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Bunuel
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Rohit_842
Kedar91
sry 21...E
I think it should be C 11. Y would have fixed two integer values -10 and 10 at x<= -5 and x>=+5 respectively. And in between it is equal to 2x so we have 9 distinct values. So total is 2 + 9 equal to 11

The answer is E. Here is detailed solution: https://gmatclub.com/forum/if-y-x-5-x-5 ... l#p1378885
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My bad, tried to solve it in the head without pen paper, took me long, but it humbles me everytime to see how I miss that x is not obliged to be an integer
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Rohit_842
My bad, tried to solve it in the head without pen paper, took me long, but it humbles me everytime to see how I miss that x is not obliged to be an integer

It is good that you’re spotting this pattern about yourself. Obviously not fantastic that you’re making this mistake but being aware of a mistake is the first step in addressing it so I would suggest for you to create a checklist that you can force yourself on a practice test to always perform.

This is something many had to do for sentence correction to spot the error but if you know that you are making certain mistakes, assume you will make it and build in a counter measure into your strategy.
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Problem Solving Butler: February 2025
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Data Sufficiency Butler: February 2025
February 27DS 1DS 2
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any good way to approach this problem? If anyone can help me please? What is the shortcut ?
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One way that I know is that any 2 of the 4 vertices of parallelogram needs to have either their x coordinate or y coordinate same. So in short you just need to find the missing combination of (x,y) which is (6,4) using which any 2 vertices will either have their x or y coordinates same. Is it A?
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hr1212
One way that I know is that any 2 of the 4 vertices of parallelogram needs to have either their x coordinate or y coordinate same. So in short you just need to find the missing combination of (x,y) which is (6,4) using which any 2 vertices will either have their x or y coordinates same. Is it A?
Missed the multiple selection, so (6,12) could also be another point. One way to check for all options is
to go through each options individually and validate below conditions -
1) 3 of these points don’t lie on a single line, if so eliminate
2) the point selected needs to have atleast same x or y with one given coordinate
3) distance b/w selected vertice and one given vertice is same as the distance b/w rest 2 vertices

Or if you can see the pattern in the given vertices then it’s pretty straightforward, given points (12,4) and (12,8) lie on the same line with distance of 4 b/w them so any point which is on the same line as (6,8) and has a distance of 4 will be the answer which is (6,4) or (6,12)
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hr1212
One way that I know is that any 2 of the 4 vertices of parallelogram needs to have either their x coordinate or y coordinate same. So in short you just need to find the missing combination of (x,y) which is (6,4) using which any 2 vertices will either have their x or y coordinates same. Is it A?
Isn’t coordinate geometry omitted in gmat focus?
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No

Only geometry is omitted
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any good way to approach this problem? If anyone can help me please? What is the shortcut ?
if you want a combinatorics answer, there will be 3 ways to have a 4th point of a parallelogram, given 3 vertices. any 2 of the 3 given vertices will always form a diagonal of a possible parallelogram. there are 3 ways to choose the 1st diagonal (3C2), so there are 3 ways to choose the other diagonal, so 3 possible points. the three points you’re given will form a triangle, you can rotate the triangle 180 degrees around the midpoint of any of the 3 sides and it will form a possible parallelogram

for illustration

if you call your point (x,y), you can find the possible ordered pairs since the diagonals of the parallelogram will bisect each other, so the midpoints of the diagonals will be the same... for example: (6,8) and (12,4) will form a diagonal with midpoint at (9,6) which is the midpoint of (x,y) and (12,8) so x = 6 and y = 4, giving (6,4)... you can do this with all 3 configurations
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34,23,18,27,44,18
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Data Sufficiency Butler: February 2025
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