaller than 0 and 24 integers which are greater than 0 to make it to a total of 50 integer set. So let’s suppose this is your set (-24,-23,-22,......,-1,0,100,101,.......,122,123,124), now if you calculate the range of highest - lowest for this set, it would be 124-(-24) = 148 which is greater than 50 which is a constraint in statement 1. For range (highest - lowest numbers in the set) to be 50, you won’t be able to find any other combination of 50 integers except the one mentioned before.
24 Dec 2024, 08:00
Kudos
Bookmarks
December 24th Quant Question of the Day
Answer and Explanation | Subscribe via E-mail, Forum, Instagram, or YouTube
Answer and Explanation | Subscribe via E-mail, Forum, Instagram, or YouTube
